What equation do I use?

What Equation Do I Use?

Answers

Answer 1

Answer:

I think it's the 3rd one

If someone tells u somethin else, go for it cause im not 100% sure...


Related Questions

What happens to cause the tissue around a cut to become swollen, red, and
painful?
A. Fluid and white blood cells move into the tissue from nearby blood
vessels.
B. White blood cells burst and release wastes made by digesting
pathogens.
C. Lymph nodes develop in the tissue and begin trapping pathogens.
D. Chemical messengers released by the tissue cause nearby
muscles to contract and pull on bones.
SUBM

Answers

Answer:

The answer is A. Fluid and white blood cells move into the tissue from nearby blood  vessels.

Explanation:

Answer:

A is the Answer

Explanation:

I took the test

A student thinks that any real vibration must be damped. Is the student correct? If so, give convincing reasoning. If not, give an example of a real vibration that keeps constant amplitude forever if the system is isolated.

Answers

Answer:

Yes the student is correct

Explanation:

The first law of thermodynamics states that energy can neither be created nor destroyed

The second law of thermodynamics states that the entropy (disorderliness) of an isolated system always increases

Therefore, whereby energy is not supplied to maintain the orderly oscillatory motion with constant amplitude, the amplitude of the system is bound to reduce with time that is the vibration of the system must be damped

I need help in question 9 plzzz

Answers

True is the correct answer

Was the cannonball able to hit its target of 50 meters when the initial velocity was 20 m/s? Why?/Why Not?

(was not able to hit the target, but I don't know the reason)

Answers

Answer:

The cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Explanation:

From the question given above, the following data were obtained:

Height to which the target is located = 50 m

Initial velocity (u) = 20 m/s

To know whether or not the cannon ball is able to hit the target, we shall determine the maximum height to which the cannon ball attained. This can be obtained as follow:

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 20² – (2 × 10 × h)

0 = 400 – 20h

Collect like terms

0 – 400 = – 20h

– 400 = – 20h

Divide both side by – 20

h = – 400 / – 20

h = 20 m

Thus, the the maximum height to which the cannon ball attained is 20 m.

From the calculations made above, we can conclude that the cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Plzz Help easy quesion for 20 points Why does someone get burned if they touch an old filament bulb that has been on for a few hours? Plzz Help

Answers

incandescent lights get hot very quickly and therefore can easily burn u or catch fire

Answer:

In reality, the filament gets so hot it in a real sense bubbles off molecules and electrons. Now and again this material gathers as a dull spot at the highest point of the bulb. Eventually, the filament falls apart, gets frail, and breaks, subsequently finishing the life of the light. Lights radiate light by siphoning an electric flow through a dainty tungsten fiber. The filament warms and emits light. Over the long haul, the filament oxidizes and turns out to be increasingly fragile, until it splits up and the bulb goes out. ... Tungsten picks up obstruction as it warms.

Hope this helped :)

Standing waves are created in the four strings shown in Figure 25. All strings have the same mass per unit length and are under the same tension The lengths of the strings are given. Rank the frequencies of the oscillations, from largest to smallest

Answers

Answer:

The rank of the frequencies from largest to smallest is

The largest frequency of oscillation is given by the string in option D

The second largest frequency of oscillation is given by the string in option B

The third largest frequency of oscillation is given by the string in option A

The smallest frequency of oscillation is given by the string in option C

Explanation:

The given parameters are;

The mass per unit length of all string, m/L = Constant

The tension of all the string, T = Constant

The frequency of oscillation, f, of a string is given as follows;

[tex]f = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L}[/tex]

Where;

T = The tension in the string

m = The mass of the string

L = The length of the string

n = The number of overtones

[tex]Therefore, \ {\sqrt{\dfrac{T}{m/L} } } = Constant \ for \ all \ strings = K[/tex]

For the string in option A, the length, L = 27 cm, n = 3 we have;

[tex]f_A = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 27} = \dfrac{2 \times K}{27} \approx 0.07407 \cdot K[/tex]

For the string in option B, the length, L = 30 cm, n = 4 we have;

[tex]f_B = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 30} = \dfrac{ K}{12} \approx 0.08 \overline 3\cdot K[/tex]

For the string in option C, the length, L = 30 cm, n = 3 we have;

[tex]f_C = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 30} = \dfrac{K}{15} \approx 0.0 \overline 6 \cdot K[/tex]

For the string in option D, the length, L = 24 cm, n = 4 we have;

[tex]f_D = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 24} = \dfrac{5 \times K}{48} \approx 0.1041 \overline 6 \cdot K[/tex]

Therefore, we have the rank of the frequency of oscillations of th strings from largest to smallest given as follows;

1 ) [tex]f_D[/tex] 2) [tex]f_B[/tex] 3) [tex]f_A[/tex] 4) [tex]f_C[/tex]

                                         

The order of the frequencies is  [tex]f_D>f_B>f_A>f_C[/tex]

Standing waves:

The frequency of the standing wave in a string tied at both ends is given by:

[tex]f=\frac{nv}{2L}[/tex]

where n is the mode of frequency

v is the velocity of the wave

and L is the length of the string.

Now the velocity of a wave in a string tied at both ends is given by

[tex]v=\sqrt{\frac{T}{\mu}}[/tex]

where T is the tension and μ is the mass per unit length.

Since T and μ are the same for all the strings, velocity [tex]v[/tex] will be the same for all.

Now to find the mode of frequency we can calculate the number of nodes (including the nodes at the ends) in the given figure and subtract by 1. Nodes are the point where the amplitude of the wave is zero.

[tex]f_A=\frac{3v}{2\times27}=\frac{v}{18}\;s^{-1}\\\\f_B=\frac{4v}{2\times30}=\frac{v}{15}\;s^{-1}\\\\f_C=\frac{3v}{2\times30}=\frac{v}{20}\;s^{-1}\\\\f_D=\frac{4v}{2\times24}= \frac{v}{12}\;s^{-1}[/tex]

Hence, [tex]f_D>f_B>f_A>f_C[/tex]

Learn more about standing waves:

https://brainly.com/question/1698005?referrer=searchResults

A professional baseball player can throw the ball around 45 m/s if the distance between the pitcher and the batter is 18.39 m. How much time does it take for the ball to get to the batter?

Answers

Answer:

The time taken for the ball to get to the batter is 0.41 s.

Explanation:

Given;

initial velocity of the baseball, u = 45 m/s

horizontal distance between the pitcher and the batter, X = 18.39 m

The horizontal distance or range of a projectile is given as;

X = ut

where;

t is the time of flight

u is the initial velocity

t = X / u

t = 18.39 / 45

t = 0.41 s

Therefore, the time taken for the ball to get to the batter is 0.41 s.

How many days does the earth take to rotate around the sun

Answers

Answer:

1 day

Explanation:

The spinning movement of Earth around its axis is known as Earth's rotation.

The Earth rotates around the Sun in 1 day that is 24 hours but once in every 23 hours, 56 minutes, and 4 seconds with respect to other stars.

According to the Indian astronomer Aryabhata, Earth rotates about its axis daily.

Which of these materials is not magnetic?'
*
Cobalt
Iron
Copper
Stainless Steel

Answers

Answer:

stainless steel is the material which is non magnetic.

calculate the resistance of a wire 150cm long and diameter 2.0mm constructed from an alloy of resistivity 44*10-⁸Ωm​

Answers

Answer:

R = 0.21 Ω

Explanation:

the formula:

R = r x l/A

R = (44 x 10-⁸ Ωm) x 1.5 / (π x (1 x 10-³ m)²)

R = 6.6 x 10-⁷ / 3.14 x 10-⁶

R = 0.21 Ω

PLEASE PLEASE HELP ASAP

A cyclist speeds up from 3 m/s to 7 m/s in 8 seconds.

What is its change in velocity?

What's its acceleration?

Answers

Answer:

Change in velocity = 4 m/s and acceleration = 0.5 m/s²

Explanation:

Given that,

Initial velocity, u = 3 m/s

Final velocity, v = 7 m/s

Time, t = 8 seconds

(a) The change in velocity of a cyclist.

[tex]\Delta v=v-u\\\\=7\ m/s-3\ m/s\\\\=4\ m/s[/tex]

(b) Acceleration,

[tex]a=\dfrac{\Delta v}{t}\\\\a=\dfrac{4\ m/s}{8\ s}\\\\a=0.5\ m/s^2[/tex]

So, the change in velocity is 4 m/s and acceleration is 0.5 m/s².

12. A rolling ball has 18 J of kinetic energy and is rolling 3.0 m/s. Find its mass.

Answers

Answer:

4g

I hope it will be useful.

Explanation:

KE = (1/2)*m*v^2

Se lanza un cuerpo verticalmente hacia arriba con una velocidad de 60m/s. Calcular a) Que altura se hallara el cuerpo al cabo de 2s, b)a qué altura máxima llega? C) cuánto tiempo se demora en llegar a la altura máxima y en qué tiempo regresa nuevamente al sitio donde fue lanzado.

Answers

Answer:

(a) 100.38 m

(b) 183.49 m

(c) 6.12 seconds and 12.24 seconds.

Explanation:

Given that a body is thrown vertically upwards with a velocity of 60 m/s.

Assuming that upward direction is positive

So, the initial velocity, u=60 m/s

As the acceleration due to gravity, g=9.81 m/s^2, acts in the downward direction, so

a=-9.81 m/s^2

(a) By using the equation of motion, the displacement of the body after time t=2 seconds, is

[tex]s=ut+\frac 1 2 at^2 \\\\ s=60\times 2 +\frac 1 2 (-9.81)2^2 \\\\[/tex]

s=100.38 m

Hence, the height of the body will be 100.38 m after 2 seconds.

(b) At the maximum height, the velocity of the object is zero, so

v=0.

The maximum height is the displacement of the body where it attains zero velocity.

Using the equation of the motion.

[tex]v^2=u^2+2as \\\\0= 60^2 +2(-9.81)s \\\\s=\frac {3600}{2\times 9.81} \\\\[/tex]

s=183.49 m

Hence, the maximum height of the body is 183.49 m.

(c) Time to reach the maximum height

v=u+at

0=60 +(-9.81)t

t=60/9.81

t=6.12 seconds.

The body will take 6.12 seconds to reach the maximum height.

As the time to reach the maximum height from the initial position is the same as the time to reach the initial position from the maximum height.

So, the total time to returns again to the place where it was launched

= 2 x 6.12 = 12.24 seconds.

pls I will give brainliest for correct answer



find the distance travelled im the first 8 hours



Answers

Answer

I think it is 112 havent done this in a while but im pretty sure thats it Good luck

Explanation:

The Fitness Log is:
A.
Fitness information presented in lesson format.
B.
A carefully considered essay response on a specified topic.
C.
A checklist of items to complete each section.
D.
A record of all the physical activity you complete in one week.

Answers

Answer:

D.  A record of all the physical activity you complete in one week.

Explanation:

A "Fitness Log" allows you to keep track of your workout or exercise. Therefore, it is a record of the different workout you've managed to complete within a time frame. It gives you several information such as the type of workout you've completed, its duration and the time of the day it was performed. This makes a person motivated to exercise because he can see his progress. He may also include his mood before and after workout in order to become more mindful in exercising and many other things.

Answer:

the answer is D  i just got the answer right

Explanation:

A ball is thrown directly upward with an initial speed of 72 m/s. How much time passes before the ball reaches the highest point it will ever reach

Answers

Answer:

7.35 seconds

Explanation:

The computation of the time passed prior to the ball reached to the highest point is as follows;

As we know that the acceleration because of gravity on earth is 9.8 m/s

As the ball is thrown directly in an upward direction with a speed of 72 m/s

So, the time passed prior to the ball reached to the highest point is

= 72 ÷ 9.8

= 7.35 seconds

Hence, the above represents the answer

Can you please help me with this physics question

Answers

Answer:

See the answers below

Explanation:

We can solve both problems using vector sum.

a)

Let's assume the forces that help the diver dive as positive downward, and the forces that oppose upward, as negative

[tex]F_{resultant}=100+30-85+900\\F_{resultant}=845[N][/tex]

The drag force is horizontal d this way in the horizontal direction we will only have the drag force that produces the water stream.

[tex]F_{drag}=50[N][/tex]

b)

Let's assume the forces that propel the rocket upwards as positive and forces like the weight of the rocket and other elements as negative forces.

[tex]F_{resultant}=960+7080-7700\\F_{resultant}=340 [kN][/tex]

How much tension must a rope withstand if it is used to accelerate a 6526 kg car vertically upwards at 8.9 m/s^2?

Answers

Answer:

The value is [tex]T = 122036.2 \ N[/tex]

Explanation:

From the question we are told that

     The mass of the car is  [tex]m = 6526 \ kg[/tex]

      The acceleration  is  [tex]a= 8.9 \ m/s^2[/tex]

Generally the net force applied on the rope is mathematically represented as

          [tex]F_{net} = T - W[/tex]

Here W is the weight of the car which is evaluated as

         [tex]W = m * g[/tex]

=>      [tex]W = 6526 * 9.8[/tex]

=>       [tex]W = 63954.8 \ N[/tex]

Generally the net force can also be mathematically represented as

       [tex]F = m * a[/tex]

So

        [tex]m * a = T - 63954.8[/tex]

=>     [tex]6526 * 8.9 = T - 63954.8[/tex]

=>      [tex]T = 122036.2 \ N[/tex]

a roller coaster accelerates from initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds . what is the acceleration ?

Answers

a roller coaster accelerates from an initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. whats the acceleration

What are immiscible liquids?

Answers

Immiscible liquids are those which won't mix to give a single phase. Oil and water are examples of immiscible liquids - one floats on top of the other. It explains the background to steam distillation and looks at a simple way of carrying this out.

An incidence that is caused by sleep and also occurs during sleep is known as a __________.

Answers

Answer:

parasomnia

Explanation:

Pretty sure it’s parasmonia (if I’m spelling that right

3. A boat at sea is being moved by the ocean current at 5 metres/minute directly to the east. At the same time it is being moved directly to
the north at 3 metres/minute by a strong wind. Determine the magnitude and direction of the boat's overall velocity.

Answers

Explanation:

A boat at sea is being moved by the ocean current at 5 metres/minute directly to the east.

At the same time, it is being moved directly to  the north at 3 metres/minute by a strong wind.

We need to find the magnitude and direction of the boat's overall velocity.

As both velocities are moving perpendicular to each other. The resultant velocity is given by :

[tex]v=\sqrt{5^2+3^2} \\\\=\sqrt{25}\\\\=5\ \text{metres/minute}[/tex]

For direction,

[tex]\tan\theta=\dfrac{v_y}{v_x}\\\\=\dfrac{3}5{}\\\\\theta=\tan^{-1}(\dfrac{3}5{})\\\\=30.96^{\circ}[/tex]

Hence, this is the required solutin.

i need help on this question.

Answers

Answer:

Answer: B. 49 N

Explanation:

Friction Force

When an object is at rest on a rough surface, it encounters a friction force that opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

[tex]Fr=\mu_k N[/tex]

Where [tex]\mu_k[/tex] is the coefficient of static friction and N is the normal force.  

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W = m.g

Thus, the friction force is:

[tex]Fr=\mu_k W[/tex]

We are given the coefficient of static friction [tex]\mu_k=0.5[/tex] and the mass of the object m=10 Kg. The minimum force needed to make it start moving is the maximum friction force:

Fr=0.5*10*9.8

Fr = 49 N

Answer: B. 49 N

Which of the following is true about thoughts

Answers

ya but what’s the following. there’s no options to choose between

Answer:

they can be unpredictable until you think it

Explanation:

Longitudinal seismic waves are known as
a primary waves.
b. secondary waves.
surface waves.
d. transverse waves.
Please select the best answer from the choices provided
О А
ОВ
ОС
D

Answers

Its “A“ primary waves!!!!!!

Answer:

A. primary waves

Explanation:

If six moles of hydrogen chloride (HCl) react with plenty of aluminum, how many moles of aluminum chloride (AlCl3) will the reaction produce?
2Al + 6HCl → 2AlCl3 + 3H2

Answers

Answer:

Two moles of aluminum chloride [tex](AlCl_3)[/tex] are produced when six miles of hydrogen Chloride [tex](HCl)[/tex] react with plenty of aluminum

Explanation:

6 Moles of [tex]HCl[/tex] will only react with 2 moles of [tex]Al[/tex] irrespective of the number of moles of each compound present. The reaction wiil take place in this ratio only. The products produced will be 2 moles of [tex]AlCl_3[/tex] and 3 moles of [tex]H_2[/tex] this ratio will also be constant.

So, six moles of hydrogen chloride [tex](HCl)[/tex] will react with plenty of aluminum to produce many 2 moles of aluminum chloride [tex](AlCl_3)[/tex].

two forces of 1.5N and 2.0N act vertically at two ends of a meter scale.Where and in what direvtion should a force should be applied so that the scale remains horizontally stable​

Answers

Answer:

.5 newtons on the 1.5 N side

Sometimes you can see a faint reflection in the surface of a shiny plate or cup.Why ?

Answers

Answer:

The degree of reflection whether faint or bright you see on the surface of an object is an indication that light particles had hit the surface. Since light is a wave and as part of its characteristics can get reflected. However, the amount of light reflected by a surface is dependent on the smoothness of the surface which can be shiny or dull, it can also be dependent on the nature of the surface which can be glass, water, and so on. So, from the question, you can see a faint reflection on the surface of a shiny plate or cup because of the smoothness of the surface which reflects the lights that hit it from a particular direction at the same angle.

How is an emulsion different from other colloids?

Answers

The difference between colloid and emulsion is that a colloid can form when any state of matter (solid, liquid or gas) combine with a liquid whereas an emulsion has two liquid components which are immiscible with each other.

Answer:

wrthfnhdghkyulyf

Explanation:

zdfhdfhghdhddddddddddddddddddddd

A bus slows from 10 m/s to a stop in 4 seconds.
What is its change in velocity? what is its acceleration?

Answers

Answer:

cant see to find the answer sorry :( i tried :( good luck !! you'll do great <3333 BEST OF LUCK :DDDD

Explanation:

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