Answer: D. None of these will increase the half life.
Explanation:
Half life is the amount of time taken to decay to half of its original value. The half life is related to rate constant by the following relation for a first order reaction:
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]
As half life is independent of concentration , temperature and pressure, none of these factors would affect the half life.
Thus in the reaction, [tex]SO_2Cl_2 \rightarrow SO_2(g)+Cl_2(g)[/tex] following first order kinetics, none of the factors will increase the half life.
Which one of the following is most likely to be an ionic compound? SO2
Answer:
Ionic compounds generally form between elements that are metals and elements that are nonmetals. For example, the metal calcium (Ca) and the nonmetal chlorine (Cl) form the ionic compound calcium chloride (CaCl2). In this compound, there are two negative chloride ions for each positive calcium ion
A beaker of water is initially saturated with dissolved air. Explain what heppens whe he gas at 1 atm is bubbled through the solution for a long time.
Answer:
The bubble goes into the atmosphere.
Explanation:
All the dissolved air evaporated from the water when there is 1 atmospheric pressure for a long time because the air is dissolved with high pressure so when the pressure is removed from the gas present in water. The bubble go away from the water solution due to more kinetic energy present in it as compared to lower atmospheric pressure.
How many hydrogen atoms are present in .46 moles of NH3
Answer:
2.78 x 10²³
Explanation:
1 mole contains 6.02 x 10²³ hydrogen atoms => 0.46 mole contains 0.46(6.02 x 10²³) hydrogen atoms or 2.78 x 10²³ atoms.
Caution => When to use H vs H₂ => This problem is specific for 'hydrogen atoms' but some may simply say hydrogen. In such cases use H₂ or 'molecular hydrogen' is the focus. it's a matter of semantics, H vs H₂.
If you are heating something, you can step away for a moment, as long as you come back very quickly.
a. True
b. False
Answer: b. False
Explanation:
The more energetic molecules move to a gas, spread out, and form bubbles when heating happens. When exposed to heat, many of the chemicals used in the laboratory are volatile and harmful (fire).
So leaving a material that you heat for even a second can be very hazardous and negligent.
Which of the following is an example of a physical change?
A. Getting a suntan
B. Digesting your food
C. Cutting your hair
D. Growing taller
SUBMIT
Answer:
C. Cutting your hair
Explanation:
A physical change is one of the two types of changes in nature (the other being chemical change). A physical change does not affect the chemical composition of the substance(s) involved.
In this case, "CUTTING ONE'S HAIR" is an example of physical change because it involves the removal of the hair without altering the chemical composition of the hair. However, other examples given in the options of this question like digestion of food, getting a suntan (change in skin coloration), and growth in height all involve a change in the chemical nature of the parts involved, hence, they are examples of chemical changes.
Whats a homogeneous mixture? A mixture that contains particles_____________
A. that are unevenly mixed together
B. that are evenly mixed together
C. that eventually separate
D. suspended in gelatin
Answer:
A homogeneous mixture is a mixture in which the components that make up the mixture are uniformly distributed throughout the mixture.
Explanation:
When a galvanic cell is comprised of an anode and a cathode of precisely the same material, this is called a(n):
Answer:
Concentration cell
Explanation:
Galvanic cells and even electrolytic cells usually consist of two electrodes namely anode and cathode. These 2 electrodes can either be made of the same metals or different metals, and also an electrolyte whereby the two electrodes are immersed.
Now, in the case where the electrodes are made of the same metal, we call it a concentration cell because A concentration cell is a cell that consists of two half-cells that have the same electrodes, but yet differ in concentrations.
The energy of the universe is constant. That what mentioned by the first law of thermodynamics,
Does this mean that AE is always equal to zero?
Select one:
a. Yes, AE = 0 at all times, which is why q = -W
b. No, AE does not always equal zero because it refers to the system's internal energy, which is
affected by heat and work.
c. No, AE never equals zero because work is always being done on the system or by the
system.
d. No, AE does not always equal zero, but this is only due to factors like friction and heat.
e. No, AE never equals zero because energy is always flowing between the system and
surroundings.
Answer:
No, ΔE does not always equal zero because it refers to the systems internal energy, which is affected by heat and work
Explanation:
According to the first law of thermodynamics, energy is neither created nor destroyed. This implies that the total energy of a system is always a constant.
So, according to the first law of thermodynamics we have that ΔE = q + w. This means that the value of ΔE depends on q (heat) and w(work). Hence ΔE is not always zero since it depends on the respective values of q and w.
NH4I(s) NH3(g) HI(g) Calculate the equilibrium concentration of HI when 0.343 moles of NH4I(s) are introduced into a 1.00 L vessel at 673 K. [HI]
This question is incomplete, the complete question is;
The equilibrium constant, Kc, for the following reaction is 7.00×10-5 at 673 K. NH4I(s) ---> NH3(g) + HI(g) Calculate the equilibrium concentration of HI when 0.343 moles of NH4I(s) are introduced into a 1.00 L vessel at 673 K
Answer:
the equilibrium concentration of HI is 1.302 × 10⁻⁵ M
Explanation:
Given that;
kc = 7.00 × 10⁻⁵ at 673 K
equilibrium concentration of HI = ?
when 0.343 moles of NH4I(s) are introduced into a 1.00 L vessel at 673 K
Molarity of NH4I = 0.343 / 1.00 = 0.343 M
NH4I(s) -----------------> NH3(g) + HI(g)
0.343 0 0 ------> Initial
(0.343 - x) x x -------> equilibrium
we know that; solid does not take part in equilibrium constant expression
so
KC = [NH3] [HI] / NH4I
we substitute
7.00 × 10⁻⁵ = x² / (0.343 - x)
0.00007 (0.343 - x) = x²
0.00002401 - 0.00007x = x²
x² + 0.00007x - 0.00002401 = 0
using; x = -b±√(b² - 4ac) / 2a
we substitute
x = -0.00007 ± √((0.00007)² - 4×1×-0.00002401) / 2×1
x = [-0.00007 ± √( 4.9×10⁻⁹ + 9.604×10⁻⁵)] / 2
x = [-0.00007 ± 0.00009604] / 2
Acceptable value of x = [-0.00007 + 0.00009604] / 2
x = 0.00002604 /2
x = 0.00001302 ≈ 1.302 × 10⁻⁵ M
therefore the equilibrium concentration of HI is 1.302 × 10⁻⁵ M
How to convert chlorophenylamine to bromochlorobenzene
Answer:
hey buddy,This's your answer...!!
Select the atom/ion in each pair which has a larger radius F or F-1
Answer:
F-
Explanation:
The atomic radius of F is 72 pm and that of F- is 136 pm.
PLS HELP ASAP 50 POINTS
The two main factors keep a planet in motion are what and what?
Answer:
Gravity, Inertia, and Velocity ( I decided to use three)
Explanation:
Gravity is the primary force that controls orbit and gravity works with inertia along with velocity.
Gravity, Inertia, and Velocity ( I decided to use three)
Explanation:
Gravity is the primary force that controls orbit and gravity works with inertia along with velocity.
In a bowl of 50 skittles, you have 12 yellow, 9 orange, 11 red, and 13 green. The rest of the skittles are purple. What percentage of the skittles are red? What percentage of the skittles are not green?
Answer:
percentage of red skittles = 22%
percentage of skittles that are not green = 74%
Explanation:
total skittles = 50
yellow = 12
orange = 9
red = 11
green = 13
purple = 50-12-9-11-13
= 5
1) percentage of red skittles
[tex] \frac{red \: skittles}{total \: skittles} \times 100[/tex]
[tex] \frac{11}{50} \times 100[/tex]
[tex] \frac{22}{10} [/tex]
[tex]22\%[/tex]
2) percentage of skittles that are not green
[tex] \frac{total \: skittles - green \: skittles}{total \: skittles} \times 100[/tex]
[tex] \frac{50 -13 }{50} \times 100[/tex]
[tex] \frac{37}{50} \times 100[/tex]
[tex]74\%[/tex]
What is the percent of hydrogen by mass in HNO3?
the percent of hydrogen by mass in HNO3 is 1.600%
Answer:
[tex]\boxed {\boxed {\sf 1.5996953 \%\ or \ 1.6 \%}}[/tex]
Explanation:
Percent composition tells us the mass percentage of an element in a compound. It can be found by dividing the mass of the element by the mass of the compound, then multiplying by 100.
[tex]\frac{element \ mass}{compound \ mass} *100[/tex]
1. Compound Mass
The compound given is HNO₃
Hydrogen (H) and Nitrogen (N) have no subscript, implying there is 1 atom of each element. Oxygen (O) has a subscript of 3, so there are 3 atoms.Use the Periodic Table to find the masses of each element.
Hydrogen: 1.008 u Nitrogen: 14.007 u Oxygen: 15.999 uNext, multiply each element's mass by the number of atoms, then add them together.
(1.008 u) + (14.007 u) + (3 * 15.999 u)63.012 u2. Percent Composition
Now we know that HNO₃'s mass is 63.012 u. This is the compound mass.
We want to find the percent of hydrogen and its mass is 1.008 u. This is the element mass.
[tex]\frac{1.008 \ u }{63.012\ u } *100[/tex]
[tex]0.015996953*100[/tex]
[tex]1.5996953[/tex]
This can be rounded to the nearest tenth. The 9 in the hundredth place tells us to round the 5 to a 6.
[tex]\approx 1.6[/tex]
The percent of hydrogen in HNO₃ is 1.5996953% or about 1.6%
Which method would be best to separate a mixture of sugar and water?
1.separation by density
2.separation by particle size
3.fration
4.distillation
Answer:
distillation
Explanation:
distillation is better suited separation method
Bleach is more basic than egg whites.
Bleach is more basic than egg whites.
Egg whites are more basic than bleach.
Egg whites are more basic than bleach.
Bleach is more acidic than egg whites.
Bleach is more acidic than egg whites.
Egg whites are more acidic than bleach.
Question 11 of 31
What is the molarity of 820 mL of Kl solution that contains 36.52 g of KI?
The Periodic Table
A. 45 mol/L
B. 0.27 mol/L
C. 2.7 x 10-4 mol/L
D. 0.45 mol/L
Answer:
Molarity = 0.27 M
Explanation:
Given data:
Volume of solution = 820 mL (820/1000 = 0.82L)
Mass of KI = 36.52 g
Molarity of solution = ?
Solution:
Number of moles of KI:
Number of moles = mass/molar mass
Number of moles = 36.52 g/ 166 g/mol
Number of moles = 0.22 mol
Molarity = number of moles / volume in L
Molarity = 0.22 mol / 0.82 L
Molarity = 0.27 M
Perform the following calculations and report each answer with the correct number of significant figures.
a. 628 × 342 b. 5.45 – 2.3 c. 28.0/13.483
d. 14.98 + 27,340 + 84.7593
Answer:
Answers are given below
Explanation:
Significant figures:
When we add or subtract the values the number of significant figures after decimal in result must be equal to the given measurement having less number of decimal places.
b) 5.45 -2.3
3.2
d) 14.98 + 27,340 + 84.7593
27439.74
When we multiply or divide the values the number of significant figures must be equal to the less number of significant figures in given value.
a) 628 × 342
214776
we will round off this value into 3 significant figures.
215000
c) 28.0/13.483
2.08
Of the choices below, which is the most abundant gas in Earth's atmosphere?
Practice
A
argon
B
nitrogen
C
carbon dioxide
D
oxygen
Answer:
B. Nitrogen
Explanation:
Hope this helps :)
The answer is nitrogen gas.
The hybrid orbital set used by the central atom in IO2- is ________.
Explanation:
[tex]IO_2^-[/tex] is the Iodite ion. The ion has a total of 7+6(2)+1 = 20 electrons. The Iodite ion, or iodine dioxide anion, is the halite with the chemical formula IO−
2. Within the ion the Iodine exists in the oxidation state of +3. The hybridization state of central atom I in Iodite ion is [tex]d^2sp^3[/tex].
Which of the following BEST describes a way in which water moves in the water cycle?
A. Water falls from the sky as rain. It stays where it falls until it evaporates
B. Water falls from the sky as snow. As the snow melts, the water runs up to Earth's mountains.
C. Water falls from the sky as rain. The water then flows downhill
D. Water falls from the sky as hail. The hail is eventually buried in the ground
Answer:
C. Water falls from the sky as rain. The water then flows downhill.
Explanation:
Water cycle can be defined as a process which typically involves the circulation (movement) of water between the Earth's atmosphere, land and ocean under various atmospheric conditions such as precipitation (rain and snow), transpiration, condensation and evaporation.
Basically, the movement of the water starts from the sky due to the condensation of water vapor to form clouds and later result to rainfall. Consequently, the rain water are either soaked by the soil or are made to flow down the hill.
The statement which best describes a way in which water moves in the water cycle is that, water falls from the sky as rain. The water then flows downhill or seeps into the ground.
A cube of an unknown metal measures 0.200 cm on one side. The mass of the cube is 52 mg. Which of the following is most likely the unknown metal?
Metal Density(g/cm^3)
rhodium 12.4
copper 8.96
niobium 8.57
vanadium 6.11
zirconium 6.51
a. copper
b. rhodium
c. niobium
d. vanadium
e. zirconium
Answer:
Option E. Zirconium
Explanation:
From the question given above, the following data were obtained:
Length of side (L) of cube = 0.2 cm
Mass (m) of cube = 52 mg
Name of the unknown metal =?
Next, we shall determine the volume of the cube. This can be obtained as follow:
Length of side (L) of cube = 0.2 cm
Volume (V) of the cube =?
V = L³
V = 0.2³
V = 0.008 cm³
Next, we shall convert 52 mg to g. This can be obtained as follow:
1000 mg = 1 g
Therefore,
52 mg = 52 mg × 1 g / 1000 mg
52 mg = 0.052 g
Thus, 52 mg is equivalent to 0.052 g.
Next, we shall determine the density of the unknown metal. This can be obtained as follow:
Mass = 0.052 g.
Volume = 0.008 cm³
Density =?
Density = mass / volume
Density = 0.052 / 0.008
Density of the unknown metal = 6.5 g/cm³
Comparing the density of the unknown metal i.e 6.5 g/cm³ with those given in table in the above, we can conclude that the unknown metal is zirconium
Help me plzzzzzzzzz
Pure metals possess few important physical and metallic properties, such as melting point, boiling point, density, specific gravity, high malleability, ductility, and heat and electrical conductivity. These properties can be modified and enhanced by alloying it with some other metal or nonmetal, according to the need.
Alloys are made to:
Enhance the hardness of a metal: An alloy is harder than its components. Pure metals are generally soft. The hardness of a metal can be enhanced by alloying it with another metal or nonmetal.
Lower the melting point: Pure metals have a high melting point. The melting point lowers when pure metals are alloyed with other metals or nonmetals. This makes the metals easily fusible. This property is utilized to make useful alloys called solders.
Enhance tensile strength: Alloy formation increases the tensile strength of the parent metal.
Enhance corrosion resistance: Alloys are more resistant to corrosion than pure metals. Metals in pure form are chemically reactive and can be easily corroded by the surrounding atmospheric gases and moisture. Alloying a metal increases the inertness of the metal, which, in turn, increases corrosion resistance.
Modify color: The color of pure metal can be modified by alloying it with other metals or nonmetals containing suitable color pigments.
Provide better castability: One of the most essential requirements of getting good castings is the expansion of the metal on solidification. Pure molten metals undergo contraction on solidification. Metals need to be alloyed to obtain good castings because alloys
Write a balanced chemical equation that shows the formation of 2,3-dimethyl-1-butanol from the elements carbon (C), hydrogen (H2 ), and oxygen (O2 ). (Use the smallest integer coefficients possible and do not include states. Enter the elements in the order: C, H, then O in the product box.)
Answer:
12C + 14H₂ + O₂ = 2C₆H₁₃OH .
Explanation:
2,3-dimethyl-1-butanol
= CH₃-CH(CH₃)-CH(CH₃)-CH₂OH.
Molecular formula = C₆H₁₃OH .
= C₆H₁₄O
12C + 14H₂ + O₂ = 2C₆H₁₃OH .
Classify this reaction.
C3H6(g) + O2(g) → CO2(g) + H2O(g)
a
Single Replacement
b
Synthesis
c
Double Replacement
d
Combustion
Answer:
d
Combustion
Explanation:
write an ionic equation for the reaction of nitric v acid and solid carbonate
Answer:
[tex]CO3^{2-}[/tex] + [tex]2H3O^{+}[/tex] => [tex]2H2O[/tex] + [tex]CO2[/tex]
Explanation:
Nitric acid reacts with sodium carbonate to form sodium nitrate, carbon dioxide and water.
Sodium carbonate + nitric acid => sodium nitrate + water + carbon dioxide
2HNO3 + Na2O3 => 2NaNO3 + CO2 + H2O
So the net ionic equation is as follows:
[tex]CO3^{2-}[/tex] + [tex]2H3O^{+}[/tex] => [tex]2H2O[/tex] + [tex]CO2[/tex]
The sodium ion and the nitrate ions are not involved in the net equation because they are not changed in the reaction.
Please answer!!! Will give brainliest to best answer!!
1. What is the difference between magma and lava?
2. Under what circumstances do large crystals form from a cooling magma?
3. Under what circumstances do small crystals form from a cooling magma?
4. What happens to the mineral particles in salt water when the water evaporates?
5. Explain how halite forms.
6. Explain how mineral veins form.
Answer:
I can answer 1, lqva is magma outside of the volcano
A vessel of volume 100ml contains 10% of oxygen and 90% of an unknown gas. The gases diffuses in 86 second through a small hole of vessel.
If pure oxygen under similar
conditions and diffuses in 75 second, find the molecular weight of unknown gas?
The molecular weight of unknown gas : 23.46 g/mol
Further explanationGiven
A vessel contains 10% of oxygen and 90% of an unknown gas.
diffuses rate of mixed gas = 86 s
diffuses rate of O₂ = 75 s
Required
the molecular weight of unknown gas (M)
Solution
The molecular weight of mixed gas :(M O₂=32 g/mol)
[tex]\tt 0.1\times 32+0.9\times M=3.2+0.9M[/tex]
Graham's Law :
[tex]\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol[/tex]
Oxygen (O2) and nitrogen (N2) are:_______ a. the major gaseous byproducts of combustion. b. the major gases that make up both troposphere and stratosphere c. the major gases that make up only the troposphere d. the major gases that make up only the stratosphere
Answer:
c. the major gases that make up only the troposphere
Explanation:
Oxygen (O2) and nitrogen (N2) are the major gases that make up only the troposphere because both oxygen and nitrogen are heavy gases which is present at lower height so it comes under the troposphere layer while on the other hand, ozone gas that act as a filter for harmful radiation of the sun is present in the stratosphere which is present next to troposphere layer of atmosphere.
What is the molarity of a 3.0 solution of magnesium chloride prepared with 9.0 molecules of MgCl2 A. 6.0 M B. 3.0 M C. 27.0 M D. 0.33 M PLEASE HELP IM GOING TO CRY SO MUCH IF I FAIL
Answer:
Option B. 3.0 M
Explanation:
From the question given above, the following data were obtained:
Volume of solution = 3.0 L
Mole of MgCl₂ = 9 moles
Molarity =?
Molarity can simply be defined as the mole of solute per unit litre of the solution. Mathematically, it can be expressed as:
Molarity = mole of solute /Volume of solution
With the above formula, we can obtain the molarity of the solution as follow:
Volume of solution = 3.0 L
Mole of MgCl₂ = 9 moles
Molarity =?
Molarity = mole of solute /Volume of solution
Molarity = 9 / 3
Molarity = 3 mol/L = 3.0 M
Thus, the molarity of the solution is 3 M