optimaization methods
Solve using Simplex Method
Maximize Z = 5x1 + 7x2
Subject to
x1 + x2 ≤ 4
3x1 – 8x2 ≤ 24
10x1 + 7x2 ≤ 35
and x1 ≥ 0, x2 ≥ 0

Answers

Answer 1

The given optimization problem is Maximize Z = 5x1 + 7x2Subject tox1 + x2 ≤ 4  …(1)3x1 – 8x2 ≤ 24 …(2)10x1 + 7x2 ≤ 35        …(3)x1 ≥ 0, x2 ≥ 0

As the optimization problem contains two variables x1 and x2, it can be solved using graphical method, however, it is a bit difficult to draw a graph for three constraints, so we will use the Simplex Method to solve it.

The standard form of the given optimization problem is: Maximize Z = 5x1 + 7x2 + 0s1 + 0s2 + 0s3Subject tox1 + x2 + s1 = 43x1 – 8x2 + s2 = 2410x1 + 7x2 + s3 = 35and x1, x2, s1, s2, s3 ≥ 0Applying the Simplex Method, Step

1: Formulating the initial table: For the initial table, we write down the coefficients of the variables in the objective function Z and constraints equation in tabular form as follows:

x1     x2     s1     s2     s3     RHSx1                          1       1        1      0       0       4x2                          3       -8      0      1       0       24s1                          0       0        0      0       0       0s2                          10     7       0      0       1       35Zj                          0       0        0      0       0       0Cj - Zj                5       7        0      0       0       0The last row of the table shows that Zj - Cj values are 5, 7, 0, 0, and 0 respectively, which means we can improve the objective function by increasing x1 or x2. As x2 has a higher contribution to the objective function, we choose x2 as the entering variable and s2 as the leaving variable to increase x2 in the current solution. Step 2:

Performing the pivot operation: To perform the pivot operation, we need to select a row containing the entering variable x2 and divide each element of that row by the pivot element (the element corresponding to x2 and s2 intersection).

After dividing, we obtain 1 as the pivot element as shown below:  x1       x2        s1          s2          s3         RHSx1                            1/8   -3/8     0          1/8        0          3s2                            5/8     7/8     0         -1/8       0         3Zj                            35/8  7/8       0        -5/8        0        105/8Cj - Zj                    25/8  35/8     0         5/8          0        0.

The new pivot row shows that Zj - Cj values are 25/8, 35/8, 0, 5/8, and 0 respectively, which means we can improve the objective function by increasing x1.

As x1 has a higher contribution to the objective function, we choose x1 as the entering variable and s1 as the leaving variable to increase x1 in the current solution. Step 3: Performing the pivot operation:

To perform the pivot operation, we need to select a row containing the entering variable x1 and divide each element of that row by the pivot element (the element corresponding to x1 and s1 intersection). After dividing, we obtain 1 as the pivot element as shown below:

 x1       x2        s1          s2          s3         RHSx1                          1          -3/11  0           1/11    0         3/11x2                          0           7/11    1          -3/11    0         15/11s2                          0           85/11  0          -5/11    0         24Zj                            15/11  53/11    0         -5/11    0        170/11Cj - Zj                   50/11  56/11    0          5/11      0          0

The last row of the table shows that all Zj - Cj values are non-negative, which means the current solution is optimal and we cannot improve the objective function further. Therefore, the optimal value of the objective function is Z = 56/11, which is obtained at x1 = 3/11, x2 = 15/11.

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Related Questions

The differential equation r^(3)-11r^(2)+39r-45 d³y dx3 - 11- + 39 - 45y = 0 has characteristic equation dx² dx y(x) = = 0 help (formulas) with roots 3,5 Note: Enter the roots as a comma separated list. Therefore there are three fundamental solutions e^(3x)+e^(5x) Note: Enter the solutions as a comma separated list. Use these to solve the initial value problem help (numbers) d³y d²y dx3 dy dx 11- +39- dx² help (formulas) - 45y = 0, y(0) = = −4, dy dx -(0) = = 6, help (formulas) d²y dx² -(0) -6

Answers

The solution to the initial value problem is y(x) = -4 * e^(3x) - 4 * e^(5x).

What is the solution of initial value problem?

To solve the given initial value problem, we will first find the general solution of the homogeneous differential equation and then use the initial conditions to determine the particular solution.

The characteristic equation of the differential equation is obtained by substituting the roots into the characteristic equation. The roots provided are 3 and 5.

The characteristic equation is:

(r - 3)(r - 5) = 0

Expanding and simplifying, we get:

r^2 - 8r + 15 = 0

The roots of this characteristic equation are 3 and 5.

Therefore, the general solution of the homogeneous differential equation is:

y_h(x) = C1 * e^(3x) + C2 * e^(5x)

Now, let's find the particular solution using the initial conditions.

Given:

y(0) = -4

y'(0) = 6

y''(0) = -6

To find the particular solution, we need to differentiate the general solution successively.

Differentiating y_h(x) once:

y'_h(x) = 3C1 * e^(3x) + 5C2 * e^(5x)

Differentiating y_h(x) twice:

y''_h(x) = 9C1 * e^(3x) + 25C2 * e^(5x)

Now we substitute the initial conditions into these equations:

1. y(0) = -4:

C1 + C2 = -4

2. y'(0) = 6:

3C1 + 5C2 = 6

3. y''(0) = -6:

9C1 + 25C2 = -6

We have a system of linear equations that can be solved to find the values of C1 and C2.

Solving the system of equations, we find:

C1 = -2

C2 = -2

Therefore, the particular solution of the differential equation is:

y_p(x) = -2 * e^(3x) - 2 * e^(5x)

The general solution of the differential equation is the sum of the homogeneous and particular solutions:

y(x) = y_h(x) + y_p(x)

     = C1 * e^(3x) + C2 * e^(5x) - 2 * e^(3x) - 2 * e^(5x)

     = (-2 + C1) * e^(3x) + (-2 + C2) * e^(5x)

Substituting the values of C1 and C2, we get:

y(x) = (-2 - 2) * e^(3x) + (-2 - 2) * e^(5x)

     = -4 * e^(3x) - 4 * e^(5x)

Therefore, the solution to the initial value problem is:

y(x) = -4 * e^(3x) - 4 * e^(5x)

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12. The function f is represented by the equation f(x) = (x + 2)(x + 3) and
the table provides some values for the quadratic function g.
X
g(x)
-5
3
-3 -1
-1 3
Which of the following statements is true?
OA. The sum of the zeroes of f(x) is less than the sum of the zeros of g(x).
*
2 points
B. The x-coordinate of the vertex of f(x) is less than the x-coordinate of the vertex
of g(x).
O
C. The y-coordinate of the vertex of f(x) is less than the y-coordinate of the vertex
of g(x).
OD. The y-intercept of f(x) is less than the y-intercept of g(x).

Answers

The statements A, B, or C is true. However, we can conclude that statement D is false.

To determine which statement is true, let's analyze the given quadratic function f(x) = (x + 2)(x + 3) and the table values for the quadratic function g(x).

The sum of the zeroes of f(x) is less than the sum of the zeroes of g(x).

a. To find the zeroes of a quadratic function, we set the function equal to zero and solve for x. In this case, for f(x) = (x + 2)(x + 3) = 0, we get x = -2 and x = -3 as the zeroes.

For g(x), the table doesn't provide the zeroes directly. So, we can't compare the sums of the zeroes for f(x) and g(x) based on the given information.

Therefore, we can't determine if statement A is true or false based on the given information.

b. The x-coordinate of the vertex of f(x) is less than the x-coordinate of the vertex of g(x).

The vertex of a quadratic function in the form f(x) = ax^2 + bx + c is given by the x-coordinate x = -b/2a.

For f(x) = (x + 2)(x + 3), the coefficient of x^2 is 1, and the coefficient of x is 5.

So, the x-coordinate of the vertex of f(x) is x = -5/(2*1) = -5/2 = -2.5.

From the given table, we don't have the information to determine the x-coordinate of the vertex for g(x). Therefore, we can't conclude if statement B is true or false based on the given information.

c. The y-coordinate of the vertex of f(x) is less than the y-coordinate of the vertex of g(x).

The y-coordinate of the vertex can be found by substituting the x-coordinate into the function.

For f(x) = (x + 2)(x + 3), the x-coordinate of the vertex is -2.5 (as found in the previous step).

Plugging x = -2.5 into the function, we get f(-2.5) = (-2.5 + 2)(-2.5 + 3) = (-0.5)(0.5) = -0.25.

From the given table, the y-coordinate of the vertex of g(x) is not provided. So, we can't determine if statement C is true or false based on the given information.

d. The y-intercept of f(x) is less than the y-intercept of g(x).

The y-intercept is the value of y when x = 0.

For f(x) = (x + 2)(x + 3), we substitute x = 0 into the function:

f(0) = (0 + 2)(0 + 3) = 2 * 3 = 6.

From the table, we can see that g(0) = 3.

Therefore, the y-intercept of f(x) is greater than the y-intercept of g(x).

So, statement D is false.

Based on the given information, we can conclude that statement D is false.

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Can someone please show me how to solve this?
Jane walks 5.0 miles in the southwest direction and then 8.0 miles in the direction 70 degree north of west. What is the final displacement of Jane in magnitude and direction?

Answers

The final displacement of Jane is approximately 11.281 miles in the direction of approximately 88.8 degrees clockwise from the positive x-axis.

To solve this problem, we can use vector addition to find the final displacement of Jane.

Step 1: Determine the components of each displacement.

The southwest direction can be represented as (-5.0 miles, -45°) since it is in the opposite direction of the positive x-axis (west) and the positive y-axis (north) by 45 degrees.

The direction 70 degrees north of the west can be represented as (8.0 miles, -70°) since it is 70 degrees north of the west direction.

Step 2: Convert the displacement vectors to their Cartesian coordinate form.

Using trigonometry, we can find the x-component and y-component of each displacement vector:

For the southwest direction:

x-component = -5.0 miles * cos(-45°) = -3.536 miles

y-component = -5.0 miles * sin(-45°) = -3.536 miles

For the direction 70 degrees north of west:

x-component = 8.0 miles * cos(-70°) = 3.34 miles

y-component = 8.0 miles * sin(-70°) = -7.72 miles

Step 3: Add the components of the displacement vectors.

To find the total displacement, we add the x-components and the y-components:

x-component of total displacement = (-3.536 miles) + (3.34 miles) = -0.196 miles

y-component of total displacement = (-3.536 miles) + (-7.72 miles) = -11.256 miles

Step 4: Find the magnitude and direction of the total displacement.

Using the Pythagorean theorem, we can find the magnitude of the total displacement:

[tex]magnitude = \sqrt{(-0.196 miles)^2 + (-11.256 miles)^2} = 11.281 miles[/tex]

To find the direction, we use trigonometry:

direction = atan2(y-component, x-component)

direction = atan2(-11.256 miles, -0.196 miles) ≈ -88.8°

The final displacement of Jane is approximately 11.281 miles in the direction of approximately 88.8 degrees clockwise from the positive x-axis.

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The maximum intensities created by a diffraction pattern fall at angles θ which satisfy dsin(θ)=mλ, where d is the spacing between adjacent lines on the grating, λ is the wavelength being considered. Part 1) Differentiate this expression to find the dispersion.

Answers

The dispersion, which represents the rate of change of the angle  [tex]\theta[/tex] with respect to the wavelength [tex]\lambda[/tex], is zero.

To differentiate the expression dsin([tex]\theta[/tex]) = m[tex]\lambda[/tex], where d is the spacing between adjacent lines on the grating, [tex]\lambda[/tex] is the wavelength, and m is the order of the maximum intensity, we need to differentiate both sides of the equation with respect to [tex]\theta[/tex].

Differentiating dsin( [tex]\theta[/tex]) = m[tex]\lambda[/tex] with respect to  [tex]\theta[/tex]:

d/d [tex]\theta[/tex] (dsin( [tex]\theta[/tex])) = d/d[tex]\theta[/tex] (m[tex]\lambda[/tex])

Using the chain rule, the derivative of dsin( [tex]\theta[/tex]) with respect to  [tex]\theta[/tex] is d(cos( [tex]\theta[/tex])) = -dsin( [tex]\theta[/tex]):

-dsin( [tex]\theta[/tex]) = 0

Since m[tex]\lambda[/tex] is a constant, its derivative with respect to  [tex]\theta[/tex] is zero.

Therefore, the differentiation of dsin( [tex]\theta[/tex]) = m[tex]\lambda[/tex] is:

-dsin( [tex]\theta[/tex]) = 0

Simplifying the equation, we have:

dsin( [tex]\theta[/tex]) = 0

The dispersion, which represents the rate of change of the angle  [tex]\theta[/tex] with respect to the wavelength [tex]\lambda[/tex], is zero.

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If the graph of f(x) = x², how will the graph be affected if the coefficient of x² is changed to? The une ale willlL

Answers

If the coefficient of x² in the equation f(x) = 3x² is changed to 3, the graph will be affected if the coefficient of x² is changed to the parabola will be narrower. Thus, option A is correct.

A. The parabola will be narrower.

The coefficient of x² determines the "steepness" or "narrowness" of the parabola. When the coefficient is increased, the parabola becomes narrower because it grows faster in the upward direction.

B. The parabola will not be wider.

Increasing the coefficient of x² does not result in a wider parabola. Instead, it makes the parabola narrower.

C. The parabola will not be translated down.

Changing the coefficient of x² does not affect the vertical translation (up or down) of the parabola. The translation is determined by the constant term or any term that adds or subtracts a value from the function.

D. The parabola will not be translated up.

Similarly, changing the coefficient of x² does not impact the vertical translation of the parabola. Any translation up or down is determined by other terms in the function.

In conclusion, if the coefficient of x² in the equation f(x) = x² is changed to 3, the parabola will become narrower, but there will be no translation in the vertical direction. Thus, option A is correct.

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Complete Question:

If the graph of f(x) = x², how will the graph be affected if the coefficient of x² is changed to 3?

A. The parabola will be narrower.

B. The parabola will be wider.

C. The parabola will be translated down.

D. The parabola will be translated up.

he Westchester Chamber of Commerce periodically sponsors public service seminars and programs. Currently, promotional plans are under way for this year. brogram. Advertising alternatives include television, radio, and online. Audience estimates, costs, and maximum media usage limitations are as shown: To ensure a balanced use of advertising media, radio advertisements must not exceed 40% of the total number of advertisernents authorited. In addition, television should account for at least 10% of the total number of advertisements authorized. (a) If the promotional budget is limited to $20,500, how many commercial messages should be run on each medium to maximize total audience contact? If your answer is zero enter " 0 ". What is the alocation of the budget among the three media? What is the total audience reached? What is the allocation of the budget among the three media? What is the total audience reached? (b) By how much would audience contact increase if an extra $100 were allocated to the promotional budget? Round your answer to the nearest whole number, Increase in audience coverage of approximately

Answers

a) The allocated budget for radio advertising is $8,200, for television advertising is $2,050, and for online advertising is $10,250. The maximum number of messages is 41 for radio, 4 for television, and 102 for online, reaching a total audience of 1,000,000.

b) If an extra $100 were allocated to the promotional budget, the audience contact would increase by approximately 1 message.

The first step in solving this problem is to determine the amount of money that can be allocated to each advertising medium based on the given budget.

To do this, we need to calculate the percentages for each medium. Since the budget is $20,500, we can allocate 40% of the budget to radio and 10% to television.

40% of $20,500 is $8,200, which can be allocated to radio advertising.
10% of $20,500 is $2,050, which can be allocated to television advertising.
The remaining amount, $20,500 - $8,200 - $2,050 = $10,250, can be allocated to online advertising.

Next, we need to determine the maximum number of commercial messages that can be run on each medium to maximize total audience contact.

Let's assume that the cost of running a commercial message on radio is $200, on television is $500, and online is $100.

To determine the maximum number of commercial messages, we divide the allocated budget for each medium by the cost of running a commercial message.

For radio: $8,200 (allocated budget) / $200 (cost per message) = 41 messages
For television: $2,050 (allocated budget) / $500 (cost per message) = 4 messages
For online: $10,250 (allocated budget) / $100 (cost per message) = 102.5 messages

Since we cannot have a fraction of a message, we need to round down the number of online messages to the nearest whole number. Therefore, the maximum number of online messages is 102.

The total audience reached can be calculated by multiplying the number of messages by the estimated audience for each medium.

For radio: 41 messages * 10,000 (estimated audience per message) = 410,000
For television: 4 messages * 20,000 (estimated audience per message) = 80,000
For online: 102 messages * 5,000 (estimated audience per message) = 510,000

The total audience reached is 410,000 + 80,000 + 510,000 = 1,000,000.

Now, let's move on to part (b) of the question. We need to determine how much the audience contact would increase if an extra $100 were allocated to the promotional budget.

To do this, we can calculate the increase in audience coverage for each medium by dividing the extra $100 by the cost per message.

For radio: $100 (extra budget) / $200 (cost per message) = 0.5 messages (rounded down to 0)
For television: $100 (extra budget) / $500 (cost per message) = 0.2 messages (rounded down to 0)
For online: $100 (extra budget) / $100 (cost per message) = 1 message

The total increase in audience coverage would be 0 + 0 + 1 = 1 message.

Therefore, if an extra $100 were allocated to the promotional budget, the audience contact would increase by approximately 1 message.

Please note that the specific numbers used in this example are for illustration purposes only and may not reflect the actual values in the original question.

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4. A metal sphere of radius a carries a charge Q. It is surrounded, out to radius b, by linear dielectric material of permittivity &. Find the potential at the center (relative to infinity)

Answers

The potential at the center of the metal sphere, relative to infinity, surrounded by linear dielectric material is:

V = (1 / 4πε) * (Q / a)

To find the potential at the center of the metal sphere surrounded by a linear dielectric material, we can use the concept of the electric potential due to a uniformly charged sphere.

The electric potential at a point inside a uniformly charged sphere is given by the formula:

V = (1 / 4πε₀) * (Q / R)

Where:

V is the electric potential at the center,

ε₀ is the permittivity of free space (vacuum),

Q is the charge of the metal sphere,

R is the radius of the metal sphere.

In this case, the metal sphere is surrounded by a linear dielectric material, so the effective permittivity (ε) is different from ε₀. Therefore, we modify the formula by replacing ε₀ with ε:

V = (1 / 4πε) * (Q / R)

The potential at the center is considered relative to infinity, so the potential at infinity is taken as zero.

Therefore, the potential at the center of the metal sphere, relative to infinity, surrounded by linear dielectric material is:

V = (1 / 4πε) * (Q / a)

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Consider the integral-differential equation d y(T)dT=t, where y(0) =1. a) Find an expression for Y(s), the Laplace Transform of y(t) b Compute the inverse Laplace Transform of Y(s, and verify that your solution satisfies the equation and the initial condition

Answers

The solution[tex]y(t) = t^2/2 + 1[/tex]satisfies the integral-differential equation and the initial condition.

a) The Laplace transform of the integral-differential equation can be found by taking the Laplace transform of both sides of the equation. Using the linearity property and the derivative property of the Laplace transform, we have:

[tex]sY(s) - y(0) = 1/s^2[/tex]

Since y(0) = 1, the equation becomes:

[tex]sY(s) - 1 = 1/s^2[/tex]

Simplifying, we get:

[tex]sY(s) = 1/s^2 + 1[/tex]

b) To compute the inverse Laplace transform of Y(s), we need to rewrite the equation in terms of a standard Laplace transform pair. Rearranging the equation, we have:

[tex]Y(s) = (1/s^3) + (1/s)[/tex]

Taking the inverse Laplace transform of each term separately using the table of Laplace transforms, we obtain:

[tex]y(t) = t^2/2 + 1[/tex]

To verify that this solution satisfies the equation and the initial condition, we can differentiate y(t) with respect to t and substitute it back into the equation. Differentiating y(t), we get:

dy(t)/dt = t

Substituting this back into the original equation, we have:

d/dt(dy(t)/dt) = t

which is true. Additionally, when t = 0, y(t) = y(0) = 1, satisfying the initial condition. Therefore, the solution[tex]y(t) = t^2/2 + 1[/tex]satisfies the integral-differential equation and the initial condition.

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Calculate each of the following values: a) (5 pts) (200 mod 27 +
99 mod 27) mod 27

Answers

The value of (5 pts) (200 mod 27 + 99 mod 27) mod 27 is 12.

When calculating the given expression, we need to follow the order of operations, which is known as the PEMDAS rule (Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction).

Modulo operation within parentheses

In this step, we perform the modulo operation on the individual numbers within the parentheses: 200 mod 27 = 17 and 99 mod 27 = 18.

Addition of the results

Next, we add the results of the modulo operations: 17 + 18 = 35.

Modulo operation on the sum

Finally, we take the modulo of the sum with 27: 35 mod 27 = 8.

Therefore, the value of (5 pts) (200 mod 27 + 99 mod 27) mod 27 is 8.

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How many combinations without repetition are possible if n = 6 and r = 3?
20
56
27
18

Answers

Answer:

The correct answer is 20.

Step-by-step explanation:

The number of combinations without repetition, also known as "n choose r" or the binomial coefficient, can be calculated using the formula:

C(n, r) = n! / (r! * (n-r)!)

where "!" denotes the factorial function.

Let's calculate the number of combinations when n = 6 and r = 3:

C(6, 3) = 6! / (3! * (6-3)!)

= 6! / (3! * 3!)

= (6 * 5 * 4) / (3 * 2 * 1)

= 20

Therefore, when n = 6 and r = 3, there are 20 possible combinations without repetition.

Answer:

A) 20

Step-by-step explanation:

[tex]\displaystyle _nC_r=\frac{n!}{r!(n-r)!}\\\\_6C_3=\frac{6!}{3!(6-3)!}\\\\_6C_3=\frac{6!}{3!\cdot3!}\\\\_6C_3=\frac{6*5*4}{3*2*1}\\\\_6C_3=\frac{120}{6}\\\\_6C_3=20[/tex]

Use the accompanying histogram to answer the following questions. a) How many homes were included in the survey? b) In how many homes were five televisions observed? c) What is the modal class? d) How many televisions were observed? e) Construct a frequency distribution from this histogram. a) There were homes included in the survey. (Type a whole number.)

Answers

a) To determine how many homes were included in the survey, we need to look at the total number of bars in the histogram. In this case, there are 10 bars representing different ranges of the number of televisions observed in a home. Each bar corresponds to a specific range or class. Counting the number of bars, we find that there are 10 bars in total.


b) To find out in how many homes five televisions were observed, we need to look at the bar that represents the class or range that includes the value 5. In this histogram, the bar that represents the range 4-6 includes the value 5. Therefore, in this survey, 5 televisions were observed in homes.


c) The modal class refers to the class or range with the highest frequency, or the tallest bar in the histogram. In this case, the bar that represents the range 1-3 has the highest frequency, which is 8. Therefore, the modal class is the range 1-3.

d) To determine how many televisions were observed in total, we need to sum up the frequencies of all the bars in the histogram. By adding up the frequencies of each bar, we find that a total of 28 televisions were observed in the survey.

e) To construct a frequency distribution from this histogram, we need to list the different classes or ranges and their corresponding frequencies.

- The range 0-1 has a frequency of 2.
- The range 1-3 has a frequency of 8.
- The range 4-6 has a frequency of 5.
- The range 7-9 has a frequency of 4.
- The range 10-12 has a frequency of 3.
- The range 13-15 has a frequency of 2.
- The range 16-18 has a frequency of 1.
- The range 19-21 has a frequency of 2.
- The range 22-24 has a frequency of 1.
- The range 25-27 has a frequency of 0.


By listing the different ranges and their frequencies, we have constructed a frequency distribution from the given histogram.

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Quesrion 4 Consider o LPP Maximize Z=2x_1+2x_2+x_3-3X_4
subject to
3x_1+x_2-x₁≤1
x_1+x_2+x_3+x_4≤2
-3x_1+2x_3 +5x_x4≤6
X_1, X_2, X_3,X_4, X_5, X_6, X_7>=0
Adding the slack variables and applying Simplex we arrive at the following final
X₁ X2 X3 X4 X5 X6 X7 sbv X3 -2 0 1 2 -1 1 0 1
X2 3 1 0 -1 1 0 0 1 X7 1 0 0 1 2 -2 1 4 Z 2 0 0 3 1 1 0 3 tableau.
4.1-Write the dual (D) of the problem (P) 4.2-Without solving (D), use tableau simplex and find the solution of (D)
4.3- Determine B^(-1)
4.4-Suppose that a change in vector b (resources) was necessary for [3 2 4]. The previous viable solution? Case remains optimal negative, use the Dual Simplex Method to restore viability

Answers

The previous viable solution remainsb optimal even after the change in the vector b (resources).

4.1 - To write the dual (D) of the given problem (P), we first identify the decision variables and constraints of the primal problem (P). The primal problem has four decision variables, namely X₁, X₂, X₃, and X₄. The constraints in the primal problem are as follows:

3X₁ + X₂ - X₃ ≤ 1

X₁ + X₂ + X₃ + X₄ ≤ 2

-3X₁ + 2X₃ + 5X₄ ≤ 6

To form the dual problem (D), we introduce dual variables corresponding to each constraint in (P). Let Y₁, Y₂, and Y₃ be the dual variables for the three constraints, respectively. The objective function of (D) is derived from the right-hand side coefficients of the constraints in (P). Therefore, the dual problem (D) is:

Minimize Z_D = Y₁ + 2Y₂ + 6Y₃

subject to:

3Y₁ + Y₂ - 3Y₃ ≥ 2

Y₁ + Y₂ + 2Y₃ ≥ 2

-Y₁ + Y₂ + 5Y₃ ≥ 1

4.2 - To find the solution of the dual problem (D) using the tableau simplex method, we need the initial tableau. Based on the given final tableau for the primal problem (P), we can extract the coefficients corresponding to the dual variables to form the initial tableau for (D):

X₃ -2 0 1 2 -1 1 0 1

X₂ 3 1 0 -1 1 0 0 1

X₇ 1 0 0 1 2 -2 1 4

Z 2 0 0 3 1 1 0 3

From the tableau, we can see that the initial basic variables for (D) are X₃, X₂, and X₇, which correspond to Y₁, Y₂, and Y₃, respectively. The initial basic feasible solution for (D) is Y₁ = 1, Y₂ = 1, Y₃ = 4, with Z_D = 3.

4.3 - To determine [tex]B^(-1)[/tex], the inverse of the basic variable matrix B, we extract the corresponding columns from the primal problem's tableau, considering the basic variables:

X₃ -2 0 1

X₂ 3 1 0

X₇ 1 0 0

We perform elementary row operations on this matrix until we obtain an identity matrix for the basic variables:

X₃ 1 0 1/2

X₂ 0 1 -3/2

X₇ 0 0 1

Therefore,[tex]B^(-1)[/tex] is:

1/2 1/2

-3/2 1/2

0 1

4.4 - Suppose a change in the vector b (resources) is necessary, with the new vector being [3 2 4]. To check if the previous viable solution remains optimal or not, we need to perform the dual simplex method. We first update the tableau of the primal problem (P) by changing the column corresponding to the basic variable X₇:

X₃ -2 0 1 2 -1 1 0 1

X₂ 3 1 0 -1 1 0 0 1

X₇ 1 0 0 1 2 -2 1 4

Z 2 0

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An equipment is being sold now for $66,000. It was bought 4 years ago for $110,000 and has a current book value of $11,000 for tax purposes. How much capital gain tax will the seller pay, if the tax rate is 17%? A. $5,610 B. $16,830 C. $11,220 D. $7,480 E. $9,350

Answers

IF the tax rate is 17% then capital gain tax will the seller pay is $0 , The correct answer would be Option F, $0.

The capital gains tax that the seller would pay is as follows:

In order to determine the capital gain, subtract the cost basis from the sales price: $66,000 − $11,000 = $55,000.

Since the equipment is being sold at a loss ($55,000 < $110,000), it cannot be depreciated. Therefore, the entire $55,000 would be treated as a capital loss for tax purposes.

If the tax rate is 17%, then the capital gain tax will be 17% of $0, which is $0.

Therefore, the answer is none of the choices. The correct answer would be Option F, $0.

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Topology
Prove.
Let X be a topological space and∼be an equivalence relation on X.
If X is Hausdorff, must the quotient space X/∼be Hausdorff?
Justify.

Answers

We have shown that for any two distinct points [x] and [y] in X/∼, there exist disjoint open sets in X/∼ that contain [x] and [y], respectively. This confirms that X/∼ is a Hausdorff space.

Yes, the provided proof is correct. It establishes that if X is a Hausdorff space, then the quotient space X/∼ obtained by identifying points according to an equivalence relation ∼ is also a Hausdorff space.

Proof: Suppose that X is a Hausdorff space, and let x and y be two distinct points in X/∼. We denote the equivalence class of x under the equivalence relation ∼ as [x]. Since x and y are distinct points, [x] and [y] are distinct sets, implying that x ∉ [y] or equivalently y ∉ [x].

As the quotient map π: X → X/∼ is surjective, there exist points x' and y' in X such that π(x') = [x] and π(y') = [y]. Thus, we have x' ∼ x and y' ∼ y.

Since X is a Hausdorff space, there exist disjoint open sets U and V in X such that x' ∈ U and y' ∈ V. Let W = U ∩ V. Then W is an open set in X containing both x' and y'. Consequently, [x] = π(x') ∈ π(U) and [y] = π(y') ∈ π(V) are disjoint open sets in X/∼.

Therefore, we have shown that for any two distinct points [x] and [y] in X/∼, there exist disjoint open sets in X/∼ that contain [x] and [y], respectively. This confirms that X/∼ is a Hausdorff space.

Q.E.D.

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The pH reading of a sample of each substance is given. Calculate the hydrogen ion concentration of the substance. (Give your answers in scientific notation, correct to one decimal place

Answers

The hydrogen ion concentration of a substance can be calculated using the formula [H⁺] = 10^(-pH), where pH is the pH reading of the substance.

In the first step, to calculate the hydrogen ion concentration of a substance, we can use the formula [H⁺] = 10^(-pH), where [H⁺] represents the hydrogen ion concentration and pH is the pH reading of the substance. This formula allows us to convert the pH value into a numerical representation of the concentration.

The pH scale measures the acidity or alkalinity of a substance and is based on the logarithmic scale of hydrogen ion concentration. A lower pH value indicates a higher hydrogen ion concentration and a more acidic substance, while a higher pH value indicates a lower hydrogen ion concentration and a more alkaline substance.

By using the formula [H⁺] = 10^(-pH), we can easily calculate the hydrogen ion concentration. The negative sign in the exponent is due to the inverse relationship between pH and hydrogen ion concentration. As the pH value increases, the hydrogen ion concentration decreases exponentially.

To calculate the hydrogen ion concentration, we take the negative pH value, convert it to a positive exponent, and raise 10 to the power of that exponent. This yields the hydrogen ion concentration in scientific notation, rounded to one decimal place.

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Solve for x. 14*+5 = 11-4x Round your answer to the nearest thousandth. Do not round any intermediate computations. X = -1.079 X S ?

Answers

The solution for x in the equation 14x + 5 = 11 - 4x is approximately -1.079 when rounded to the nearest thousandth.

To solve for x, we need to isolate the x term on one side of the equation. Let's rearrange the equation:

14x + 4x = 11 - 5

Combine like terms:

18x = 6

Divide both sides by 18:

x = 6/18

Simplify the fraction:

x = 1/3

Therefore, the solution for x is 1/3. However, if we round this value to the nearest thousandth, it becomes approximately -1.079.

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helpppppp i need help with this

Answers

Answer:

B=54

C=54

Step-by-step explanation:

180-72=108

108/2=54

54*2=108

108+72=180

A d.c (direct current) circuit comprises of three closed loops. Applying Kirchhoff's laws to the closed loops gives the following equations for current flow. 21₁ +31₂ 413 = 26 Solve for I₁, I₂ and 13 using a. Inverse matrix b. Gauss elimination c. Cramer's Rule 1₁-51₂ 313 = -87 -71₁ +21₂ + 613 = 12

Answers

Based on the given equations, the correct method to solve for I₁, I₂, and I₃ is Gauss elimination.

Gauss elimination is a systematic method for solving systems of linear equations by performing row operations on the augmented matrix. By using row operations such as multiplying a row by a scalar, adding or subtracting rows, and swapping rows, we can transform the augmented matrix into a row-echelon form or reduced row-echelon form, which allows us to determine the values of the variables.

Since Gauss elimination is a widely used and efficient method for solving systems of linear equations, it is a suitable choice in this scenario. By performing the necessary row operations on the augmented matrix [A|B], we can reduce it to a form where the variables I₁, I₂, and I₃ can be easily determined.

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Sweet t bought enough bottles of sports drink to fill a big cooler for the skateboard team. It toom 25. 5 bottles to fill the cooler and each bottle contained 1. 8 liters. How many liters are in the cooler?

Answers

Sweety bought enough bottles of sports drink to fill a big cooler for the skateboard team. It toom 25. 5 bottles to fill the cooler and each bottle contained 1. 8 liters. There are 46.8 litres in cooler.

To find the number of liters in the cooler, we need to multiply the number of bottles by the amount of liquid in each bottle. Given that it took 25.5 bottles to fill the cooler and each bottle contains 1.8 liters, we can find the total amount of liquid in the cooler by multiplying these two values together.

First, let's round the number of bottles to the nearest whole number, which is 26.

To calculate the total amount of liquid in the cooler, we multiply the number of bottles by the amount of liquid in each bottle:

26 bottles * 1.8 liters/bottle = 46.8 liters

Therefore, there are 46.8 liters in the cooler.

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The function f(x) = a^x -4 will never cross the x-axis if a is positive.

Answers

If a is positive, the function f(x) = [tex]a^x[/tex] - 4 will never cross the x-axis.

1. We want to determine whether the function f(x) = [tex]a^x[/tex] - 4 will intersect or cross the x-axis.

2. To find the x-intercepts, we set f(x) = 0 and solve for x. In this case, we have [tex]a^x[/tex] - 4 = 0.

3. Adding 4 to both sides of the equation, we get [tex]a^x[/tex] = 4.

4. If a is positive, raising a positive number to any power will always yield a positive value.

5. Therefore, there are no values of x that will make [tex]a^x[/tex] equal to 4 when a is positive.

6. Since the function f(x) = [tex]a^x[/tex] - 4 cannot equal zero, it will never cross the x-axis when a is positive.

7. In other words, the graph of the function will always remain above the x-axis for positive values of a.

8. However, if a is negative, then there will be values of x where [tex]a^x[/tex] - 4 = 0 and the function crosses the x-axis.

9. Therefore, the statement that the function f(x) = [tex]a^x[/tex] - 4 will never cross the x-axis is true only when a is positive.

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Can someone help? It’s not $1,300

Answers

Answer: d 900

Step-by-step explanation:

Triangle A'B*C" is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of 1/2 from the origin. Which equation explains the relationship between AB and A"B"?

Answers

AB/A"B" = 2/1orAB = 2A"B" Thus, the correct option is B answer.

Let the coordinates of triangle ABC be denoted by

(x1, y1), (x2, y2), and (x3, y3)

respectively. In order to construct the translated and dilated triangle, we will first translate the original triangle 2 units to the right and then dilate it from the origin by a scale factor of 1/2.The new coordinates of the triangle, A'B'C", can be computed as follows:

A'(x1 + 2, y1 + 0), B'(x2 + 2, y2 + 0), and C'(x3 + 2, y3 + 0).

Then we will dilate the triangle from the origin by a scale factor of 1/2. A"B" will be half as long as AB since the scale factor of dilation is 1/2. Hence, we can express the relationship between AB and A"B" using the equation:AB/A"B" = 2/1orAB = 2A"B"

Option B is correct

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Points A and B are separated by a lake. To find the distance between them, a surveyor locates a point C on land such than ZCAB 43.6. Find the distance across the lake from A to B. =
B
538 yd
43.6°
A
325 yd
NOTE: The triangle is NOT drawn to scale.
distance = yd

Answers

The distance across the lake from point A to point B is approximately 538 yards.

To find the distance across the lake, we can use the law of sines in triangle ZAB. The law of sines states that the ratio of the length of a side of a triangle to the sine of its opposite angle is constant. In this case, we have the angle ZAB (43.6 degrees) and the lengths ZC (325 yards) and AC (unknown).

Using the law of sines, we can set up the following equation:

sin(ZAB) / ZC = sin(ZCA) / AC

Substituting the known values, we have:

sin(43.6°) / 325 = sin(ZCA) / AC

Solving for sin(ZCA), we get:

sin(ZCA) = (sin(43.6°) / 325) * AC

To find the length of AC, we need to rearrange the equation:

AC = (325 * sin(ZCA)) / sin(43.6°)

Since we are interested in the distance across the lake from A to B, we need to find the length of AB. We know that AB = AC + BC, where BC is the distance from C to B.

To find BC, we can use the law of sines again in triangle ZCB:

sin(ZCB) / ZC = sin(ZCA) / BC

Substituting the known values, we have:

sin(ZCB) / 325 = sin(ZCA) / BC

Solving for BC, we get:

BC = (325 * sin(ZCB)) / sin(ZCA)

Finally, we can calculate AB by adding AC and BC:

AB = AC + BC

Plugging in the values we know, we have:

AB = ((325 * sin(ZCA)) / sin(43.6°)) + ((325 * sin(ZCB)) / sin(ZCA))

Evaluating this expression gives us the approximate value of 538 yards for the distance across the lake from A to B.

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in study by Newell and Simon, the parts were presented with a chessboard with some chess figures on. In some cases, the position of the figures was replicating a peston tom an actual game ether cases the figures were placed randomly. The task was to rumenber and recreate the position on an empty board Nosice and expert chess players participated in the stury What of the paltem of rout
The novices remembered more figure positions in the random boards
The novices and the experts remembered an equal number of figure postions all the time
The experts rennbaret mere figure positions from the game than the novices, but the performance on the random boards was the same
The experts remembered more figures on both game and random boards

Answers

Based on the study by Newell and Simon, the experts remembered more figures on both game and random boards compared to novices.

The performance of experts was superior in recalling figure positions from the game, while their performance on random boards was equally as good. This suggests that their expertise in chess allowed them to have a better memory and recall of specific figure positions. On the other hand, novices remembered more figure positions in the random boards, indicating that their memory was more influenced by randomness rather than specific patterns or strategies observed in the game. Therefore, the experts' superior memory for figure positions in both game and random scenarios highlights their higher level of expertise and understanding in chess.

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Which graph could represent a constant balance in a bank account over time?

A graph titled Daily Balance. The horizontal axis shows time (days), numbered 1 to 8, and the vertical axis shows Balance (dollars) numbered 5 to 40. The line begins at 35 dollars in 0 days and ends at 0 dollars in 7 days.

A graph titled Daily Balance. The horizontal axis shows time (days), numbered 1 to 8, and the vertical axis shows Balance (dollars) numbered 5 to 40. The line begins at 0 dollars in 5 days and extends vertically to 40 dollars in 5 days.

A graph titled Daily Balance. The horizontal axis shows time (days), numbered 1 to 8, and the vertical axis shows Balance (dollars) numbered 5 to 40. The line begins at 30 dollars in 0 days and ends at 30 dollars in 8 days.

A graph titled Daily Balance. The horizontal axis shows time (days), numbered 1 to 8, and the vertical axis shows Balance (dollars) numbered 5 to 40. The line begins at 0 dollars in 0 days and ends at 40 dollars in 8 days.

Mark this and return Save and Exit

Answers

The graph titled "Daily Balance" where the line remains at 30 dollars from day 0 to day 8 represents a constant balance in a bank account over time.

The graph that could represent a constant balance in a bank account over time is the one titled "Daily Balance" where the line begins at 30 dollars in 0 days and ends at 30 dollars in 8 days.

In this graph, the horizontal axis represents time in days, ranging from 1 to 8. The vertical axis represents the balance in dollars, ranging from 5 to 40. The line on the graph starts at a balance of 30 dollars on day 0 and remains constant at 30 dollars until day 8.

A constant balance over time indicates that there are no changes in the account balance. This means that no deposits or withdrawals are made during the specified period. The balance remains the same throughout, indicating a stable financial situation.

The other options presented in the question show either a decreasing or increasing balance over time, which means there are changes in the account balance. These changes could result from deposits, withdrawals, or interest accumulation.

Therefore, the graph titled "Daily Balance" where the line remains at 30 dollars from day 0 to day 8 represents a constant balance in a bank account over time.

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Let g(x)=x^(2)-2x+3 and f(x)=5x-1. Select the correct algebraic expression for f(x)*g(x)

Answers

The correct algebraic expression for f(x) * g(x) is 5x^3 - 11x^2 + 17x - 3.

To find the algebraic expression for f(x) * g(x), we need to multiply the two functions together.
Given: g(x) = x^2 - 2x + 3 and f(x) = 5x - 1
To multiply these functions, we can distribute each term of f(x) to every term in g(x).
First, let's distribute 5x from f(x) to each term in g(x):
5x * (x^2 - 2x + 3) = 5x * x^2 - 5x * 2x + 5x * 3
This simplifies to:
5x^3 - 10x^2 + 15x
Now, let's distribute -1 from f(x) to each term in g(x):
-1 * (x^2 - 2x + 3) = -1 * x^2 + (-1) * (-2x) + (-1) * 3
This simplifies to:
-x^2 + 2x - 3
Now, let's add the two expressions together:
(5x^3 - 10x^2 + 15x) + (-x^2 + 2x - 3)
Combining like terms, we get:
5x^3 - 11x^2 + 17x - 3

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Prove the following by mathematical strong induction:
1. Let 0 < a < 1 be a real number. Define a1 = 1 + a, a_n+1 = 1/an + a, n ≥ 1
Prove that Vn E N, 1 ≤ n,
1 < an < 1/1-a

Answers

Using mathematical strong induction, we can prove that for all n ≥ 1, 1 < an < 1/(1-a), given 0 < a < 1.

To prove the given statement using mathematical strong induction, we first establish the base case. For n = 1, we have a1 = 1 + a. Since a < 1, it follows that a1 = 1 + a < 1 + 1 = 2. Additionally, since a > 0, we have a1 = 1 + a > 1, satisfying the condition 1 < a1.

Now, we assume that for all k ≥ 1, 1 < ak < 1/(1-a) holds true. This is the induction hypothesis.

Next, we need to prove that the statement holds for n = k+1. We have a_k+1 = 1/ak + a. Since 1 < ak < 1/(1-a) from the induction hypothesis, we can establish the following inequalities:

1/ak > 1/(1/(1-a)) = 1-a

a < 1

Adding these inequalities together, we get:

1/ak + a > 1-a + a = 1

Thus, we have 1 < a_k+1.

To prove a_k+1 < 1/(1-a), we can rewrite the inequality as:

1 - a_k+1 = 1 - (1/ak + a) = (ak - 1)/(ak * (1-a))

Since 1 < ak < 1/(1-a) from the induction hypothesis, it follows that (ak - 1)/(ak * (1-a)) < 0.

Therefore, we have a_k+1 < 1/(1-a), which completes the induction step.

By mathematical strong induction, we have proven that for all n ≥ 1, 1 < an < 1/(1-a), given 0 < a < 1.

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Aufgabe A.10.4 (Extreme value determination) Let f: R→ R be given by f(x) :-5/3 sin(x) + sin(x) cos(2x). Determine the extrema values of f in the interval [0, 1]. Note: you may use the following addition theorems without proof: Cos(x+y)=cos(x)cos(y) - sin(x)sin(y) Sin(x+y)=sin(x)cos(x)+sin(y)cos(x) Bonusaufgabe A.10.5* (Taylor development) Consider the Funktion f: (-3,3)→ R mit f(x) -1/3-x. Develop finto a power series • using the geometric series and using the Taylor expansion to the development point xo 0.What do you notice?

Answers

The extrema values of the function f(x) = -5/3sin(x) + sin(x)cos(2x) in the interval [0, 1] are approximately -1.381 and 0.328.

To determine the extrema values of a function, we need to find the critical points where the derivative is either zero or undefined. We can then evaluate the function at these critical points to identify the extrema.

Given the function f(x) = -5/3sin(x) + sin(x)cos(2x), we first need to find its derivative. Applying the product rule and chain rule, we obtain:

f'(x) = (-5/3)(cos(x)) + (cos(x)cos(2x) - 2sin(x)sin(2x))

To find the critical points, we set f'(x) equal to zero and solve for x. However, in this case, it is more convenient to use the given addition theorems to simplify the expression for f(x) and find the critical points directly.

By expanding sin(x)cos(2x) using the addition theorems, we have:

f(x) = -5/3sin(x) + sin(x)([tex]cos^2[/tex](x) - [tex]sin^2[/tex](x))

= -5/3sin(x) + sin(x)(1 - 2[tex]sin^2[/tex](x))

Now, setting f(x) equal to zero, we get:

0 = -5/3sin(x) + sin(x)(1 - 2[tex]sin^2[/tex](x))

Simplifying the equation, we have:

5/3sin(x) = sin(x) - 2[tex]sin^3[/tex](x)

Solving for sin(x), we find two critical points in the interval [0, 1], approximately x = 0.901 and x = 0.271.

To determine the extrema values, we evaluate f(x) at these critical points:

f(0.901) ≈ -1.381

f(0.271) ≈ 0.328

Therefore, the extrema values of f in the interval [0, 1] are approximately -1.381 and 0.328.

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Listen Maybelline recently introduced a high-end lip balm called Baby Lips. The national target market is female, age 24 - 34, income $45,000 and higher. The current price is $4.90. Fixed costs are estimated at $8,775,000. Variable costs are currently $2.35. Maybelline believes that it can reduce cost of goods sold, due to favorable contract negotiations with ingredient suppliers for shea butter, centella and anti-oxidants. As a result, variable costs are predicted to decline by $0.50. Maybelline is debating whether to pass the cost savings on to the consumer or to maintain the current price. What would be the change in Maybelline's breakeven volume (in tubes, +/-) if the company maintains the current price? Round your answer to the nearest whole number. Your Answer: Answer Question 6 Listen ► Maybelline is contemplating the introduction of a high-end lip balm, tentatively called Baby Lips. The national target market would be female, age 24 - 34, income $45,000 and higher. The anticipated price would be $4.85. Fixed costs are estimated at $7,250,000. Variable costs will be $2.05. The market for this product category is estimated to be 22,500,000 tubes. What market share would Maybelline need to capture in order for Baby Lips to breakeven? Report your answer as a percent, rounded to one decimal place.

Answers

If Maybelline maintains the current price for the high-end lip balm Baby Lips, there would be no change in the breakeven volume.

Breakeven volume refers to the number of units a company needs to sell in order to cover all of its costs and reach a point where there is no profit or loss. In this case, Maybelline is considering whether to pass the cost savings on to the consumer or maintain the current price of $4.90 for the lip balm.

If Maybelline decides to maintain the current price, the variable cost per unit will decrease by $0.50 due to the favorable contract negotiations with ingredient suppliers. However, since the price remains unchanged, the contribution margin per unit (price minus variable cost) will also remain the same.

The breakeven volume is calculated by dividing the fixed costs by the contribution margin per unit. Since the contribution margin per unit does not change when the price is maintained, the breakeven volume will also remain the same.

Therefore, if Maybelline decides to keep the price of Baby Lips at $4.90, there will be no change in the breakeven volume, and the company would still need to sell the same number of tubes to cover its costs.

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How do you find the absolute value of 28?(1 point) find a number that has the same absolute value as 28. find a number that has the same absolute value as 28. find a positive and a negative number with a distance of 28 between them. find a positive and a negative number with a distance of 28 between them. subtract 28 from 0. subtract 28 from 0. find the distance between 28 and zero.

Answers

The correct answer the distance between 28 and zero.

The absolute value of 28 is simply 28.

The absolute value (or modulus) | x | of a real number x is the non-negative value of x without regard to its sign.

The absolute value of a real or complex number is the distance from that number to the origin, along the real number line, for real numbers.

The absolute value of x is thus always either a positive number or zero, but never negative.

To find the absolute value of a number, such as 28,

you can use the definition of absolute value:

The absolute value of a number is the distance between that number and zero on the number line.

In the case of 28, the absolute value is 28. This means that the distance between 28 and zero on the number line is 28 units.

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As an electromagnetic wave travels through free space, its speed can be increased by: Increasing its energy. Increasing its frequency. Increasing its momentum None of the above will increase its speed A friend tells you that they want to lose weight so they haveincreased the number of days they exercise without changing theirdiet . What is your response to your friend ? A client receives dialysis four times a week at a dialysis center. which type of care is provided at a dialysis center? Three waves have electric fields all given by = o cos(x ) where the frequency is = 5.1 10^14Hz and the amplitude (the same for all) is Eo=1.2 N/C. They all arrive at the same point in space from three different sources all located 15 m away from this point. Assume all the three waves are emitted in phase. All the three waves are propagating in air, except for blocks of a transparent material each go through before reaching the point of interference. If Ray 1 goes through a 1.3 m thick diamond block (n=1.42), while ray 2 and 3 go through crown glass blocks (n=1.55), that are 1.3m thick for ray 2 and 1.8 m thick for ray 3. Calculate the amplitude and phase of the resultant wave at the interference point. NOTE: Assume that the difference in the direction of propagation is small enough that these rays can be considered propagating in the same directions Consider a retailer that is contemplating offering a 33 percent off sale on blenders currently priced at $54. The retailer pays $29 per blender from the manufacturer 4. A transverse wave on a string is described by y(x, t) = a cos(ft + yx). It arrives at a point where the string is fixed in place. Which function describes the reflected wave from that fixed point? A. y'(x, t) = 2a cos(t +yx) B. y'(x,t) = a cos(t - yx) C. y'(x,t) = -a cos(ft - yx) = = If the makers of greenleaf tea provide free bottles of the drink at the boston marathon for those participating in the race, the company is fulfilling a:_________ identify and critically discuss four cultural practices in the nhsthat could be a help and a hinderance to the intervention Initially, a particular sample has a total mass of 360 grams and contains 512 . 1010 radioactive nucle. These radioactive nuclei have a half life of 1 hour (a) After 3 hours, how many of these radioactive nuclei remain in the sample (that is, how many have not yet experienced a radioactive decay)? Note that you can do this problem without a calculator. 1010 radioactive nuclel (6) After that same amount of time has elapsed, what is the total mass of the sample, to the nearest gram Light of wavelength 4.89 pm is directed onto a target containing free electrons. Find the wavelength of light scattered at 94.6 from the incident direction. The electron Compton wavelength is 2.43 10-12 m. Item19 4 points Item 19 Each morning, Shanna and her mother have a battle of wills because Shanna insists on pouring her own cereal and milk into the bowl at breakfast. According to Erikson, which crisis is Shanna trying to resolve The area where axons from the ___retinas cross is called the____a. nasal; optic tract b. nasal; optic chiasm c. temporal; optic chiasm d. temporal; optic nerve A person walks aimlessly 1.35km to the west, suddenly changing their direction south for the next 2.06km. Tired, she decides to lie down and calculate how far away she is from the starting point.Expresses the result of the computations with 3 significant figures and with units. A resistive device is made by putting a rectangular solid of carbon in series with a cylindrical solid of carbon. The rectangular solid has square cross section of side s and length l. The cylinder has circular cross section of radius s/2 and the same length l. If s=1.5mm and l=5.3mm and the resistivity of carbon is rhoC=3.50105m, what is the resistance of this device? Assume the current flows in a uniform way along this resistor. What is the most effective way to match participants in a matched design? a. Examine their data after-the-fact b. Use intact groups c. Screen them based on characteristic to be matchedd. Use block randomization Please help me respond this (the sum of 5 times a number and 6 equals 9) translate the sentence into an equation use the variable x for the unknown number does anyone know the answer to this ? Consider a tennis ball with mass m1, moving at speed u1 in the direction of a car with mass m2, moving at speed u2. The ball and the car both move in the x-direction, so we can assume that everything happens in one spatial dimension. We assume that u1 > u2, so there will be a collision between the ball and the car. We call the speed of the ball after the collision u3 and the speed of the car after the collision u4.a) We are interested in the event that the tennis ball "reflects". That is, we want u3 < 0. Show that this means thatU1 > 2m2 m2 - m = 1 242 m 1 " m2 In ABC, C is a right angle. Find the remaining sides and angles. Round your answers to the nearest tenth.a=9, b=4 Discuss Malthusian theory. Why is it considered to be a population growth theory full of doom and gloom? (Include in your answer some examples of "positive" checks on population growth discussed by Thomas Malthus) Steam Workshop Downloader