Answer:
D
Explanation:
The standard international (SI) unit for spring constant is N/m, so N/km is the same thing but bigger.
Increasing the number of turns on the generator coil....? 1 point Increases the voltage output. Does not alter the output voltage. Reduces the output voltage.
Answer:
increases the voltage output
Explanation:
By Increasing the number of turns on the generator coil , the output volatge of a generator increases. However, there are various other methods availbble to increase the output voltage of a generator. Some of these can be
1. By increasing the rpm of generator coil.
2. By using stronger magnets
help pls physics problem
Answer:
0.4329 seconds
Explanation:
We are given;
Distance; d = 0.635 m
Velocity; v = 3.22 m/s
Angle; θ = 62.9°
To find the time, we have to find the horizontal component of the velocity.
Thus, Vx = 3.22 × cos 62.9
Formula for time is;
t = d/Vx
t = 0.635/(3.22 × cos 62.9)
t = 0.4329 sec
Thus the time he will take to clear the hurdle is 0.4329 sec
What exercise will strengthen your legs?
Biking
Stretching
Lifting a box
Playing catch
Answer:
biking
Explanation:
To make the Bike move you peddle with your legs.
Strong magnetic fields created by high currents can result in:910 A. Arc flash B. Arc blast C. Large mechanical stresses that may cause conductors to move D. Shock
Answer:
B. Arc blast
Explanation:
Arc blast are as a result of rapid injection of electrical energy into an arc. These shock waves and arc blast pressure wave at low level can lead to damage of eardrums at lower levels and cardiac arrest at high levels.
Strong magnetic fields created by high currents (> 100 kA) can result to equipment destruction. These arc blast hazards are mostly found in high-energy power circuits and large capacitor banks.
traveling at about 30 mph, how many feet will the average driver cover from the time they see the danger until they hit the brakes
Answer: 75 ft
Explanation:
Breaking distance = Speed²/ 20
= 30²/20
= 45 feet
Stopping distance = Speed + braking distance
= 30 + 45
= 75 ft
14. A 3.0 kg metal ball, at rest, is hit by a 1.0 kg metal ball moving at 4.0 m/s. The 3.0 kg ball moves
forward at 2.0 m/s and the 1.0 kg ball bounces back at 2.0 m/s.
(a) What is the total kinetic energy before the collision?
Answer:
The kinetic energy before the collision was 8 J
Explanation:
The given parameters are;
The mass of the metal ball at rest, m₁ = 3.0 kg
The velocity of the ball at rest = 0 m/s
The mass of the metal ball that hits the one at rest, m₂ = 1.0 kg
The velocity of the metal ball that hits the one at rest, v₂ = 4.0 m/s
The velocity with which the 3.0 kg ball moves forward = 2.0 m/s
The velocity with which the 1.0 kg ball bounces back = 2.0 m/s
a) Kinetic energy, K.E. = 1/2 × m × v²
Where;
m = The mass of the of the object in motion
v = The velocity of the object
Before the collision, we have;
Initial K.E. = 1/2 × m₁ × v₁² + 1/2 × m₂ × v₂²
∴ Initial K.E. = 1/2 × 3.0 kg × (0 m/s)² + 1/2 × 1.0 kg × (4.0 m/s) ² = 8 J
The kinetic energy before the collision = The initial K.E. = 8 J.
PLEASE ANSWER WILL MARK BRAINLIEST
Im doing it for free just say something to make meh smile and u get brainliest :3
Answer:
your pretty no matter what others say
Explanation:
Answer:
two bros chillin in a hot tub five feet apart cuz there not gay
Explanation:
do you remember this vine
A bullet has a speed of 500 m/s as it leaves a rifle. If it is fired horizontally from a cliff 12m above a lake, how far does the bullet travel before striking the water?
The level of mercury falls in a barometer
while taking it to a mountain.
Answer:
This is due to a relative decrease in atmospheric pressure in high places.
Explanation:
Given that atmospheric pressure decreases at the higher point or ground, this reduced atmospheric pressure, however, will be unable to contain the Mercury in the barometer tube.
Therefore, at the top of the mountain where the air pressure is low, the barometer reading ultimately goes down.
Hence, the level of mercury falls in a barometer while taking it to a mountain "due to a relative decrease in atmospheric pressure in high places."
A projectile is shot a cliff of 20m high, at an angle of 60o with respect to the horizontal, and it lands on the ground 8 seconds later. Find: a) the initial speed ? b) the speed of the projectile after 4 s c) the horizontal range d)the maximum height it reached e) what was the speed of the projectile when it landed on the ground?
Answer:
a) The initial speed of the projectile is approximately 42.410 meters per second.
b) The speed of the projectile after 4 seconds is approximately 21.352 meters per second.
c) The horizontal range of the projectile is 169.64 meters.
d) The maximum height of the projectile is 68.775 meters.
e) The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.
Explanation:
According to the statement, the projects shows a parabolic motion, which consists in the combination of horizontal uniform motion and vertical uniformly accelerated motion due to gravity. This motion is represented by the following equations of motion:
[tex]x = x_{o} + v_{o}\cdot t\cdot \cos \theta[/tex] (1)
[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \theta + \frac{1}{2}\cdot g\cdot t^{2}[/tex] (2)
Where:
[tex]x_{o}[/tex], [tex]x[/tex] - Initial and current horizontal position, measured in meters.
[tex]y_{o}[/tex], [tex]y[/tex] - Initial and current vertical position, measured in meters.
[tex]\theta[/tex] - Launch angle, measured in sexagesimal angle.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]t[/tex] - Time, measured in second.
a) By using (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]y = 0\,m[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], then initial speed of the projectile is:
[tex]v_{o}\cdot t \cdot \sin \theta = y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2}[/tex]
[tex]v_{o} = \frac{y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2} }{t\cdot \sin \theta}[/tex]
[tex]v_{o} = \frac{0\,m-20\,m-\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)^{2} }{(8\,s)\cdot \sin 60^{\circ}}[/tex]
[tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex]
The initial speed of the projectile is approximately 42.410 meters per second.
b) The vertical component of the velocity of the projectile is determine by differentiating (2) in time and substitute all known values:
[tex]v_{y} = v_{o}\cdot \sin \theta +g\cdot t[/tex] (3)
([tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 4\,s[/tex])
[tex]v_{y} = -2.5\,\frac{m}{s}[/tex]
The horizontal component of the velocity of the projectile is:
[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]
[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]
And the speed of the projectile is determined by Pythagorean Theorem:
[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]
[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-2.5\,\frac{m}{s} \right)^{2}}[/tex]
[tex]v \approx 21.352\,\frac{m}{s}[/tex]
The speed of the projectile after 4 seconds is approximately 21.352 meters per second.
c) By (1) we find the horizontal range of the projectile:
([tex]x_{o} = 0\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 8\,s[/tex])
[tex]x = 0\,m + \left(42.410\,\frac{m}{s} \right)\cdot (8\,s)\cdot \cos 60^{\circ}[/tex]
[tex]x = 169.64\,m[/tex]
The horizontal range of the projectile is 169.64 meters.
d) The projectile reaches its maximum height when velocity is zero. By (3) and knowing that [tex]v_{y} = 0\,\frac{m}{s}[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the time associated with maximum height is:
[tex]0\,\frac{m}{s} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ}+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot t[/tex]
[tex]t = 3.745\,s[/tex]
And by (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 3.745\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the maximum height reached by the projectile is:
[tex]y = 20\,m + \left(42.410\,\frac{m}{s} \right)\cdot (3.745\,s)\cdot \sin 60^{\circ}+\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (3.745\,s)^{2}[/tex]
[tex]y = 68.775\,m[/tex]
The maximum height of the projectile is 68.775 meters.
e) If we know that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the components of the speed are, respectively:
[tex]v_{y} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ} + \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)[/tex]
[tex]v_{y} = -41.728\,\frac{m}{s}[/tex]
[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]
[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]
And the speed of the projectile is determined by Pythagorean Theorem:
[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]
[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-41.728\,\frac{m}{s} \right)^{2}}[/tex]
[tex]v \approx 46.807\,\frac{m}{s}[/tex]
The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.
While helping a friend move, you lift a 176 N box full of books and perform 180 J of work to do so. What distance, directly upward, do you lift the box? Show all your work.
Answer:
d = 1.022 [m]
Explanation:
Work in physics is defined as the product of force by distance. In this way we have the following expression.
[tex]W=F*d[/tex]
where:
W = work done = 180 [J] (units of Joules)
F = force = 176 [N]
d = distance [m]
[tex]d = W/F\\d = 180/176\\d = 1.022 [m][/tex]
A person rides in an elivator. What is the equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton’s third law?
Answer:
weight of the person and reaction force according to that weight by the elevator
every action has an equal and opposite reaction
Weight of the person and reaction force according to that weight by the elevator is balanced.
What is Newton's third law?According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.
A person rides in an elivator then the equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton’s third law and are balanced.
Weight of the person and reaction force according to that weight by the elevator is balanced.
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Which topic are you most likely to find in a physics textbook?
A.
photosynthesis
B.
electricity and magnetism
C.
metals and nonmetals
D.
division of a living cell
E.
ionic, covalent, and metallic bonding
Answer: C. electricity and magnetism
Explanation:
Answer:
B.
electricity and magnetism
is the ans
I find this in physics
Why do clownfish rarely go far from their home
Answer:
In the wild, clownfish rarely leave their anemone home. In fact, part of its purpose is to defend the anemone from other fish. However, clownfish bred in aquariums (without an anemone home) may still have this instinct, but it’s much calmer than wild harvested species.
Explanation:
newtons law of gravitation is called a universal law why
Answer:
it is applicable on all bodies having mass and the bodies Will be governed by the same law
An electric heater is rated at 1500 W. If the heater is rated as 80% efficient, calculate the output
rate of energy
Answer:
Power = 1200 [W].
Explanation:
The efficiency of an electrical equipment is defined as the relationship between the power realized, over the power that is consumed. For this case, they give us the data of consumed power and efficiency in this way we can calculate the power that the equipment performs.
[tex]Efficency=\frac{Power_{done}}{P_{consumed}}\\0.8 = \frac{Power_{done}}{1500} \\Power_{done}=1500*0.8\\Power_{done} = 1200 [W][/tex]
This means that of the 1500 [W], 1200 [W] are actually used to get the job done. This is established by means of the first law of thermodynamics.
Linear momentum is conserved is a system when the net force is equal to
Answer:
zero
Explanation:
The linear momentum is conserved when the system is closed. Therefore, the net force is zero.
A -0.6 C charge that moves downward is in a uniform electric field with a strength of 200 N/C what is the magnitude and direction of the force on the charge
Answer:
The magnitude and direction of the force on the charge is 120 N in the direction of the charge.
Explanation:
Given;
magnitude of the charge, q = 0.6 C
electric field strength, E = 200 N/C
The magnitude of the electric force is calculated as;
F = Eq
where;
F is the magnitude of the force
Substitute the given values and solve for F;
F = (200)(0.6)
F = 120 N in the direction of the charge.
Therefore, the magnitude and direction of the force on the charge is 120 N in the direction of the charge.
What are organs made of?
O Organs are made of colections of tissues,
O Organs are made of cells, but not tissues.
O Organs are made of collections of other
O Organs are made of muscle and bone.
DONE
Answer:
Organs are made of collections of tissues, which are groups of cells.
Explanation:
Rank this objects in order of their acceleration small to larger
Answer:
The answer is "DACB".
Explanation:
The missing data of the question is defined in the attached file please find it.
Using formula:
[tex]\to F= m \cdot a\\\\ \to m= 5 \ kg[/tex]
In object A:
[tex]F= 15 \\\\a =\frac{F}{m} = \frac{15}{5} = 3[/tex]
In object B:
[tex]F= 30 \\\\a =\frac{F}{m} = \frac{30}{5} = 6[/tex]
In object C:
[tex]F= 20 \\\\a =\frac{F}{m} = \frac{20}{5} = 4[/tex]
In object D:
[tex]F= 0 \\\\a =\frac{F}{m} = \frac{0}{5} = 30[/tex]
That's why the answer is "DACB" .
help me please ASAP
Answer:
F = 1200 [N]
Explanation:
Torque is defined as the product of force by Radius.
[tex]T=F*r[/tex]
where:
T = torque = 300 [N*m]
r = radius = 50/2 = 25 [cm] = 0.25 [m]
[tex]F=T/r\\F = 300/0.25\\F = 1200 [N][/tex]
Derive 3:
v2=u2 + 2as
I HAVE ATTACHED A FILE..
Please find the attached photograph for your answer
Sudhir walks 0.40 km in a direction 60.0° west of north, then goes 0.50 km due west. What is his displacement?
Answer:
The displacement of Sudhir is 0.781 km.
Explanation:
Given;
initial distance, d₁ = 0.4 km = 400 m, N60.0°W
final distance, d₂ = 0.5 km
Make a sketch of Sudhir motion to form a right angled triangle;
(Check image uploaded).
Apply cosine rule to determine d "displacement"
d² = 500² + 400² - (2 x 500 x 400 x cos 120)
d² = 410,000 - (400,000 x -0.5)
d² = 410,000 - (-200,000)
d² = 410,000 + 200,000
d² = 610,000
d = √610000
d = 781.03 m
d = 0.781 km
Therefore, the displacement of Sudhir is 0.781 km.
A race car was is moving at a constant speed of 35 m/s. A security car was
moving at a speed of 5 m/s as the race car passes by it and was accelerating at
constant rate of 5 m/s2. what was the speed of the security car when it took
over the race car?
65 m/s
60 m/s
35 m/s
5 m/s
Answer:
Final speed of security car v = 65 m/s
Explanation:
Given:
Speed of race car u1 = 35m/s
Speed of security car u2 = 5 m/s
Acceleration = 5 m/s²
Find:
Final speed of security car v
Computation:
Assume, they chase S meter
So
S = u1t + [1/2]at²
S = 35t
S = u2t + [1/2]at²
so,
35t = 5t + [1/2](5)t²
t = 12 s
So
v = u + at
v = 5 + 5(12)
Final speed of security car v = 65 m/s
Which of the following statements would be best described as an expression of an attitude that is low in accessibility and high in ambivalence?
A.
Frank: “I eat a banana for breakfast everyday. I’ve loved them since I was little.”
B.
Judy: “I really dislike bananas. I don’t know why. I just always have.”
C.
Ralph: “I’m not sure about bananas. I’d have to think about it.”
D.
Fiona: “I am a huge banana fan. I don’t know why. I just like them.”
Answer:
The answer is C. Ralph: “I’m not sure about bananas. I’d have to think about it.”
Explanation:
I did the practice.
Answer:
C.) Ralph: "I'm not sure about bananas. I'd have to think about it."
Explanation:
Just took the practice
A runner went from 6 m/s and two seconds what was his acceleration
Answer:
is it 3?
Explanation:
Im taking a guess and just dividing 6 and 2
1.What is the influence of Greek Philosophy on the understanding of human-environment? What is the implication of this on the relationship of human beings and the human environment?
Explanation:
The theory which is linked to person and climate is more concerned with Mother Nature and human's position within it. It is a misconception that humans are the most important species on this planet and they are relying on other species for their life. Conservation ethics also revolve around making human societies and habitats healthier, preserving vital resources for the present and future. This philosophical approach values the human/nonhuman interaction of nature, understanding how humans and the world have a continuing causal association with one another.
A 40 kg boy is moving upwards in a lift with an acceleration of 2 m /s ^2 what would be the weight felt by him if measuured in a scale
Answer:
40×（9.8+2）＝432n
Explanation:
9.8m/s^2 is acceleration of gravity
What are the units of Mass and Weight in the English System? Explain.
Answer:
I tried...
Explanation:
Assuming the English system of mass and weight is the same as the Imperial system, the measurements are:
• 1 pound (lb) = 16 ounces (oz)
• 2,000 pounds (lbs) = 1 ton (T)
I think that's everything?
In the English system, mass is measured in pounds and weight is also measured in pounds. However, it is important to understand the difference between mass and weight.
Mass is a measure of the amount of matter in an object and is a scalar quantity. It does not change with location or gravitational force. In the English system, mass is typically measured using a scale or balance, which compares the object's mass to a standard mass. The pound (lb.) is the unit of mass in the English system.
Weight, on the other hand, is a measure of the force exerted on an object due to gravity and is a vector quantity. It depends on the object's mass and the gravitational force acting on it. In the English system, weight is typically measured using a spring scale or a balance that incorporates a spring. The pound (lb.) is also used as the unit of weight in the English system.
Weight = Mass x Acceleration due to gravity
Mass is measured in pounds (lb.) and weight is also measured in pounds (lb.).It is important to note that weight can vary depending on the gravitational force acting on an object.
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PLEASE HELP! I know the answer to this, but I need an explanation.
Let r be the distance between the man and point Q. He applies a torque of
(r i ) × ((-800 N) j ) = ((-800 N) r ) k
pointing "into the page" with magnitude (800 N) r.
Meanwhile, the rope applies a torque of
((3.0 m) i ) × ((500 N) j ) = (1500 N•m) k
pointing out of the "page" with mag. 1500 N•m
The beam is held in place in a horizontal position, so the torques cancel and
(800 N) r = 1500 N•m
r = (1500 N•m)/(800 N) = 1.875 m ≈ 1.9 m