PLEASE HELPP: 2.11.2 Project: Performance Task: The Parallax Problem (For San Francisco)

The Scenario: You’re looking for a sponsor to pay for you to participate in a sailboat race. Now that you’ve solved the parallax problem, use the same skills you used there to write a proposal that shows that you can win the race.
The Project: Use the information provided in the performance task to estimate your travel costs and to calculate your average speed and the speed of last year’s winner. Use the questions below to help you gather information to write your proposal

3. What is the distance between buoy A and B? (5 points)

4. What are the lengths of the other two triangle legs? (4 points: 2 points each)
Remember what you know about the shape of the Race Course.

5. What is the total length of the race course? (4 points: 3 for calculation, 1 for answer)

Part VIII: Calculate the winner’s speed. (10 points)
1. What was the winner’s speed during last year’s race? (5 points: 3 points for speed. 2 points for conversion to knots).

2. How does the winner’s speed compare with your average speed? How much faster or slower are you? (5 points)

Part IX: Write your proposal. (8 points)

Now it’s time to make your proposal to the sponsor. Your sponsor will have their logo on your boat, so they want to be sure it’s likely to do well. The sponsor also needs to know what the expenses and risks are, so they know how much their investment in you will cost.

1. Complete the table to summarize the results of your study. (4 points)
Category:
Race:
Risk Analysis:
Itemized Travel Cost

Safety hazards

Competitive Analysis:
My time and speed

Last year's winning time and speed


Reward Analysis:
My chances of winning



2. Write a summary paragraph explaining why the sponsor should accept your proposal. (4 points)

The linear equation from the given table is expressed as:

y =  -1500x + 8350

The general form for the equation of a line in slope intercept form is:

y = mx + c

where:

m is slope

c is y-intercept

The formula for the equation of a line through two coordinates is:

(y - y₁)/(x - x₁) = (y₂ - y₁)/(x₂ - x₁)

We will take the two coordinates (1, 6850) and (2, 5350)

Thus:

(y - 6850)/(x - 1) = (5350 - 6850)/(2 - 1)

(y - 6850)/(x - 1) = -1500

y - 6850 = -1500x + 1500

y = -1500x + 1500 + 6850

y =  -1500x + 8350

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a. There are 15,600 ways to select a president, a vice president, and a secretary from a class of 26 members.

b. There are 14,950 ways to form a 4-person committee from a class of 26 members.

a. To select a president, a vice president, and a secretary from a class of 26 members, we can use the concept of permutations.

For the president position, we have 26 choices. After selecting the president, we have 25 choices remaining for the vice president position. Finally, for the secretary position, we have 24 choices left.

The total number of ways to select a president, a vice president, and a secretary is obtained by multiplying the number of choices for each position:

Number of ways = 26 * 25 * 24 = 15,600

Therefore, there are 15,600 ways to select a president, a vice president, and a secretary from a class of 26 members.

b. To form a 4-person committee from a class of 26 members, we can use the concept of combinations.

The number of ways to choose a committee of 4 people can be calculated using the formula for combinations:

Number of ways = C(n, r) = n! / (r!(n-r)!)

where n is the total number of members (26 in this case) and r is the number of people in the committee (4 in this case).

Plugging in the values, we have:

Number of ways = C(26, 4) = 26! / (4!(26-4)!)

Calculating this expression, we get:

Number of ways = 26! / (4! * 22!)

Using factorials, we simplify further:

Number of ways = (26 * 25 * 24 * 23) / (4 * 3 * 2 * 1) = 14,950

Therefore, there are 14,950 ways to form a 4-person committee from a class of 26 members.

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The calculated value of x to the nearest degree is 56

From the question, we have the following parameters that can be used in our computation:

The triangle

The value of x can be caluclated using the following cosine rule

So, we have

cos(x) = 5/9

Evaluate the quotient

cos(x) = 0.5556

Take the arc cos of both sides

x = 56

Hence, the value of x to the nearest degree is 56

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The value of 12 remains 12.

The value of X cannot be determined without additional information.

The value of 25° remains 25°.

To find the values of the variables in the given information, we have:

12: This is a given value and does not require calculation. Therefore, the value of 12 remains as it is.

X: Without additional information or an equation to solve, we cannot determine the value of X. It could represent any unknown quantity or variable, and its specific value would depend on the context or problem being solved.

25°: This is an angle measure in degrees. The value of 25° remains as it is.

To summarize:

The value of 12 remains 12.

The value of X cannot be determined without additional information.

The value of 25° remains 25°.

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Answer:

45 inches represent 55 miles on the scale drawing.

Step-by-step explanation:

To solve this proportion, we can set up the following ratio:

9 inches / 11 miles = x inches / 55 miles

We can cross-multiply to solve for x:

9 inches * 55 miles = 11 miles * x inches

495 inches = 11 miles * x inches

Now, we can isolate x by dividing both sides by 11 miles:

495 inches / 11 miles = x inches

Simplifying the expression:

45 inches = x inches

Answer:

Step-by-step explanation:

Let's revisit the equation and the solution using the values x = -4, 0, and 5.

The given equation is: 5 + x - 12 = x - 7

Let's go through the steps again to solve it:

5 + x - 12 = x - 7

Combine like terms:

x - 7 = x - 7

Now, subtract x from both sides:

x - x - 7 = x - x - 7

Simplify:

-7 = -7

The equation simplifies to -7 = -7, which is true.

Now, let's use the values x = -4, 0, and 5 to verify the solution.

For x = -4:

5 + (-4) - 12 = (-4) - 7

-11 = -11

The equation is satisfied for x = -4.

For x = 0:

5 + 0 - 12 = 0 - 7

-7 = -7

The equation is satisfied for x = 0.

For x = 5:

5 + 5 - 12 = 5 - 7

-2 = -2

The equation is satisfied for x = 5.

Therefore, the solution x = 0 is correct, and it satisfies the equation for the given values. My earlier statement that x = -4 and x = 5 do not satisfy the equation was incorrect. I apologize for the confusion caused.

Answer:

The description provides the clues for each digit in a 6-digit number. Let's break it down:

1. Highest place value and lowest place value has a number equals to the number of days in a week: There are 7 days in a week, so the first and last digits are 7.

2. Hundreds place is equal to half a dozen: Half a dozen is 6, so the third digit from the right (hundreds place) is 6.

3. Tens place is the number of sides of a triangle: A triangle has 3 sides, so the second digit from the right (tens place) is 3.

4. Thousands place is equal to the number of poles of earth: Earth has two poles, so the second digit from the left (thousands place) is 2.

5. Ten thousands place is equal to result of subtracting any number from itself: Subtracting any number from itself yields 0, so the third digit from the left (ten thousands place) is 0.

Putting it all together, the 6-digit number would be: 702,637.

Answer:

arc LKF = 208°

Step-by-step explanation:

the angle FLX between the tangent and the secant is half the measure of the intercepted arc LKF , then intercepted arc is twice angle FLX , so

arc LKF = 2 × 104° = 208°

The equivalent ratio of the corresponding sides and the triangle proportionality theorem indicates that the similar triangles are;

1. ΔAJK ~ ΔSWY according to the SAS similarity postulate

2. ΔLMN ~ ΔLPQ according to the AA similarity postulate

3. ΔPQN ~ ΔLMN

LM = 12, QP = 8

4. ΔLMK~ΔLNJ

NL = 21, ML = 14

Similar triangles are triangles that have the same shape but may have different sizes.

1. The ratio of corresponding sides between the two triangles circumscribing the congruent included angle are;

24/16 = 3/2

18/12 = 3/2

The ratio of each of the two sides in the triangle ΔAJK to the corresponding sides in the triangle ΔSWY are equivalent and the included angle, therefore, the triangles ΔAJK and ΔSWY are similar according to the SAS similarity rule.

2. The ratio of the corresponding sides in each of the triangles are;

MN/LN = 8/10 = 4/5

PQ/LQ = 12/(10 + 5) = 12/15 = 4/5

The triangle proportionality theorem indicates that the side MN and PQ are parallel, therefore, the angles ∠LMN ≅ ∠LPQ and ∠LNM ≅ ∠LQP, which indicates that the triangles ΔLMN and ΔLPQ are similar according to the Angle-Angle AA similarity rule

3. The alternate interior angles theorem indicates;

Angles ∠PQN ≅ ∠LMN and ∠MLN ≅ ∠NPQ, therefore;

ΔPQN ~ ΔLMN by the AA similarity postulate

LM/QP = (x + 3)/(x - 1) = 18/12

12·x + 36 = 18·x - 18

18·x - 12·x = 36 + 18 = 54

6·x = 54

x = 54/6 = 9

LM = 9 + 3 = 12

QP = x - 1

QP = 9 - 1 = 8

4. The similar triangles are; ΔLMK and ΔLNJ

ΔLMK ~ ΔLNJ by AA similarity postulate

ML/NL = (6·x + 2)/(6·x + 2 + (x + 5)) = (6·x + 2)/((7·x + 7)

ML/NL = LK/LJ = (24 - 8)/24

(24 - 8)/24 = (6·x + 2)/((7·x + 7)

16/24 = (6·x + 2)/(7·x + 7)

16 × (7·x + 7) = 24 × (6·x + 2)

112·x + 112 = 144·x + 48

144·x - 112·x = 32·x = 112 - 48 = 64

x = 64/32 = 2

ML = 6 × 2 + 2 = 14

NL = 7 × 2 + 7 = 21

MN = 2 + 5 = 7

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The periods of daylight and darkness on that day are approximately:

Daylight: 202.5°

Darkness: 157.5°

Hence, the correct option is:

C. 202°3°, 157°30'

To calculate the periods of daylight and darkness on a certain day, we need to find the difference between the times of sunrise and sunset.

Sunrise time: 5.30 am

Sunset time: 7.00 pm

To find the period of daylight, we subtract the sunrise time from the sunset time:

Daylight = Sunset time - Sunrise time

First, let's convert the times to a 24-hour format for easier calculation:

Sunrise time: 5.30 am = 05:30

Sunset time: 7.00 pm = 19:00

Now, let's calculate the period of daylight:

Daylight = 19:00 - 05:30

To subtract the times, we need to convert them to minutes:

Daylight = (19 * 60 + 00) - (05 * 60 + 30)

Daylight = (1140 + 00) - (330)

Daylight = 1140 - 330

Daylight = 810 minutes

To convert the period of daylight back to degrees, we can use the fact that in 24 hours (1440 minutes), the Earth completes a full rotation of 360 degrees.

Daylight (in degrees) = (Daylight / 1440) * 360

Daylight (in degrees) = (810 / 1440) * 360

Daylight (in degrees) ≈ 202.5 degrees

To find the period of darkness, we subtract the period of daylight from a full circle of 360 degrees:

Darkness = 360 - Daylight

Darkness = 360 - 202.5

Darkness ≈ 157.5 degrees

Therefore, the periods of daylight and darkness on that day are approximately:

Daylight: 202.5°

Darkness: 157.5°

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The correct answer choice is: A. The system has exactly one solution. The solution is (11, 7).

The correct answer choice is: A. all three countries had the same population of 7 thousand in the year 2011.

Based on the information provided above, the population (y) in the year (x) of the countries listed are approximated by the following system of equations:

-x + 20y = 129

-x + 10y = 59

y = 7

where:

By solving the system of equations simultaneously, we have the following solution:

-x + 20(7) = 129

x = 140 - 129

x = 11

-x + 10(7) = 59

x = 70 - 59

x = 11

Therefore, the system of equations has only one solution (11, 7).

For the year when the population are all the same for three countries, we have:

x = 2010 + (11 - 10)

x = 2011

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Answer:

[tex]\textsf{C)} \quad -\dfrac{3}{2}[/tex]

Step-by-step explanation:

To find the average rate of change of a function over an interval, we can use the formula:

[tex]\boxed{\begin{minipage}{6.3 cm}\underline{Average rate of change of function $f(x)$}\\\\$\dfrac{f(b)-f(a)}{b-a}$\\\\over the interval $a \leq x \leq b$\\\end{minipage}}[/tex]

In this case, the interval is [4, 8], so:

From inspection of the given graph:

Substitute the values into the formula to calculate the average rate of change:

[tex]\begin{aligned}\text{Average rate of change}&=\dfrac{h(8)-h(4)}{8-4}\\\\&=\dfrac{3-9}{8-4}\\\\&=\dfrac{-6}{4}\\\\&=-\dfrac{3}{2}\end{aligned}[/tex]

Therefore, the average rate of change of h(x) over the interval [4, 8] is -3/2.

a) Option a) 9 - 1/2 is equal to 17/2.

b) Option b) 27 - 2/3 is equal to 79/3.

a) The expression 9 - 1/2 can be simplified by finding a common denominator for the terms. The common denominator for 9 and 1/2 is 2.

Multiplying 9 by 2/2, we get:

9 * (2/2) = 18/2

So, the expression 9 - 1/2 can be simplified to:

18/2 - 1/2 = 17/2

Therefore, option a) 9 - 1/2 is equal to 17/2.

b) The expression 27 - 2/3 can be simplified in a similar manner by finding a common denominator for the terms. The common denominator for 27 and 2/3 is 3.

Multiplying 27 by 3/3, we get:

27 * (3/3) = 81/3

So, the expression 27 - 2/3 can be simplified to:

81/3 - 2/3 = 79/3

Therefore, option b) 27 - 2/3 is equal to 79/3.

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Part 1- The lower class boundary for the first class is 100.

Part 2- Approximately 75% of students take exactly two courses.

Part 1:

To find the lower class boundary for the first class, we need to consider the given class intervals. The lower class boundary is the smallest value within each class interval.

Given the class intervals:

100 - 104

105 - 109

110 - 114

115 - 119

120 - 124

125 - 129

130 - 134

The lower class boundary for the first class interval (100 - 104) would be 100.

So, the lower class boundary for the first class is 100.

Part 2:

To determine the percentage of students who take exactly two courses, we need to calculate the relative frequency for that particular category.

Given the data:

of Courses Frequency Relative Frequency Cumulative Frequency

1 23 0.4423 23

2 - 39

3 13 0.25 -

We can see that the cumulative frequency for the second class (2 courses) is 39. To find the relative frequency for this class, we need to divide the frequency by the total number of students surveyed, which is 52.

Relative Frequency = Frequency / Total Number of Students

Relative Frequency for 2 courses = 39 / 52 ≈ 0.75 (rounded to 4 decimal places)

To convert this to a percentage, we multiply the relative frequency by 100.

Percentage of students taking exactly two courses = 0.75 * 100 ≈ 75%

Therefore, approximately 75% of students take exactly two courses.

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Question

Part 1.

Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.

Lengths (mm) Frequency

100 - 104 1

105 - 109 16

110 - 114 71

115 - 119 108

120 - 124 83

125 - 129 18

130 - 134 3

What is the lower class boundary for the first class?

class boundary =

Part 2

In a student survey, fifty-two part-time students were asked how many courses they were taking this term. The (incomplete) results are shown below:

Please round your answer to 4 decimal places for the Relative Frequency if possible.

# of Courses Frequency Relative Frequency Cumulative Frequency

1 23 0.4423 23

2   39

3 13 0.25

What percent of students take exactly two courses? %

The conditions that prove that the triangles ΔABC and ΔXYZ are similar, ΔABC ~ ΔXYZ, based on the order of the lettering are;

BA/YX = BC/YZ = AC/XZ

AC/XZ = BA/YX, ∠A ≅ ∠C

Similar triangles are triangles that have the same shape (the same two or all three interior angles in each triangle) but in which may have different sizes.

Triangles are similar if they equivalent ratio for their sides and and if the angles in each triangle are congruent to the angles in the other triangle

Therefore, the conditions that indicates that two triangles are that one triangle is a scaled image of the other triangle, therefore, the ratio of the corresponding sides of the triangles are equivalent, which indicates;

ΔABC is similar to ΔXYZ if we get;

A condition that indicates that two triangle are similar is the Side Angle Side, SAS, similarity postulate, which states that two triangles are congruent if the ratio of two corresponding sides are equivalent and the angle between the two sides in the two triangles are congruent, therefore;

ΔABC is similar to ΔXYZ if we get;

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The measure of the indicated arc angle is 134 degrees.

The angle subtended by the arc at the centre of the circle is the angle of the arc.

Therefore, the central angle of an arc is the angle at the centre of the circle between the two radii subtended by the arc.

Hence, the central angle is also known as the arc's angular distance.

Therefore, the measure of an arc is the measure of its central angle.

Hence, the measure of the indicated arc is 134 degrees.

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Step-by-step explanation:

a. f(g(0)) = f(0^2 - 2) = f(-2) = -2 + 3 = 1

b. g(f(0)) = g(0+3) = g(3) = 3^2 - 2 = 7

c. f(g(x)) = g(x) + 3 = x^2 - 2 + 3 = x^2 + 1

d. g(f(x)) = f(x)^2 - 2 = (x+3)^2 - 2 = x^2 + 6x + 7

e. f(f(-2)) = f(-2+3) = f(1) = 1+3 = 4

f. g(g(4)) = g(4^2 - 2) = g(14) = 14^2 - 2 = 194

g. f(f(x)) = f(x+3) = (x+3)+3 = x+6

h. g(g(x)) = g(x^2 - 2) = (x^2 - 2)^2 -2 = x^4 - 4x^2 + 2

The limit of the expression lim (x² - √x⁴ + 3x²) as x approaches any value is indeterminate (∞ - ∞), except when x approaches zero, where the limit is 0.

To find the limit of the expression lim (x² - √x⁴ + 3x²) as x approaches a certain value, we can simplify the expression and evaluate the limit.

First, let's simplify the expression:

lim (x² - √x⁴ + 3x²)

= lim (4x² - x² - √x⁴)

= lim (3x² - √x⁴)

Now, let's consider the behavior of the expression as x approaches a value.

As x approaches any finite value, the term 3x² will approach a finite value.

For the term √x⁴, as x approaches a finite value, the square root of x⁴ will approach the absolute value of x².

Therefore, the limit becomes:

lim (3x² - √x⁴) = lim (3x² - |x²|)

Next, let's consider the different cases as x approaches positive infinity, negative infinity, and zero.

1. As x approaches positive infinity, the term 3x² will tend to positive infinity, and |x²| will also tend to positive infinity. Thus, the expression becomes:

lim (3x² - |x²|) = lim (∞ - ∞)

In this case, the limit is indeterminate (∞ - ∞).

2. As x approaches negative infinity, the term 3x² will tend to positive infinity, and |x²| will also tend to positive infinity. Thus, the expression becomes:

lim (3x² - |x²|) = lim (∞ - ∞)

Again, in this case, the limit is indeterminate (∞ - ∞).

3. As x approaches zero, the term 3x² will tend to zero, and |x²| will also tend to zero. Thus, the expression becomes:

lim (3x² - |x²|) = lim (0 - 0) = 0

Therefore, the limit of the expression lim (x² - √x⁴ + 3x²) as x approaches any value is indeterminate (∞ - ∞), except when x approaches zero, where the limit is 0.

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The expression 3x² + 6x + 4x + 8 is factorized as (x + 2)(3x + 4).

To factorize the algebraic expression 3x² + 6x + 4x + 8, you can follow these three steps:

Step 1: Grouping

Group the terms in pairs based on their common factors:

(3x² + 6x) + (4x + 8)

Step 2: Factor out common factors

Factor out the greatest common factor from each group of terms:

3x(x + 2) + 4(x + 2)

Now, we have a common factor of (x + 2) in both terms.

Step 3: Combine the factored terms

Combine the factored terms using the common factor:

(x + 2)(3x + 4)

The expression 3x² + 6x + 4x + 8 is factorized as (x + 2)(3x + 4).

In this process, we grouped the terms with similar variables and then factored out the greatest common factor from each group. Finally, we combined the factored terms using the common factor to obtain the fully factorized expression.

It's important to note that factoring algebraic expressions requires practice and familiarity with common factoring techniques. In some cases, you may encounter expressions that require additional methods such as factoring by grouping, using special factoring formulas, or applying quadratic factoring techniques.

By following these three steps, you can factorize the given expression by identifying common factors and combining terms accordingly.

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The cubic function with the desired properties is:

f(x) = (-3/4)x³ - (9/4)x² - (113/4)x + 63/4

To find the values of a, b, c, and d, we can use the given information about the relative maximum, relative minimum, and point of inflection.

Relative Maximum:

The point (-7, 163) is a relative maximum. At this point, the derivative of the cubic function is equal to zero. Taking the derivative of the cubic function, we have:

f'(x) = 3ax² + 2bx + c

Setting x = -7 and f'(-7) = 0, we get:

49a - 14b + c = 0

Relative Minimum:

The point (5, -125) is a relative minimum. At this point, the derivative of the cubic function is equal to zero. Taking the derivative of the cubic function, we have:

f'(x) = 3ax² + 2bx + c

Setting x = 5 and f'(5) = 0, we get:

75a + 10b + c = 0

Point of Inflection:

The point (-1, 19) is a point of inflection. At this point, the second derivative of the cubic function changes sign. Taking the second derivative of the cubic function, we have:

f''(x) = 6ax + 2b

Setting x = -1, we get:

-6a + 2b = 0

Solving the system of equations formed by the above three equations, we can find the values of a, b, c, and d.

49a - 14b + c = 0

75a + 10b + c = 0

-6a + 2b = 0

Solving these equations, we find:

a = -3/4

b = -9/4

c = -113/4

d = 63/4

Therefore, the cubic function with the desired properties is:

f(x) = (-3/4)x³ - (9/4)x² - (113/4)x + 63/4

The angular velocity of the object is 31.25 radians/second.

Angular velocity is defined as the change in angular displacement per unit of time. In this case, the object rotates a total of 25 radians in 0.8 seconds. Therefore, the angular velocity can be calculated by dividing the total angular displacement by the time taken.

Angular velocity (ω) = Total angular displacement / Time taken

Given that the object rotates 25 radians and the time taken is 0.8 seconds, we can substitute these values into the formula:

ω = 25 radians / 0.8 seconds

Simplifying the equation gives:

ω = 31.25 radians/second

So, the angular velocity of the object is 31.25 radians/second.

Angular velocity measures how fast an object is rotating and is typically expressed in radians per second. It represents the rate at which the object's angular position changes with respect to time.

In this case, the object completes a rotation of 25 radians in 0.8 seconds, resulting in an angular velocity of 31.25 radians per second. This means that the object rotates at a rate of 31.25 radians for every second of time.

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Note the translated question is:

An object that is rotated moves 25 radians in 0.8 seconds. what is the angular velocity of said object?

Answer:

Step-by-step explanation:

The correct answer is A. A rectangle the same size as the base.

When a rectangular pyramid is sliced parallel to the base, the resulting cross-section is a rectangle that is the same size as the base. The parallel slicing ensures that the cross-section maintains the same dimensions as the base of the pyramid. Therefore, option A, a rectangle the same size as the base, represents the cross-section.

Answer:

59

Step-by-step explanation:

6 plus 4 equals 8 plus 9

(a) The average cost in 2010 is $2088.82.

(b) A graph of the function g for the period 2006 to 2015 is: D. graph D.

(c) Assuming that the graph remains accurate, its shape suggest that: B. the average cost increases at a slower rate as time goes on.

Based on the information provided, we can logically deduce that the average annual cost (in dollars) for health insurance in this country can be approximately represented by the following function:

g(x) = -1736.7 + 1661.4Inx

where:

x = 6 corresponds to the year 2006.

For the year 2011, the average cost (in dollars) is given by;

x = (2010 - 2006) + 6

x = 4 + 6

x = 10 years.

Next, we would substitute 10 for x in the function:

g(10) = -1736.7 + 1661.4In(10)

g(10) = $2088.82

Part b.

In order to plot the graph of this function, we would make use of an online graphing tool. Additionally, the years would be plotted on the x-axis while the average annual cost would be plotted on the x-axis of the cartesian coordinate as shown below.

Part c.

Assuming the graph remains accurate, the shape of the graph suggest that the average cost of health insurance increases at a slower rate as time goes on.

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Answer:

(fg)(x)= (x²+6)(x²-x+9)

multiply the terms:

(fg)(x)= x²(x²-x+9) +6(x²-x+9)

add the like terms:

(fg)(x)= (x⁴-x³+9x²)+(6x²-6x+54)

and you get your final answer:

(fg)(x)= x⁴-x³+15x²-6x+54

1/3 of a full rotation: (-0.5, √3/2)

1/2 of a full rotation: (-1, 0)

2/3 of a full rotation: (0.5, -√3/2)

These are the coordinates of point P after the corresponding rotations around the unit circle's center.

To find the coordinates of point P after the unit circle rotates a certain amount counter-clockwise around its center, we can use the properties of the unit circle and the trigonometric functions.

1/3 of a full rotation:

A full rotation in the unit circle corresponds to 360 degrees or 2π radians. Therefore, 1/3 of a full rotation is equal to (1/3) * 360 degrees or (1/3) * 2π radians.

When the unit circle rotates 1/3 of a full rotation, point P will end up at an angle of (1/3) * 2π radians or 120 degrees from the positive x-axis.

In the unit circle, the x-coordinate of a point on the circle represents the cosine of the angle, and the y-coordinate represents the sine of the angle.

At an angle of 120 degrees or (1/3) * 2π radians, the cosine is -0.5 and the sine is √3/2.

Therefore, the coordinates of point P after rotating 1/3 of a full rotation are (-0.5, √3/2).

1/2 of a full rotation:

Similarly, 1/2 of a full rotation is equal to (1/2) * 360 degrees or (1/2) * 2π radians.

When the unit circle rotates 1/2 of a full rotation, point P will end up at an angle of (1/2) * 2π radians or 180 degrees from the positive x-axis.

At an angle of 180 degrees or (1/2) * 2π radians, the cosine is -1 and the sine is 0.

Therefore, the coordinates of point P after rotating 1/2 of a full rotation are (-1, 0).

2/3 of a full rotation:

Again, 2/3 of a full rotation is equal to (2/3) * 360 degrees or (2/3) * 2π radians.

When the unit circle rotates 2/3 of a full rotation, point P will end up at an angle of (2/3) * 2π radians or 240 degrees from the positive x-axis.

At an angle of 240 degrees or (2/3) * 2π radians, the cosine is 0.5 and the sine is -√3/2.

Therefore, the coordinates of point P after rotating 2/3 of a full rotation are (0.5, -√3/2).

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To show that ABC ≅ AXYZ by SAS, we would need to establish that angle BAC ≅ angle XYZ.

To show that triangles ABC and AXYZ are congruent by the Side-Angle-Side (SAS) criterion, we need to establish that two corresponding sides and the included angle are congruent.

Given AB ≅ XY and BC ≅ YZ, we already have two corresponding sides congruent.

To complete the congruence by the SAS criterion, we need to establish that the included angles are congruent. In this case, the included angle is angle BAC (or angle XYZ).

Therefore, to show that ABC ≅ AXYZ by SAS, we would need to establish that angle BAC ≅ angle XYZ.

None of the answer choices directly addresses the congruence of the angles. So, none of the given options (A, B, C, D) are sufficient to show the congruence of the triangles by SAS.

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Answer:

Step-by-step explanation:

I cannot see the graphs.

The simplified fraction of 350/120 is 35/12

from the question, we have the following parameters that can be used in our computation:

350/120

Divide the zeros

So, we have

350/120 = 35/12

Divide the fractions by 3

This is impossible

Hence, the simplified fraction is 35/12

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Answer: [tex](-\infty, 6) \cup (6, \infty)[/tex]

Step-by-step explanation:

Polynomials are continuous for all reals, so we only need to consider the rational part. Since the denominator is undefined at [tex]x=6[/tex], there is a vertical asymptote at [tex]x=6[/tex].