Solve each equation for θ with 0 ≤ θ <2 π.

2 sinθ-√2=0

The number of sides in the regular polygon is 27.

The sum of the measures of the interior angles of a regular polygon is given as 4500 degrees. To find the number of sides in the polygon, we can use the formula for the sum of interior angles of a polygon, which is given by:

Sum = (n - 2) * 180 degrees

Here, 'n' represents the number of sides in the polygon. We can rearrange the formula to solve for 'n' as follows:

n = (Sum / 180) + 2

Substituting the given sum of 4500 degrees into the equation, we have:

n = (4500 / 180) + 2

n = 25 + 2

n = 27

Therefore, the regular polygon has 27 sides.

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A formula involving integrals for a particular solution of the differential equation y"' - 27y" + 243y' - 729y = g(t) is given by Y(t) = ∫[∫[∫g(t)dt]dt]dt.

To find a particular solution Y(t) of the given differential equation, we can use an integral formula.

The formula is Y(t) = ∫[∫[∫g(t)dt]dt]dt, which involves multiple integrals of the function g(t) with respect to t.

By repeatedly integrating g(t) with respect to t, we perform three successive integrations, representing the third, second, and first derivatives of the function Y(t), respectively.

This allows us to obtain a particular solution that satisfies the given differential equation.

It is important to note that the integral formula provides a general approach to finding a particular solution.

The specific form of g(t) will determine the integrals involved and the limits of integration, which need to be considered during the integration process.

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The median is 133 and the mode is 132.

Median and mode are measures of central tendency. Median is the number that is at the center of a dataset that has been arranged in ascending or descending order.

130, 130, 132, 132, 132, 134, 138, 140, 148, 148

Median = (n + 1) / 2

Where n is the number of observations

(10 + 1) / 2 = 11/5 = 5.5

The median is the 5.5th number - (132 + 134) / 2 = 133

Mode is the number that appears with the highest frequency in the dataset. The mode is 132 that appears 3 times

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The depth of the water in the large container cube is  2.6 inches.

Tracey have two empty cube shaped containers with sides 5 inches and 7 inches. she fills the smaller container and then pour the water in the larger container.

Therefore, the depth of the water in the larger container can be found as follows:

Hence,

volume of the smaller cube = 5³

volume of the smaller cube =  125 inches³

Therefore,

volume of water poured in the larger cube = lwh

125 = 7 × 7 × h

h = 125 / 49

h = 2.55102040816

h = 2.6 inches

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The parent function for g(x) = x + 2 is the identity function, f(x) = x, which is a straight line passing through the origin with a slope of 1.

To graph g(x) = x + 2, we start with the parent function and apply the transformation. The transformation for g(x) involves shifting the graph vertically upward by 2 units.

Here's the step-by-step process to graph g(x):

Plot points on the parent function, f(x) = x. For example, if x = -2, f(x) = -2; if x = 0, f(x) = 0; if x = 2, f(x) = 2.

Apply the vertical shift by adding 2 units to the y-coordinate of each point. For example, if the point on the parent function is (x, y), the corresponding point on g(x) will be (x, y + 2).

Connect the points to form a straight line. Since g(x) = x + 2 is a linear function, the graph will be a straight line with the same slope as the parent function.

The transformation of the parent function f(x) = x to g(x) = x + 2 results in a vertical shift upward by 2 units. This means that the graph of g(x) is the same as the parent function, but it is shifted upward by 2 units along the y-axis.

Visually, the graph of g(x) will be parallel to the parent function f(x), but it will be shifted upward by 2 units. The slope of the line remains the same, indicating that the transformation does not affect the steepness of the line.

i) The polar form of Z is:[tex]Z = 3\sqrt 2 \left( {\cos \frac{\pi }{4} + i\sin \frac{\pi }{4}} \right),[/tex]

ii) [tex]Z^7 = -2187 - 2187i[/tex] and is expressed in the form a + bi

Polar Form of Z = -3 -3i.

In order to express the complex number -3-3i in polar form, we use the formula:

r = \sqrt {a^2 + b^2 }

where a = -3 and b = -3,

hence;[tex]r &= \sqrt {a^2 + b^2 } \\&= \sqrt {{\left( { - 3} \right)^2} + {\left( { - 3} \right)^2}} \\&= \sqrt {18} \\&= 3\sqrt 2 \[/tex]

We can calculate the argument [tex]\theta of Z as:\theta = \tan ^{ - 1} \left( {\frac{b}{a}} \right)[/tex]

where a = -3 and b = -3,

hence;

  [tex]\theta &= \tan ^{ - 1} \left( {\frac{b}{a}} \right) \\&= \tan ^{ - 1} \left( {\frac{{ - 3}}{{ - 3}}} \right) \\&= \tan ^{ - 1} \left( 1 \right) \\&= \frac{\pi }{4} \[/tex]

Therefore, the polar form of Z is:

Z = [tex]3\sqrt 2 \left( {\cos \frac{\pi }{4} + i\sin \frac{\pi }{4}} \right)[/tex]

ii)  Z^7 = -2187 - 2187i and is expressed in the form a + bi

Since we already have Z in polar form we can now easily find

Z^7.Z^7 = [tex]{\left( {3\sqrt 2 } \right)^7}{\left( {\cos \frac{\pi }{4} + i\sin \frac{\pi }{4}} \right)^7}[/tex]

We can expand [tex]\left( {\cos \frac{\pi }{4} + i\sin \frac{\pi }{4}} \right)^7[/tex] using De Moivre's theorem:

[tex]\left( {\cos \theta + i\sin \theta } \right)^n = \cos n\theta + i\sin n\ \\theta\\Therefore; \\Z^7 &= {\left( {3\sqrt 2 } \right)^7}\left( {\cos \frac{{7\pi }}{4} + i\sin \frac{{7\pi }}{4}} \right) \\&= 3^7\left( {2\sqrt 2 } \right)\left( {\cos \left( {\frac{{6\pi }}{4} + \frac{\pi }{4}} \right) + i\sin \left( {\frac{{6\pi }}{4} + \frac{\pi }{4}} \right)} \right) \\&= 2187\sqrt 2 \left( { - \frac{1}{{\sqrt 2 }}} \right) + 2187i\left( { - \frac{1}{{\sqrt 2 }}} \right) \\&=  - 2187 - 2187i \[/tex]

Thus, Z^7 = -2187 - 2187i and is expressed in the form a + bi

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The correct placement of brackets to make the equation true is 3 + (4 * 2) - (2 * 3) = 3

To make the equation 3 + 4x2 - 2x3 = 3 true, we need to determine the correct placement of brackets to ensure the order of operations is followed.

Given the expression 3 + 4x2 - 2x3, we first perform the multiplications from left to right.

Multiplying 4x2, we have:

3 + (4 * 2) - 2x3 = 3 + 8 - 2x3

Next, we perform the multiplication 2x3:

3 + 8 - (2 * 3) = 3 + 8 - 6

Now, we perform the additions and subtractions from left to right:

3 + 8 - 6 = 11 - 6 = 5

As a result, the right bracket arrangement to make the equation true is: 3 + (4 * 2) - (2 * 3) = 3

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The value the variables are;

y = 2.3

x = 3.5

From the information given, we have that the triangle is

sin X = 3/4

divide the values, we have;

sin X = 0.75

X = 48. 6

Then, we have;

X + Y= 90

Y = 90 - 48.6 = 41.4 degrees

tan Y = y/2.6

cross multiply the values

y = 2.3

The value of x is ;

sin 41.4 = 2.3/x

x = 3.5

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The pixel with the maximum value in the given matrix is located at coordinates (3, 2) with a value of 13.

To find the pixel with the maximum value, we need to apply the given kernel on the 5x5 matrix. The kernel is a 3x4 matrix:

2 5 7 8

4 1 3 5

9 11 13 2

We start by placing the kernel on the top left corner of the matrix and calculate the element-wise product of the kernel and the corresponding sub-matrix. Then, we sum up the resulting values to determine the output for that position. We repeat this process for each valid position in the matrix.

After performing the calculations, we obtain the following result:

Output matrix:

60 89 136

49 77 111

104 78 62

The pixel with the maximum value in this output matrix is located at coordinates (3, 2) with a value of 13.

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The primitive function of the given function f(x) = -5/2 * x is F(x) = -5/4 * x² + C where C is the constant of integration. This means that F(x) is the antiderivative of f(x).

To find the antiderivative, integrate the given function with respect to x.

When we integrate the given function f(x) = -5/2 * x, we get;

∫f(x)dx = ∫-5/2 * x dx

= -5/2 ∫x dx

= -5/2 * x²/2 + C

The constant of integration C is an arbitrary constant and could take any real value.

Therefore, the antiderivative of f(x) is

F(x) = -5/4 * x² + C where C is a constant of integration.

The primitive function is usually the antiderivative of a function. The antiderivative of a function is its inverse operation of differentiation.

Therefore, to find the primitive function, we integrate the given function with respect to x.

In this case, the primitive function is given by F(x) = -5/4 * x² + C.

The primitive function of the given function f(x) = -5/2 * x is F(x) = -5/4 * x² + C where C is the constant of integration. This function is obtained by integrating f(x) with respect to x. The constant of integration C is an arbitrary constant and could take any real value.

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A basis for the vector space {f(x) ∈ P3[x] | ƒ′(6) = ƒ(1)} is {p(x) = ax^2 + bx + 11a, q(x) = dx}, where a and d can be any real numbers.

To find a basis {p(x), q(x)} for the given vector space {f(x) ∈ P3[x] | ƒ′(6) = ƒ(1)}, we need to find two polynomials p(x) and q(x) that satisfy the condition ƒ′(6) = ƒ(1) and are linearly independent.

Let's start by finding p(x):

We can choose p(x) as a polynomial of degree 2 since we are working with P3[x].

Let p(x) = ax^2 + bx + c.

Taking the derivative of p(x), we have:

p'(x) = 2ax + b.

We need p'(6) to be equal to p(1), so let's evaluate them:

p'(6) = 2a(6) + b = 12a + b

p(1) = a(1)^2 + b(1) + c = a + b + c

For p'(6) = p(1), we have:

12a + b = a + b + c

Simplifying this equation, we get:

11a = c

So, we can choose c = 11a.

Thus, p(x) = ax^2 + bx + 11a.

Now, let's find q(x):

We can choose q(x) as a polynomial of degree 1 since we are working with P3[x].

Let q(x) = dx + e.

Taking the derivative of q(x), we have:

q'(x) = d.

We need q'(6) to be equal to q(1), so let's evaluate them:

q'(6) = d

q(1) = d(1) + e = d + e

For q'(6) = q(1), we have:

d = d + e

Simplifying this equation, we get:

e = 0

Thus, q(x) = dx.

Therefore, a basis for the vector space {f(x) ∈ P3[x] | ƒ′(6) = ƒ(1)} is {p(x) = ax^2 + bx + 11a, q(x) = dx}, where a and d can be any real numbers.

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The profit from selling 30 violins is $79,850. The composite function for the craftsman’s profit is P(I(x)) = 5995x - 100,000. We can use this composite function to find the profit earned when he sells 30 violins by substituting x = 30 in the function.

The craftsman makes and sells violins. The function (I(x)=5995 x) represents the income in dollars from selling (x) violins. The function (P(y)=y-100,000) represents his profit in dollars if he makes an income of (y) dollars.

We are given that the function for income in dollars from selling x violins is I(x) = 5995x. The craftsman’s profit P(y) is given by the function y - 100,000. We want to find out the craftsman’s profit when he sells 30 violins.So the income earned from selling 30 violins is:

I(30) = 5995 × 30 = 179,850

Therefore, the craftsman’s profit is: P(179,850) = 179,850 - 100,000 = 79,850

We can write the composite function for the craftsman’s profit as follows: P(I(x)) = I(x) - 100,000

We know that the income from selling x violins is I(x) = 5995x. We can substitute this value in the composite function to get: P(I(x)) = 5995x - 100,000

To find the profit earned when he sells 30 violins, we substitute x = 30 in the above expression: P(I(x)) = P(I(30))= P(5995 × 30 - 100,000)= P(79,850)= 79,850

Therefore, the profit earned when he sells 30 violins is $79,850.

Thus, the profit from selling 30 violins is $79,850. The composite function for the craftsman’s profit is P(I(x)) = 5995x - 100,000. We can use this composite function to find the profit earned when he sells 30 violins by substituting x = 30 in the function.

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Solve the system using systematic elimination to find x(t) and y(t).

The given problem asks to solve a system of differential equations using systematic elimination.

Systematic elimination is a method used to eliminate one variable at a time from a system of equations to obtain a simplified form.

In this case, we have two equations involving the variables x and y, along with their respective derivatives.

The goal is to find the functions x(t) and y(t) that satisfy these equations. By applying systematic elimination, we can eliminate one variable by manipulating the equations algebraically.

The resulting simplified equation will involve only one variable and its derivative.

Solving this simplified equation will yield the solution for that variable.

Repeat the process for the remaining variable to obtain the complete solution for the system of differential equations.

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Answer:

To find out how many hours Elmer will have to work to pay for the new bike, we first need to know the total cost of the bike, which is $90 according to the previous question.

Elmer earns $12 per hour. So, we can calculate the total hours he would need to work by dividing the total cost of the bike by his hourly wage.

Total hours = Total cost / Hourly wage = $90 / $12 = 7.5 hours

Therefore, Elmer will have to work for 7.5 hours to pay for the new bike.

If x, a, b ∈ R and xa = xb, it is not always true that a = b. The equation xa = xb can be rewritten as x(a - b) = 0. In order for this equation to hold true, either x = 0 or (a - b) = 0.

Case 1: If x = 0, then the equation xa = xb becomes 0a = 0b, which is true for any values of a and b.

Case 2: If (a - b) = 0, then a = b, and the equation xa = xb holds true.

However, if neither x = 0 nor (a - b) = 0, then the equation xa = xb implies that x = 0 and (a - b) = 0 simultaneously, which leads to a contradiction.

Therefore, the statement "if x, a, b ∈ R and xa = xb, then a = b" is false.

Regarding the second part of your question, when asked to prove the implication "If P, then Q" by arguing by contradiction, we need to assume P is true and attempt to derive a contradiction. This means we assume P is true and Q fails, and try to find a contradiction.

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The integral that represents the volume of the surface that lies below the surface z = 4xy - y³ and above the region D in the xy-plane is given by:

Volume = ∫[0,2]∫[0,2π] (4rcosθrsinθ - r³sin³θ) rdrdθ.

The given equation is z = 4xy - y³, and the region D is bounded by y = 0, x = 0, x + y = 2, and the circle x² + y² = 4.

To obtain the integral that represents the volume of the surface that lies below the surface z = 4xy - y³ and above the region D in the xy-plane, we will use double integration as follows:

Volume = ∫∫(4xy - y³) dA

Where the limits of integration are as follows:

First, we find the limits of integration with respect to y:

y = 0

y = 2 - x

Secondly, we find the limits of integration with respect to x:

Lower limit: x = 0

Upper limit: x = 2 - y

Now we set up the integral as follows:

Volume = ∫[0,2]∫[0,2π] (4rcosθrsinθ - r³sin³θ) rdrdθ

where D is described by r = 2cosθ.

The above integral is calculated using polar coordinates because the region D is a circular region with a radius of 2 units centered at the origin of the xy-plane.

This implies that we have the following limits of integration: 0 ≤ r ≤ 2cosθ and 0 ≤ θ ≤ 2π.

Therefore, the integral that denotes the volume of the surface above the area D in the xy-plane and beneath the surface z = 4xy - y³ is denoted by:

Volume = ∫[0,2]∫[0,2π] (4rcosθrsinθ - r³sin³θ) rdrdθ.

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Given the functions:f(x) = x² - 3xg(x) = √(2x)h(x) = 5x - 4

To find the value of (hog) (x) for x = 2,

we need to evaluate h(g(x)), which is given by:h(g(x)) = 5g(x) - 4

We know that g(x) = √(2x)∴ g(2) = √(2 × 2) = 2

Hence, (hog) (2) = h(g(2))= h(2)= 5(2) - 4= 6

Therefore, (hog) (2) = 6.

In this problem, we were required to evaluate the composite function (hog) (x) for x = 2,

where g(x) and h(x) are given functions.

The solution involved first calculating the value of g(2),

which was found to be 2. We then used this value to calculate the value of h(g(2)),

which was found to be 6.

Thus, the value of (hog) (2) was found to be 6.

The simplified exact form of √Undefined × X Ś is Undefined,

as the square root of Undefined is undefined.

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Answer:

07n + 6

Step-by-step explanation:

Given: The cost of 7 t-shirts and a $6 tax

Let n represent the cost of 1 t-shirt.

Then, the total cost of 7 t-shirts would be 7n.

Adding the $6 tax gives a total cost of 7n + 6.

Therefore, the correct option is:

07n + 6

The answer choice which could represent the cost of 7 t-shirts and a $6 tax as in the task content is: 7n + 6.

It follows that the cost of 7 t-shirts and a $6 tax is the statement which is to be represented algebraically.

On this note, it follows that the if the cost of each t-shirts is taken to be: n.

Therefore, the required representation of the total cost would be:

[tex]\rightarrow\bold{7n + 6}[/tex]

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The national people meter sample has 4,000 households, and 250

of those homes watched program A on a given Friday Night. In other

words 6.25% of all households watched program A.

To determine the fraction of all households that watched program A, we divide the number of households that watched program A by the total number of households in the sample.

Fraction of households that watched program A = Number of households that watched program A / Total number of households in the sample

Fraction of households that watched program A = 250 / 4000

Fraction of households that watched program A ≈ 0.0625

Therefore, approximately 6.25% of all households watched program A.

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The congruence relation mod n is transitive.

The congruence relation mod n is reflexive.

The congruence relation mod n is symmetric.

How to prove the relation

To prove that the congruence relation mod n is transitive, reflexive, and symmetric

Transitivity: If a≡ n b and b≡ n c, then a≡ n c.

Reflexivity: For any natural number a, a≡ n a.

Symmetry: If a≡ n b, then b≡ n a.

To prove transitivity, assume that a≡ n b and b≡ n c. This means that there exist natural numbers k and j such that b-a=nk and c-b=nj. Adding these two equations

c-a = (c-b) + (b-a) = nj + nk = n(j+k)

Since j and k are natural numbers, j+k is also a natural number. Therefore, n divides c-a, which means that a≡ n c.

Thus, the congruence relation mod n is transitive.

Similarly, to prove reflexivity, we need to show that for any natural number a, a≡ n a. This is true because a-a=0 is divisible by any natural number, including n.

Hence, the congruence relation mod n is reflexive.

To prove symmetry, assume that a≡ n b. This means that there exists a natural number k such that b-a=nk. Dividing both sides by -n,

a-b = (-k)n

Since -k is also a natural number, n divides a-b, which means that b≡ n a.

Therefore, the congruence relation mod n is symmetric.

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Congruence mod n is reflexive, transitive, and symmetric.

In the previous question, we proved that n divides a - a or a - a = 0.

Therefore a ≡ a (mod n) is true and we have n divides 0, i.e.,  ∃k:Nvnk=∣a−a∣ = 0.

Thus, congruence mod n is reflexive.

Let a ≡ n b and b ≡ n c such that n divides b - a and n divides c - b.

Therefore, there exist two natural numbers p and q such that b - a = pn and c - b = qn.

Adding the two equations, we have c - a = (p + q)n. Since p and q are natural numbers, p + q is also a natural number. Therefore, n divides c - a.

Hence, congruence mod n is transitive.

Now, let's prove that congruence mod n is symmetric.

Suppose a ≡ n b. This means that n divides b - a. Then there exists a natural number k such that b - a = kn. Dividing both sides by -1, we get a - b = -kn. Since k is a natural number, -k is also a natural number.

Hence, n divides a - b. Therefore, b ≡ n a. Thus, congruence mod n is symmetric.

Therefore, congruence mod n is reflexive, transitive, and symmetric.

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When you are writing a positioning statement, if you do not have real differences and cannot see a way to create them, then you can create a difference based on b) opinion.

A positioning statement is a brief, clear, and distinctive description of who you are and what separates you from your competition when you are competing for attention in the marketplace. A company's position is the set of customer perceptions of its goods and services relative to those of its rivals. A successful positioning strategy places your goods or services in the minds of your customers as better or more affordable than your competitors'. A company's positioning strategy is how it distinguishes itself from its rivals. A strong positioning statement is essential for any company, brand, or product. It communicates to the target audience why a company is unique and distinct from others. Positioning that is based on opinion includes marketing that makes sweeping statements, claims, or guarantees that cannot be validated or demonstrated as fact.

This is often referred to as 'puffery.' Puffery is a technique used by advertisers to promote a product in a way that does not make a factual statement but instead generates a feeling in the consumer that their product is superior to others on the market. Opinion-based positioning requires a great deal of creativity and should be combined with strong marketing, advertising, and public relations to ensure that the message is communicated successfully to the target audience.

Therefore, the correct answer is b) opinion.

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Based on the given information, the product should be distributed from {S}1 to the retailers located at R1, R2, R3, and R4.

To determine the most efficient distribution route, several factors need to be considered. These factors include the distance between the origin point {S}1 and each retailer, transportation costs, logistical infrastructure, and delivery timeframes. By evaluating these factors, a decision can be made regarding the optimal distribution route.

One approach could be to assess the geographical proximity of {S}1 to each retailer. If {S}1 is closest to R1 compared to the other retailers, it would make logistical sense to prioritize R1 for distribution. However, other factors such as transportation costs and delivery timeframes must also be considered. If the transportation costs are significantly higher or the delivery timeframes are longer for R1 compared to the other retailers, it might be more efficient to distribute the product to a different retailer.

Moreover, the logistical infrastructure and transportation networks available between {S}1 and the retailers should be evaluated. If there are direct and efficient transportation routes between {S}1 and one or more retailers, it would make sense to utilize those routes for distribution. This consideration would help minimize transportation costs and delivery times.

Ultimately, the decision on the optimal distribution route depends on a comprehensive analysis of various factors such as geographical proximity, transportation costs, logistical infrastructure, and delivery timeframes. By carefully evaluating these factors, a well-informed decision can be made regarding the distribution of the product from {S}1 to retailers R1, R2, R3, and R4.

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The solution of the higher-order differential equation y⁽⁴⁾ - y‴ + 2y = 0 is: y = C₁e^t + C₂cos(√2t) + C₃sin(√2t) + C₄t * e^t

where C₁, C₂, C₃, and C₄ are arbitrary constants.

Given the higher-order differential equation y⁽⁴⁾ - y‴ + 2y = 0.

To solve this equation, assume a solution of the form y = e^(rt). Substituting this form into the given equation, we get:

r⁴e^(rt) - r‴e^(rt) + 2e^(rt) = 0

⇒ r⁴ - r‴ + 2 = 0

This is the characteristic equation of the given differential equation, which can be solved as follows:

r³(r - 1) + 2(r - 1) = 0

(r - 1)(r³ + 2) = 0

Thus, the roots are r₁ = 1, r₂ = -√2i, and r₃ = √2i.

To find the solution, we can use the following steps:

For the root r₁ = 1, we get y₁ = e^(1t).

For the root r₂ = -√2i, we get y₂ = e^(-√2it) = cos(√2t) - i sin(√2t).

For the root r₃ = √2i, we get y₃ = e^(√2it) = cos(√2t) + i sin(√2t).

For the double root r = 1, we need to find a second solution, which is given by t * e^(1t).

The general solution of the differential equation is:

y = C₁e^t + C₂cos(√2t) + C₃sin(√2t) + C₄t * e^t

The above solution contains four arbitrary constants (C₁, C₂, C₃, and C₄), which can be evaluated using initial conditions or boundary conditions. Therefore, the solution of the higher-order differential equation y⁽⁴⁾ - y‴ + 2y = 0 is:

y = C₁e^t + C₂cos(√2t) + C₃sin(√2t) + C₄t * e^t

where C₁, C₂, C₃, and C₄ are arbitrary constants.

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Answer:

For two triangles to be similar, their corresponding angles must be equal. Triangle 1 has angles measuring 26°, 53°, and an unknown angle. Triangle 2 has angles measuring 26°, a°, and an unknown angle.

To determine the value of a that would refute Frank's claim, we need to find a value for which the unknown angles in both triangles are equal.

In triangle 1, the sum of the angles is 180°, so the third angle can be found by subtracting the sum of the known angles from 180°:

Third angle of triangle 1 = 180° - (26° + 53°) = 180° - 79° = 101°.

For triangle 2 to be similar to triangle 1, the unknown angle in triangle 2 must be equal to 101°. Therefore, the value of a that would refuse Frank's claim is a = 101°.

Step-by-step explanation:

Answer:

101

Step-by-step explanation:

In Δ1, let the third angle be x

⇒ x + 26 + 53 = 180

⇒ x = 180 - 26 - 53

⇒ x = 101°

∴ the angles in Δ1 are 26°, 53° and 101°

In Δ2, if the angle a = 101° then the third angle will be :

180 - 101 - 26 = 53°

∴ the angles in Δ2 are 26°, 53° and 101°, the same as Δ1

So, if a = 101° then the triangles will be similar

Answer: 15.83%

Step-by-step explanation: To find the percentage of the original bill saved with the coupon, you need to find how much of the original bill is reduced by. 31.58 - 26.58 = 5. And 5 is what percentage of 31.58. So you do 5/31.58 and multiply by 100% to get the answer in percent.

(3Q)^(t) = 3Q^(t) this expression can be concluded as true.

The given matrix is Q = [2 3][1 -2]

To prove that (3Q)^(t) = 3Q^(t),

we need to calculate the transpose of both sides of the equation.

Let's solve it step by step as follows:

(3Q)^(t)

First, we will calculate 3Q which is;

3Q = 3[2 3][1 -2]= [6 9][-3 6]

Then we will calculate the transpose of 3Q as follows;

(3Q)^(t) = [6 9][-3 6]^(t)= [6 9][-3 6]= [6 -3][9 6]Q^(t)

Now we will calculate Q^(t) which is;

Q = [2 3][1 -2]

So,

Q^(t) = [2 1][3 -2]

Therefore, we can conclude that (3Q)^(t) = 3Q^(t) is true.

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The probability that should be found is A. P(5 female undergraduates take on debt).

To calculate this probability, we can use the binomial probability formula. In this case, we have 50 female undergraduates selected at random, and the probability that an individual female undergraduate takes on debt is 11.9% or 0.119.

The binomial probability formula is given by:

P(X = k) = (n C k) * p^k * (1 - p)^(n - k)

Where:

- P(X = k) is the probability of exactly k successes (in this case, 5 female undergraduates taking on debt).

- n is the total number of trials (in this case, 50 female undergraduates selected).

- k is the number of successes we want to find (in this case, exactly 5 female undergraduates taking on debt).

- p is the probability of success on a single trial (in this case, 0.119).

- (n C k) represents the number of combinations of n items taken k at a time, which can be calculated using the formula: (n C k) = n! / (k! * (n - k)!)

Now, let's calculate the probability using the formula:

P(5 female undergraduates take on debt) = (50 C 5) * (0.119)^5 * (1 - 0.119)^(50 - 5)

Calculating the combination and simplifying the expression:

P(5 female undergraduates take on debt) ≈ 0.138

Therefore, the probability that exactly 5 female undergraduates have taken on debt, out of a random selection of 50 female undergraduates, is approximately 0.138.

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A function is known f(x) = 5x^(1/2) + 3x^(1/4) + 7, we have to find the first derivative of the function. The derivative of a function is the measure of how much the function changes with respect to a change in the input variable, x. The first derivative of the function f(x) is given by f'(x).

To find the first derivative of the function, f(x) = 5x^(1/2) + 3x^(1/4) + 7, we will use the power rule of differentiation. The power rule of differentiation states that if f(x) = x^n, then f'(x) = nx^(n-1) where n is a real number. Applying the power rule of differentiation to the given function,

we getf(x) = 5x^(1/2) + 3x^(1/4) + 7=> f'(x) = (5 × (1/2) x^(1/2-1)) + (3 × (1/4) x^(1/4-1)) + 0= (5/2)x^(-1/2) + (3/4)x^(-3/4)Now, the first derivative of the function is given by f'(x) = (5/2)x^(-1/2) + (3/4)x^(-3/4).Therefore, option (d) is the correct answer.

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The solution for the expression are A=0, B=1, C=0 and D=3. The solution for x=5/2 and y=√15/2.

Given expression is:

\frac{x^2+x+3}{(x^2+1)^2}=\frac{Ax+B}{x^2+1}+\frac{Cx+D}{(x^2+1)^2}

Comparing the two sides, we get:

(x^2+x+3)=(Ax+B)(x^2+1)+(Cx+D)

Expanding the right side, we get:

(x^2+x+3)=Ax^3+(A+B)x^2+(B+C)x+(C+D)

For the coefficients of x^3 on both sides to be equal, we must have A=0.

For the coefficients of x^2 on both sides to be equal, we must have A+B=1.

Substituting A=0, we get B=1.

For the coefficients of x on both sides to be equal, we must have B+C=1.

Substituting B=1, we get C=0.

For the constants on both sides to be equal, we must have C+D=3.

Substituting C=0, we get D=3.

Hence, we get:\frac{x^2+x+3}{(x^2+1)^2}=\frac{1}{x^2+1}+\frac{3}{(x^2+1)^2}

Solving the system of equations x^2-y^2=-5 and 3x^2+2y^2=30:

Multiplying the first equation by 2, we get:

2x^2-2y^2=-10\implies x^2-y^2+2x^2= -5+2x^2

Substituting 3x^2+2y^2=30, we get:

(3x^2+2y^2) + x^2-y^2 = 30-5\implies 4x^2 = 25\implies x = \pm\frac{5}{2}

Substituting in x^2-y^2=-5, we get:

y^2 = \frac{15}{4}\implies y = \pm\frac{\sqrt{15}}{2}

Therefore, the solutions are:(x,y) = \left(\frac{5}{2},\frac{\sqrt{15}}{2}\right), \left(\frac{5}{2},-\frac{\sqrt{15}}{2}\right), \left(-\frac{5}{2},\frac{\sqrt{15}}{2}\right), \left(-\frac{5}{2},-\frac{\sqrt{15}}{2}\right).

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