Answer:
So that vehicles do not topple or skid off the road.
Explanation:
As a vehicle is negotiating a curve, two equal and opposite forces act on the vehicle; centripetal force which keeps it moving and centrifugal force which tends to throw it out of the path.
In order to avoid skidding off the road curved roads are banked. Banking a curved surface provides the centripetal force that points towards the center of the road hence the vehicle or car does not skid off or topple.
Study the image. Point 1 is beneath water moving toward land. Point 2 is next to an erupting vocano. Point 3 is beneath Earth apostrophe s crust moving toward the water. Point 4 is the same layer as Point 1 moving down below Point 3. At which point is subduction occurring? 1 2 3 4
Answer:
I believe the answer is D) 4
Explanation:
Subduction is the sideways and downward movement of the edge of a plate of the earth's crust into the mantle beneath another plate.
Answer: point 4
Explanation:
Early mines used to be ventilated as illustrated below. Explain why this works in terms of convection.
A man does 4,465 J of work in the process of pushing his 2.90 103 kg truck from rest to a speed of v, over a distance of 25.0 m. Neglecting friction between truck and road, determine the following.(a) the speed vm/s
(b) the horizontal force exerted on the truck
N
Answer:
(a)The final speed of the truck "v" is 1.76 m/s
(b) The horizontal force exerted on the truck is 178.64 N
Explanation:
Given;
work done by the man, W = 4,465 J
mass of the truck, m = 2.9 x 10³ kg
initial speed of the truck, u = 0
distance the truck was pushed to, d = 25 m
final speed of the truck, = v
The work done in pushing the truck is calculated as;
W = F x d
where;
F is the horizontal force applied
d is the distance in which the truck was pushed to
W = ma x d
[tex]a = \frac{W}{md} \\\\a = \frac{4465}{2.9 \times 10^3 \ \times 25} \\\\a = 0.0616 \ m/s^2[/tex]
(a)The final speed of the truck "v" is calculated as;
v²= u² + 2ad
v² = 0 + 2(0.0616 x 25)
v² = 3.08
v = √3.08
v = 1.76 m/s
(b) the horizontal force exerted on the truck
F = ma
F = (2.9 x 10³) (0.0616)
F = 178.64 N
The force of friction between an object and the surface upon which it is sliding is 46N and the coefficient of friction between them is 0.30. What is the weight of the object?
Answer:
let the coefficient of friction be ß
Explanation:
[tex]from \: third \: law \: of \: solid \: friction \\ friction = \beta \times R \\ where \: R \: is \: the \: normal \: reaction \\ 46 = 0.30 \times R \\ R = \frac{46}{0.30} \\ R = 153.33 \: N \\ but \: R = mg \\ where \: mg \: is \: the \: weight \\ hence \\ weight, W = 153.33 \: N[/tex]
What will happen to the wavelength of light uf the frequency is doubled?What will happen to the wavelength of light uf the frequency is doubled?
Answer:
if the frequency is double, the wavelength is only half as long
Explanation:
Considering the definition of wavelength, frequency and propagation speed, if the wavelength is doubled, the frequency is reduced by half.
In a periodic wave the wavelength (λ) is the physical distance between two points from which the wave repeats itself. That is, the wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
The frequency (f) is a measure of the number of cycles or repetitions of the wave per unit of time. Its unit is s⁻¹ or hertz (Hz).
The wavelength and its frequency are related from the speed at which the wave travels. The propagation speed (v) is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave's disturbance propagates along its displacement. So, the speed expression is:
v=λ×f
This indicates that the higher the frequency, the shorter the wavelength and the lower the frequency, the longer the wavelength.
All electromagnetic waves propagate in a vacuum at a constant speed of 300,000,000 m/s, the speed of light. Then, since an inversely proportional relationship is established between the frequency and the wavelength, if the wavelength is doubled, the frequency is reduced by half.
In summary, if the wavelength is doubled, the frequency is reduced by half.
Learn more:
brainly.com/question/2232652?referrer=searchResults brainly.com/question/7321084?referrer=searchResults brainly.com/question/14946166?referrer=searchResultsVin Diesel jumps out of a plane. Gravity pulls on him with 184N of force and his parachute pushes him up with 82 N of force.
Net Force = (your answer)
Body Diagram or Explanation = (your answer)
Answer:
Fr = 102[N]
Explanation:
We must perform a free body diagram to understand the forces acting on Vin Diesel. In the attached image we see the forces related to his weight and the air resistance force.
We must analyze the forces in the Y axis, we see that we have the force of the air opposing the fall of Vin Diesel, in this way this force is negative since it opposes the movement, the fall.
∑Fy = 0
[tex]F_{weight}-F_{air}=F_{r}\\F_{r}= 184-82\\F_{r}=102[N][/tex]
What is the motion of the object?
F = 90 N
F3 = 60 N
F = 20 N
F2 = 90 N
Constant speed to the left
Accelerating to the left
Accelerating to the right
Constant speed to the right
Answer:
Thus, the object is accelerating to the left
Explanation:
The Net Force
The net force is the result of adding all the forces as vectors acting on a body.
[tex]\vec F=\vec F_1+\vec F_2+...+\vec F_n[/tex]
Each vector can be expressed in its rectangular components Fx and Fy, and the sum is the sum of the rectangular components separately.
Second Newton's law gives the relation between the net force and the acceleration of the body:
[tex]\vec F = m.\vec a[/tex]
We can see the acceleration is a vector with the same direction as the net force.
The diagram shows two vertical forces and two horizontal forces.
The vertical forces are acting in opposite directions and with the same magnitude, thus they cancel out, leaving zero net force in the y-axis.
The horizontal forces are opposite and with different magnitudes. Since the force acting to the left (F3) has a greater magnitude than the force acting to the right (F4), there is a net force directed to the left with a magnitude of 60 N - 20 N = 40 N
Thus, the object is accelerating to the left
Calculate the force between charges of 55 × 108 C and 1 × 107C if they are 5
cm apart.?
First:
5 cm = 0,05 m
Now, the formula:
F = k * (qq') / r²
Replacing:
F = 9x10⁹ * (55x10⁸ * 1x10⁷) / 0,05²
F = 9x10⁹ * (5,5x10¹⁶ / 2,5x10⁻³)
F = 9x10⁹ * 2,2x10¹⁹
F = 1,98x10²⁹
The force between the charges is 1,98x10²⁹ Newtons.
what is general relativity
Explanation:
General relativity is a theory of space and time. ... The central idea of general relativity is that space and time are two aspects of spacetime. Spacetime is curved when there is matter, energy, and momentum resulting in what we perceive as gravity. The links between these forces are shown in the Einstein field equations.
What is the magnitude of the electric field on a +2 C charge if it experiences an electric force of 6 N?
Answer:
call me 7164013838 hurry bye
A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
what is the velocity of a point on the edge of the wheel?
A. 6.15 m/s
B. 5.39 m/s
C. 5.84 m/s
D. 6.20 m/s
Answer:
The correct answer is B)
Explanation:
When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel. So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.
The formula for calculating the velocity of a point on the edge of the wheel is given as
[tex]V_{r}[/tex] = 2π r / T
Where
π is Pi which mathematically is approximately 3.14159
T is period of time
Vr is Velocity of the point on the edge of the wheel
The answer is left in Meters/Seconds so we will work with our information as is given in the question.
Vr = (2 x 3.14159 x 1.94m)/2.26
Vr = 12.1893692/2.26
Vr = 5.39352619469
Which is approximately 5.39
Cheers!
Activity: Lab safety and Equipment Puzzle
Answer:
number 2 down is: safetygoggles
Explanation:
no space
Lab safety personal protective equipment should always be put on when in the lab, and lab equipment are what scientists for lab work
The words for the lab safety and lab equipment puzzle are:
1. Test tube rack
2. Splash goggles
3. Fire extinguisher
4. Balance scale
5. Closed heel
6. Deluge shower
7. Waft
8. Pipette
9. Proctor
10. Meter stick
11. Bunsen burner
12. Cleanup
13. Beaker tongs
14. Measuring cylinder
15. Funnel
16. Trash bin
17. Hot plate
18. Beaker
19. Lab apron
20. Fire blanket
Learn more about lab equipment here:
https://brainly.com/question/13142279
https://brainly.com/question/13164015
https://brainly.com/question/17391361
What kind of force is the force of gravity?
Answer:
Its a Universal Force
Explanation:
If the net work done on a particle is zero, which of the following statements must be true?
A. The speed is unchanged.
B. The velocity is zero.
C. The velocity is unchanged.
D. More information is needed.
E. The velocity is decreased.
Answer:
A. The speed is unchanged.
Explanation:
In the case when the work is to be done on a particle i.e. zero so the change made in KE of the particle would be zero. This represent the work energy theroem. But when the KE remains same or does not change so it should be the same and the particle speed would also the same
Therefore as per the given statement, the first option is correct
And rest of the options are wrong
Pls someone help me with this :(
A slithering snake travels once around a circle of radius 3.20m. The coefficient of friction between the ground and the snake is 0.25, and the snake's weight is 80.0N. How much work does the snake do against friction?
Answer:
The magnitude of the work done by the snake against friction is 402 J.
Explanation:
The work is given by:
[tex] W = F*d [/tex]
Where:
F: is the force
d: is the distance
The distance traveled by the snake is given by the perimeter of the circle:
[tex] P = 2\pi r = 2\pi 3.20 m = 20.1 m [/tex]
Now, the force in the direction of the movement is:
[tex] |\Sigma F| = F_{\mu} = \mu N = \mu W = 0.25*80.0 N = 20 N [/tex]
Finally, the work is:
[tex] W = F*d = 20 N*20.1 m = 402 J [/tex]
Therefore, the magnitude of the work done by the snake against friction is 402 J.
I hope it helps you!
A series RC circuit contains two resistors and two capacitors. The resistors are 39 ohms and 56 ohms. The capacitors have capacitive reactances of 80 ohms and 40 ohms. When calculating the circuit values, the total resistance used is:_______
a. 215 ohms
b. 95 ohms
c. 25 ohms
d. 120 ohms
Answer:
The correct option is b
Explanation:
From the question we are told that
The resistance of the first resistor is [tex]R_1 = 39 \ \Omega[/tex]
The resistance of the second resistor is [tex]R_2 = 56 \ \Omega[/tex]
The capacitive reactance of the first capacitor is [tex]jX_{c_1 } = 80 \ \Omega[/tex]
The capacitive reactance of the first capacitor is [tex]jX_{c_2 } = 40 \ \Omega[/tex]
Generally given that the resistors are connected in parallel , their equivalent resistance is
[tex]R_e = R_1 +R_2[/tex]
=> [tex]R_e = 39 + 56[/tex]
=> [tex]R_e = 95 \ \Omega[/tex]
Generally given that the capacitors are connected in parallel , their equivalent capacitive reactance is
[tex]jX_e = jX_{c_1} + jX_{c_2}[/tex]
=> [tex]jX_e = 80 + 40[/tex]
=> [tex]jX_e = 120[/tex]
Hence the impedance of the circuit is
[tex]Z = R_e - jX_e[/tex]
=> [tex]Z = 95 - j120[/tex]
Generally from the impedance equation , the total used resistance is
[tex]R_e = 95 \ \Omega[/tex]
why reverberation doesn't occur in well furnished room?
Answer:
It is because the room is occupied with stuffs.
Explanation:
In a well furnished room there are things
like bed, cupboard, wardrobe and other stuffs, So they act as absorbing materials.
They absorb sound and do not give a chance to resounds.
If a bow holds 500J of potential energy as the arrow is pulled back, how much kinetic energy will the arrow have after it has been released?
Answer:
500J
Explanation:
The arrow will have an energy of 500J after it has been released from its state of rest.
This is compliance with the law of conservation of energy which states that "in every system, energy is neither created nor destroyed but transformed from one form to another".
The energy at rest which is the potential energy is 500J This energy will be converted to kinetic energy in total after the arrow has been released. This way, no energy is lost and we can account for the energy transformations occurring.A 20-kg object sitting at rest is struck elastically in a head-on collision with a 10-kg object initially moving at 3.0 m/s. Find the final velocity
Answer:
1 m/s
Explanation:
Using law of conservation of momentum
m1v1 + m2v2 = (m1 + m2)vf , where
m1 = mass of object at rest, 20 kg
v1 = initial velocity of object at rest, 0 m/s
vf = final velocity of the bodies
m2 = mass of object in motion, 10 kg
v2 = initial velocity of object in motion, 3 m/s
On substituting, we have
(20 * 0) + (10 * 3) = (20 + 10) vf
0 + 30 = 30 vf
vf = 30 / 30
vf = 1 m/s
Therefore, the velocity of the bodies after hitting each other is 1 m/s
Two students are standing next to one another. One student has a mass of 79.0 kg, and the other has a mass of 93.5 kg. If they are standing so that their centers of mass are a distance of 1.12 m apart, what is the force of the gravitational attraction between them?
A. 4.40 * 10^-7 N
B. 3.93 * 10^-7 N
C. 1.29 * 10^-6 N
D. 8.77 * 10^-6 N
Answer:
[tex]F=3.93\times 10^{-7}\ N[/tex]
Explanation:
Mass of student 1, m₁ = 79 kg
Mass of student 2, m₂ = 93.5 kg
The students are 1.12 m apart, d = 1.12 m
We need to find the force of the gravitational attraction between them. The force of gravitational force is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{79\times 93.5}{(1.12)^2}\\\\=3.93\times 10^{-7}\ N[/tex]
So, the force of gravitational attraction between them is [tex]3.93\times 10^{-7}\ N[/tex]. Hence, the correct option is (B).
4. Which of the following would NOT be a major process in the formation of sedimentary
rocks?
a Erosion
b. Melting
C Deposition
d. Weathering
Answer:
b. melting
Explanation:
it is made of sediments and that is not necessary
Jaden has a mass of 45 kilograms on Earth. Jupiter has more gravity than the Earth. On Jupiter, Jaden's mass will be O more than 45 kilograms o less than 45 kilograms 45 kilograms
Answer:
m = 45 kg
Explanation:
Given that,
Mass of Jadan, m = 45 kg on Earth
Jupiter has more gravity than the Earth.
Mass of an object is the amount of matter contained inside an object. We need to tell about the mass of Jaden on Jupiter. The mass of the object remains same everywhere.It does not change in any of the location.
Hence, Jaden's mass will be 45 kg on Jupiter.
A hiker walks 200 m west and then walks 100 m north. In what direction is her resulting displacement?a. northb. westc. northwestd. None of the answers is correct.
Answer:
Option (C) is correct.
Explanation:
Assuming that the hiker starts walking from the origin O as shown in the figure.
First, he walks 200 m west to point A (say), then he walks 100 m north to the final point B (say) as shown in the figure.
The final point B is in the north-west direction, therefore, the resulting point is in the north-west direction.
Hence, option (C) is correct.
If velocity, time and force were chosen as basic quantities, find the
dimensions of mass and energy.
Answer:
The Dimension of mass is [F T v⁻¹] and Dimension of energy is [F T v]
Explanation:
(i) We know that,
Force = mass × acceleration
= mass × velocity/time
⇒ mass = force × time ÷ velocity
or. [mass] = [force] [time] ÷ [velocity]
= [F] [T] ÷ [v]
∴ [mass] = [F T v⁻¹]
(ii) Dimensions of energy are same as the dimensions of kinetic energy
∴ Energy = [ ½mv²] = [m] [v]²
= [F T v⁻¹] [v]²
Energy = [F T v]
Thus, The Dimension of mass is [F T v⁻¹] and Dimension of energy is [F T v]
-TheUnknownScientist
Explanation:
fvt-1 = mass
ftv = energy
solve at least one question (30 points)
Answer:
(a) the particle position = 135 m
(b) the velocity of the particle = 44 m/s
(c) the acceleration of the particle = 50 m/s²
Explanation:
Solution to Question 2.
Given;
velocity of a particle, v = 2 - 4t + 2t³
initial position at t = 0, s₀ = 3 m
(a) the particle position at t = 3 s
s = vt
s = (2 - 4t + 2t³)t
s = 2t - 4t² + 2t⁴
s = s₀ + s₃
s = s₀ + 2(3) - 4(3²) + 2(3⁴)
s = s₀ + 6 - 36 + 162
s = s₀ + 132 m
s = 3m + 132 m
s = 135 m
(b) the velocity of the particle at t = 3 s
v = 2 - 4t + 2t³ = 2 - 4(3) + 2(3)³
v = 44 m/s
(c) the acceleration of the particle at t = 3s
v = 2 - 4t + 2t³
[tex]a = \frac{dv}{dt} \\\\a = \frac{d}{dt} (2 -4t + 2t^3)\\\\a = -4 + 6t^2[/tex]
a = -4 + 6(3)²
a = 50 m/s²
At the beach in San Francisco (0 meters) the pressure of the atmosphere is 101.325 kPa
(kilopascals) and in Denver, 1609.344 meters above sea level, the pressure of the atmosphere
is about 83.437 kPa. Using this data, find a linear equation for pressure P in terms of
altitude h. (Hint: write the pressure and altitude in each location as a point (h, P). Then
use point-slope form to find the equation of the line.)
Answer:
[tex]P = -\frac{17978}{1609344}(h)+101.325[/tex]
Explanation:
Given
[tex]h = height[/tex]
[tex]P = Pressure[/tex]
[tex](h_1,P_1) = (0,101.325)[/tex]
[tex](h_2,P_2) = (1609.344 ,83.437 )[/tex]
Required
Determine the linear equation for P in terms of h
First, we calculate the slope/rate (m);
The following formula is used:
[tex]m = \frac{P_2 - P_1}{h_2 - h_1}[/tex]
Substitute values for P's and h's
[tex]m = \frac{83.347 - 101.325}{1609.344- 0}[/tex]
[tex]m = \frac{-17.978}{1609.344}[/tex]
[tex]m = -\frac{17.978}{1609.344}[/tex]
Multiply by 1000/1000
[tex]m = -\frac{17.978 * 1000}{1609.344*1000}[/tex]
[tex]m = -\frac{17978}{1609344}[/tex]
The equation is then calculated using:
[tex]P - P_1 = m(h - h_1)[/tex]
Substitute values for m, h1 and P1
[tex]P - P_1 = m(h - h_1)[/tex]
[tex]P - 101.325 = -\frac{17978}{1609344}(h - 0)[/tex]
[tex]P - 101.325 = -\frac{17978}{1609344}(h)[/tex]
Make P the subject
[tex]P = -\frac{17978}{1609344}(h)+101.325[/tex]
The above is the required linear equation
A 12-inch ruler rests on your right index finger at the 6-inch mark.
Required:
a. What forces are present?
b. Write the first and second equations of equilibrium fully and show that both conditions are satisfied.
Answer:
Explanation:
Let the right index finger be the pivot, the balanced ruler is shown in the diagram attached to this answer.
a. The forces present are:
i. The weight of the ruler, W, which acts upwards at the point of pivot.
ii. The reaction, R, of the right index finger on the ruler which acts upwards.
b. According to the principle of equilibrium, the total forces acting upwards must be equal to the total forces acting downwards.
So that,
R = W ................. 1
ii. The sum of clockwise moment must be equal to the sum of anticlockwise moment.
Since the ruler is balanced at the mid-point (6 inch), then;
R x 0 = w x 0 = 0 ............... 2
This implies that no moment is experienced by the ruler balanced on the right index finger. Therefore, the ruler is said to be in a state of equilibrium.
A 10 kg block is attached to a light cord that is wrapped around the pulley of an electric motor, as shown above. If the motor raises the block from the floor to a height of 8.0 meters in 5 seconds what was the motor’s power output?
Answer:
156.8 Watts
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 10 kg
Height (h) = 8 m
Time (t) = 5 s
Power (P) =?
Next, we shall determine the energy used by the motor to raise the block. This can be obtained as follow:
Mass (m) = 10 kg
Height (h) = 8 m
Acceleration due to gravity (g) = 9.8 m/s²
Energy (E) =?
E = mgh
E = 10 × 9. 8 × 8
E = 784 J
Finally, we shall determine the power output of the motor. This can be obtained as illustrated below:
Time (t) = 5 s
Energy (E) = 784 J
Power (P) =?
P = E/t
P = 784 / 5
P = 156.8 Watts
Therefore, the power output of the motor is 156.8 Watts
give me two reasons that may render a metalochromic indicator efficient
Answer:
A complexometric indicator is an ionochromic dye that undergoes a definite color change in presence of specific metal ions.[1] It forms a weak complex with the ions present in the solution, which has a significantly different color from the form existing outside the complex. Complexometric indicators are also known as pM indicators.[2]