PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP

The first person with the right answer gets to be a brainlest

In the attachment there is a density column where there is colour

Question: tell me why is the red at the bottom of the density column if it is the least dense

Answer:

D) 60 m

Explanation:

We can use the constant acceleration equation that contains displacement, initial velocity, acceleration, and time. We want to solve for the time that the ball was in the air first.

Let's use this equation in terms of the y-direction.

The vertical displacement will be 0 meters since the ball will be on the floor. The initial vertical velocity is 10 m/s, the vertical acceleration is g = 10 m/s², and we are going to solve for time t.

Let's set the upwards direction to be positive and the downwards direction to be negative. We must use -g to be consistent with our other values.

Plug the known values into the equation.

Simplify the equation.

Factor the equation.

Solve for t by setting both factors to 0.

We get t = 0, t = 2. We must use t = 2 seconds because it is the only value for t that makes sense in the problem.

Now that we have the time that the ball was in the air, we can use the same constant acceleration equation to determine the horizontal displacement of the tennis ball. We will use this equation in terms of the x-direction:

Plug the known values into the equation.

We can eliminate the right side of the equation since anything multiplied by 0 outputs 0.

The horizontal displacement of the ball is 60 meters. Therefore, the answer is D) 60 m.

Answer:

0.06 m/s²

Explanation:

force= mass × acceleration

acceleration= force / mass

acceleration= 15/250= 0.06 m/s²

hope it helps! please mark me brainliest..

Have a good day ahead

The acceleration of the ball in the direction of the kick will be  600 m/[tex]s^{2}[/tex]

We have a Ball.

We have to determine the acceleration of the ball in the direction of the kick.

The product of mass and acceleration of a body is called force.

Force = Mass x Acceleration.

According to the question, we have -

Mass = 250 g = 0.025 Kg

Force = 15 N

Then, the acceleration of the ball in the direction of the kick will be -

F = m x a

a = F / m

a = 15 / 0.025 = 600 m/[tex]s^{2}[/tex]

Hence, the acceleration of the ball in the direction of the kick will be  600 m/[tex]s^{2}[/tex]

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Answer:

Average speed = 46.67 m/s

Explanation:

Given that the time taken in covering first 1000 m = 25 seconds.

The time taken in covering next 2.5 km = 50 seconds.

Total distance covered = 1000 m + 2500 m = 3500 m

Total time taken = 25+50=75 seconds

Average speed = Total distance covered / total time taken

= 3500/75 = 46.67 m/s

Answer:

a) [tex] v_{U-235} = 2.68 \cdot 10^{5} m/s [/tex]

[tex]v_{He-4} = -1.57 \cdot 10^{7} m/s[/tex]  

b) [tex] E_{He-4} = 8.23 \cdot 10^{-13} J [/tex]

[tex] E_{U-235} = 1.41 \cdot 10^{-14} J [/tex]

Explanation:

Searching the missed information we have:                                        

E: is the energy emitted in the plutonium decay = 8.40x10⁻¹³ J

m(⁴He): is the mass of the helium nucleus = 6.68x10⁻²⁷ kg  

m(²³⁵U): is the mass of the helium U-235 nucleus = 3.92x10⁻²⁵ kg            

a) We can find the velocities of the two nuclei by conservation of linear momentum and kinetic energy:

Linear momentum:

[tex] p_{i} = p_{f} [/tex]

[tex] m_{Pu-239}v_{Pu-239} = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} [/tex]

Since the plutonium nucleus is originally at rest, [tex]v_{Pu-239} = 0[/tex]:

[tex] 0 = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} [/tex]  

[tex] v_{He-4} = -\frac{m_{U-235}v_{U-235}}{m_{He-4}} [/tex]    (1)

Kinetic Energy:

[tex] E_{Pu-239} = \frac{1}{2}m_{He-4}v_{He-4}^{2} + \frac{1}{2}m_{U-235}v_{U-235}^{2} [/tex]

[tex] 2*8.40 \cdot 10^{-13} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} [/tex]    

[tex] 1.68\cdot 10^{-12} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} [/tex]   (2)    

By entering equation (1) into (2) we have:

[tex] 1.68\cdot 10^{-12} J = m_{He-4}(-\frac{m_{U-235}v_{U-235}}{m_{He-4}})^{2} + m_{U-235}v_{U-235}^{2} [/tex]  

[tex] 1.68\cdot 10^{-12} J = 6.68 \cdot 10^{-27} kg*(-\frac{3.92 \cdot 10^{-25} kg*v_{U-235}}{6.68 \cdot 10^{-27} kg})^{2} +3.92 \cdot 10^{-25} kg*v_{U-235}^{2} [/tex]  

Solving the above equation for [tex]v_{U-235}[/tex] we have:

[tex] v_{U-235} = 2.68 \cdot 10^{5} m/s [/tex]

And by entering that value into equation (1):

[tex]v_{He-4} = -\frac{3.92 \cdot 10^{-25} kg*2.68 \cdot 10^{5} m/s}{6.68 \cdot 10^{-27} kg} = -1.57 \cdot 10^{7} m/s[/tex]                        

The minus sign means that the helium-4 nucleus is moving in the opposite direction to the uranium-235 nucleus.

b) Now, the kinetic energy of each nucleus is:

For He-4:

[tex]E_{He-4} = \frac{1}{2}m_{He-4}v_{He-4}^{2} = \frac{1}{2} 6.68 \cdot 10^{-27} kg*(-1.57 \cdot 10^{7} m/s)^{2} = 8.23 \cdot 10^{-13} J[/tex]

For U-235:

[tex] E_{U-235} = \frac{1}{2}m_{U-235}v_{U-235}^{2} = \frac{1}{2} 3.92 \cdot 10^{-25} kg*(2.68 \cdot 10^{5} m/s)^{2} = 1.41 \cdot 10^{-14} J [/tex]

I hope it helps you!                                                                                    

Answer:

Lens at a distance = 7.5 cm

Lens at a distance = 6.86 cm  (Approx)

Explanation:

Given:

Object distance u = 12 cm

a) Focal length = 20 cm

b) Focal length = 16 cm

Computation:

a. 1/v = 1/u + 1/f

1/v = 1/20 + 1/12

v = 7.5 cm

Lens at a distance = 7.5 cm

b.  1/v = 1/u + 1/f

1/v = 1/16 + 1/12

v = 6.86 cm  (Approx)

Lens at a distance = 6.86 cm  (Approx)

Answer:

a cold front i think

Explanation:

Answer: D.

Explanation:

Answer:

i think the answer is b

Explanation:

playing sports often require both

Answer:

B. The more potential energy it has.

Explanation:

I majored in Physics

Answer:

Mr. Dececco will not be happy

Explanation:

I'll give you a hint, the answer starts with the number 3. Use the kinematics equation of  [tex]delta\ x =v_{0}t+ \frac{1}{2}at^{2}[/tex]

Answer:

the max is 2,500 or less

Explanation:

because you cant owe anymore

Answer:

theta = 90°

Explanation:

hope it's helpful

Explanation:

A • B = (2i - 3j + k) • (i + j + k)

= (2)(1) + (- 3)(1) + (1)(1)

= 0 = AB cos θ

∴ cos θ = 0 (as A ≠ 0,B ≠ 0)

or θ = 90°

or the vectors A and B are mutually perpendicular.

-TheUnknownScientist

Answer:

I guess that the bottom part that is colored red represents the base of the container and not the actual red liquid.

Always, the densest materials/substances will go to the bottom.

One could see different things if, for example, when one of the elements changes state it becomes more or less dense (an example is the water, which has a solid phase, the ice, less dense than the liquid phase, and you can see that solid water usually floats on liquid water)

But in the text there is nothing about possible changes in temperature or changes in phase, then that option can be discarded.

The only option that makes sense is that the red part at the bottom represents the base of the column.

Answer:

0.40

Explanation:

a) Work done is expressed as

W = Force × distance

Given.

Force = 150N

Distance = 6.85m

Workdone = 150×6.85

Work done = 1027.5Joules

b) According to Newton's second law

\sumFx = ma

Fm - Ff = ma

Since speed is constant, acceleration us zero

Fm - Ff = 0

Fm = Ff = nR

Fm is the moving force

Ff is the frictional force

n is the coefficient of kinetic energy between the crate and rough surface

R is the reaction

From the formula;

Fm = nR

n = Fm/R

n = Fm/mg

n = 150/38(9.8)

n = 150/372.4

n = 0.40

Hence the coefficient of kinetic energy between the crate and rough surface is 0.40

Explanation:

Length of a string, l = 0.626 m

A tennis ball revolves in a horizontal circle above his head at a rate of 4.50 rev/s.

(a) The centripetal acceleration of the tennis ball is given by :

[tex]a=\omega^2r\\\\a=(4.5\times 2\pi)^2\times 0.626\\\\=500.44\ m/s^2[/tex]

(b) When r = 0.626 m and ω = 4.50 rev/s

Speed,

[tex]v=r\omega\\\\=0.626\times 4.50 \times 2\pi\\\\=17.69\ m/s[/tex]

When r = 1 m and ω = 4 rev/s

Speed,

[tex]v=r\omega\\\\=1\times 4 \times 2\pi\\\\=25.13\ m/s[/tex]

Speed is more in second case when child now increases the length of the string to 1.00m but has to decrease the rate of rotation to 4.00 rev/s.

(c) [tex]a=\omega^2r\\\\a=(4\times 2\pi)^2\times 1\\\\=631.65\ m/s^2[/tex]

Hence, this is the required solution.

Answer:

A. 9.8 m/s²

B. Zero

C. 6.125 m/s

D. 1.91 m

Explanation:

From the question given above, the following data were obtained:

Time (T) spent in the air = 1.25 s

A. Determination of the acceleration of the ball.

From the description given in question above, the motion of the tennis ball is motion under gravity. Hence, the ball will experience an acceleration due to gravity of 9.8 m/s²

B. Determination of the velocity at maximum height.

Maximum height is the greatest point reached by the tennis ball above the ground. At maximum height, the velocity of the tennis ball is zero since it has no further force to propel it upward.

C. Determination of the initial velocity of the ball.

We'll begin by calculating the time taken to reach the maximum height. This can be obtained as follow:

Time (T) spent in the air = 1.25 s

Time (t) to reach the maximum height =?

T = 2t

1.25 = 2t

Divide both side by 2

t = 1.25 / 2

t = 0.625 s

Finally, we shall determine the initial velocity of the ball. This can be obtained as follow:

Time (t) to reach the maximum height = 0.625 s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) =?

v = u – gt (since the ball is going against gravity)

0 = u – (9.8 × 0.625)

0 = u – 6.125

Collect like terms

0 + 6.125 = u

u = 6.125 m/s

Thus, the initial velocity of the ball is 6.125 m/s

D. Determination of the maximum height.

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) = 6.125 m/s

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 6.125² – (2 × 9.8 × h)

0 = 37.52 – 19.6h

Collect like terms

0 – 37.52 = – 19.6h

– 37.52 = – 19.6h

Divide both side by – 19.6

h = – 37.52 / – 19.6

h = 1.91 m

Thus, the maximum height reached by the ball is 1.91 m

Answer:

it depends on wether the + and - are facing eachother

or away from eachother

Explanation:

Answer:

Yes, they are correct, you need to include all parts of the question, don't just copy and paste the words. But in the diagram that was supposed to be there, the magnets' north poles are facing each other. Therefore they would push away from each other if they were to get any closer.  So, the magnetic potential energy would decrease due to their movement away from each other. So your answer is (C. It will decrease.

Explanation:

Answer:

640.5

Explanation: i got it right on acellus

The wavelength of the light is 320.23 nm.

Light passing through a double slit with separation is given as

d = 3.33 × 10⁻⁵ m.

Line number m = 1

Angle θ = 0.551°

   The distance between two sound waves i.e., crest and trough is called the wavelength.

Human eye can detect the wavelength of about 380 nm to 700 nm.

To find the wavelength, here we use the formula as,

             sin θ = Line number × λ ÷ ( distance )

By substituting all the values,

            Sin ( 0.551 ) = 1 × λ ÷ ( 3.33 × 10⁻⁵)

Rearranging the equation,

             λ= (Sin ( 0.551 ) ×  ( 3.33 × 10⁻⁵) ) ÷ (1)

              λ = 320.23  nm.

Thus, wavelength λ of the light is 320.23 nm.

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Answer:

Option C. BC shows zero acceleration, and CD shows negative acceleration.

Explanation:

To successfully answer the question given above, we must know the meaning of zero acceleration and negative acceleration respectively.

Zero acceleration simply means the object is not accelerating. This implies that velocity of the object is constant (i.e unchanged) with time.

Negative acceleration simply means the object is decelerating i.e coming to rest.

Now, let us answer the question given above.

From the question given above, the following data were obtained:

1. AB indicates that the particle is accelerating because the velocity increased from A to B with time.

2. BC indicates zero acceleration because the velocity of the Particle is constant (i.e unchanged) with time.

3. CD indicates that the object is coming to rest i.e decelerating (negative acceleration) because the velocity of the object decreased from C to D with time.

From the above illustrations, we can see that only option C gives the correct answer to the question.

Answer:

Option C. BC shows zero acceleration, and CD shows negative acceleration.

Explanation:

Complete question is;

The cars in a soapbox derby have no engines; they simply coast downhill. Which of the following design criteria is best from a competitive point of view?

The car's wheels should;

A. have large moments of inertia

B. be massive

C. be hoop-like wheels rather than solid disks

D. have small moments of inertia

Answer:

D. The car's wheels should have small moments of inertia

Explanation:

They are simply cast downhill due to no engine and thus the solid wheels will have very small moments of inertia and will therefore accelerate at a faster rate.

Looking at the options, the correct one that corresponds to the description I just made is Option D.

The car's wheels should have small moments of inertia.

This is defined as the resistance of any physical object to a change in its velocity.

We told they were cast downhill due to no engine and the solid wheels having very small moments of inertia causing increase in acceleration depicts option D which was why it was chosen.

Read more about Inertia here https://brainly.com/question/1140505

Answer:

the average reaction time is 0.25 seconds.

Answer:  C) 48 N forward

===================================================

Explanation:

Subtract the two forces, since they are working opposite one another.

79-31 = 48

The net force is 48 newtons forward. The truck is moving forward since the engine's force (79 N) is larger than the force of friction (31 N).

The force of friction cannot exceed the engine's force because friction only slows down an object, and does not push the object backward. In other words, if the object was stationary, then the ground isn't pushing the object backwards assuming you're on a level flat ground.

Answer:

Explanation:

Maybe start by trying to draw out some transverse waves, longitudinal waves, stationary waves etc. From there you could explain things about each type. For example, particles oscillate in the direction of energy transfer in longitudinal waves or you could include that all electromagnetic waves are examples of transverse waves. Hope this helps you get started :)

Waves are a form of energy transfer through matter or space. Waves can be characters using their amplitude, frequency, wavelength, energy etc.

A wave can be defined as the energy transfer or disturbances in air or matter. Sound and light are two types of waves.

There are broadly two types of waves namely longitudinal waves which vibration parallel  to the direction of the wave and transverse wave vibrating perpendicular to the direction of wave.

A wave is associated with an amplitude. It is the maximum distance that its molecules are displaced or it is the measure of intensity.

Frequency of a wave is the number crests or troughs passing per unit time. Wavelength is the distance between two consecutive crests or throughs.

Each wave is associated with certain amount of energy which is directly proportional to its frequency. High energy wave can easily penetrate through a body.

Hence, by the terms such as amplitude, frequency, wavelength and energy a wave can be characterized.

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Answer:

beta decay

Explanation:

the decay above is known as beta decay because give electron after it decay.

Answer: It’s definitely “Beta” friend!

Answer: D. 40

Explanation:

Power = Force * Velocity

Force = 600N

Power needs to be converted to Watts:

= 24 * 1,000

= 24,000 W

24,000 = 600 * Velocity

Velocity = 24,000/600

= 40 m/s

Answer:

B. The two sleds will move to the right.

Explanation:

I majored in physics

Answer:

b

Explanation:

Answer:

The ratio of the time period of the proton to the electron is 1835.16.

Explanation:

Given that,

Two particles, an electron and a proton, move in a circular path in a uniform magnetic field of intensity B=1.23 T

We need to find the ratio between the time period of the proton Tp to the electron Te.

The time period in magnetic field is given by :

[tex]T=\dfrac{2\pi m}{qB}[/tex]

For proton, time period is :

[tex]T_P=\dfrac{2\pi m_P}{q_pB}\ ....(1)[/tex]

For an electron, the time period is :

[tex]T_e=\dfrac{2\pi m_e}{q_eB}\ ....(2)[/tex]

From equation (1) and (2) :

[tex]\dfrac{T_p}{T_e}=\dfrac{\dfrac{2\pi m_p}{q_pB}}{\dfrac{2\pi m_e}{q_eB}}\\\\As\ q_e=q_p\\\\\dfrac{T_p}{T_e}=\dfrac{m_p}{m_e}\\\\=\dfrac{1.67\times 10^{-27}}{9.1\times 10^{-31}}\\\\=1835.16[/tex]

So, the ratio of the time period of the proton to the electron is 1835.16.

Answer:

That isnt a question so no one will know the answer to what you are talking about. I suggest adding a sceenshot or picture of the question.

Answer:

The best example would be a pendulum inside a sealed empty room.

Explanation: