HAPPY NEW YEAR EVERYONE. HERE IS TODAY'S OPTIONAL CHALLENGE
What is 1567238932 * 1456788345
Try to do this on paper and not with a calculator.
This is optional and if you decide to do it, good luck.

Answer:

64

Step-by-step explanation:

v = s^3

v = (4)^3 [4x4x4]

v = 64

Answers:

plus all rounded so i don't cuffuse anyone

1. f(x) = x² + x + 4

f(x) = 0

0 = x² + x + 4

-4 = x² + x

2. linear equation

one solution

Answer:

B). SAS similarity.

Step-by-step explanation:

In Δ WVU & ΔCAB,

UV/CA = 17/34 = 1/2

&

VW/AB = 14/28 = 1/2

∵ UV/CA = VW/AB = 1/2

& ∠V = ∠A (Given)

∵ ΔWVU ≅  ΔCAB   (by SAS similarity)

Answer:

30

Step-by-step explanation:

I asked the my math tutor lol

Answer:

y = 7

Step-by-step explanation:

Given

4y - 6 = 2y + 8 ( subtract 2y from both sides )

2y - 6 = 8 ( add 6 to both sides )

2y = 14 ( divide both sides by 2 )

y = 7

Answer:

Step-by-step explanation:

Oil change

Tire change

Time limitation = 60 min

Required inequality:

Simplified

Answer:

Length of the Rectangle is to be considered as the circumference of the resulting cylinder and the width of the rectangle should be considered as the height of the cylinder only then we get the maximum volume of the cylinder which is 47.77[tex]in^3[/tex]

Step-by-step explanation:

The given dimensions are

Width of the rectangle is  6inches.

Length of the rectangle 10inches.

Now we need to choose in what orientation we need to use the length and the width of the rectangle so that it can be rolled into a rectangle and we get the maximum volume of the resulting cylinder.

so lets consider two cases

CASE-1: width of the rectangle is to be rolled as the circumference of the cylinder and length of the rectangle is to used as the height of the cylinder

 2*pi*r = 6

      r = [tex]\frac{6}{2pi}[/tex]

      r = [tex]\frac{3}{pi}[/tex] Inch

and the height = 10inch.

Volume of the resultant cylinder will be

   = [tex]pi*r^2*h[/tex]

   = [tex]pi*(\frac{3}{pi} )^2*10[/tex]

   = [tex]\frac{9}{pi}*10[/tex]

   = [tex]\frac{90}{pi}[/tex] = 28.662 [tex]in^3[/tex]

CASE-2: When the length of the rectangle is to used as the circumference of the resultant cylinder and the width of the cylinder is used as the height of the cylinder.

2*pi*r= 10

         r =  [tex]\frac{5}{pi}[/tex]

and the height of the cylinder is 6 inch

Now the volume of the cylinder will be

 Volume= [tex]pi*r^2*h[/tex]

              = [tex]pi*(\frac{5}{pi} )^2*6[/tex]

              = [tex]\frac{25}{pi}*6[/tex]

              = [tex]\frac{150}{pi}[/tex] = 47.77[tex]in^3[/tex]

Clearly we have the second case in which the resulting Cylinder will have the maximum volume.

Therefore the CASE-2 will provide the maximum Volume of 47.77[tex]in^3[/tex] to the resulting cylinder in which the length of the rectangle is to be considered as the circumference of the Cylinder and the width of the rectangle is to be considered as the height of the cylinder.

Answer:

so we should find the %20 of 60

60.%20=12

Step-by-step explanation:

the answer is 12

hope it helps

Answer:

g(x) = 1/2x² is the correction option.

Hence, option B is true.

Step-by-step explanation:

Please check the attached graph.

It means when we multiply the parent function by a number 'b' which is less than 1, then the parent function f(x) = x² is vertically compressed by b.

Here, the graph is vertically compressed by 1/2, therefore we conclude that g(x) = 1/2x² is the result of vertical compression of the parent function by 1/2.

Therefore, g(x) = 1/2x² is the correction option.

Hence, option B is true.

Answer:

m=1

c=7

I hope it will be useful.

Answer:

-5

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

c Which system of linear inequalities has the point (2, 1) in its solution set? Which system of linear inequalities has the point (2, 1) in its solution set?

y less-than negative x + 3. y less-than-or-equal-to one-half x + 3 On a coordinate plane, 2 lines are shown. The first solid straight line has a positive slope and goes through (negative 4, 1) and (0, 3). Everything below the line is shaded. The second dashed straight line has a negative slope and goes through (0, 3) and (3, 0). Everything to the left of the line is shaded.

y less-than negative one-half x + 3. y less-than one-half x. On a coordinate plane, 2 lines are shown. The first solid straight line has a negative slope and goes through (0, 3) and (4, 1). Everything below the line is shaded. The second dashed straight line has a positive slope and goes through (0, 0) and (2, 1). Everything below and to the right of the line is shaded.

y less-than-or-equal-to negative x + 3. y less-than-or-equal-to one-half x + 2 On a coordinate plane 2 solid straight lines are shown. The first line has a positive slope and goes through (negative 4, 1) and (0, 3). Everything below the line is shaded. The second line has a negative slope and goes through (0, 3) and (3, 0). Everything below and to the left of the line is shaded.

y less-than one-half x. y less-than-or-equal-to negative one-half x + 2v

The system of linear inequalities x + 2y ≤ 4 and 2x - y > 0 has (2,1) in its solution set.

The solution set is given as:

[tex](x,y) = (2,1)[/tex]

The above solution set is true for x + 2y ≤ 4 and 2x - y > 0, and the proof is as follows:

Substitute 2 for x and 1 for y in x + 2y ≤ 4 and 2x - y > 0.

So, we have:

[tex]\mathbf{2 + 2\times1 \le 4 }[/tex]

[tex]\mathbf{2 + 2\le 4 }[/tex]

[tex]\mathbf{4\le 4 }[/tex] --- this is true, because 4 is less than or equal to 4

Also, we have:

[tex]\mathbf{2x - y > 0}[/tex]

[tex]\mathbf{2 \times 2 - 1 > 0}[/tex]

[tex]\mathbf{4 - 1 > 0}[/tex]

[tex]\mathbf{3> 0}[/tex] --- this is also true, because 3 is greater than 0

Hence, the system of linear inequalities x + 2y ≤ 4 and 2x - y > 0 has (2,1) in its solution set.

Read more about inequalities at:

https://brainly.com/question/11702933

Answer:

s = 6 inches

Step-by-step explanation:

Given:

r = 53 inches,

∠S = 6°

∠T = 58°.

Required:

Length of s

Solution:

Use Sine Rule

Thus:

[tex] \frac{s}{Sin(S)} = \frac{r}{Sin(R)} [/tex]

<R = 180 - (58 + 6)

<R = 116°

r = 53 inches,

∠S = 6°

s = ?

Plug in the values

[tex] \frac{s}{Sin(6)} = \frac{53}{Sin(116)} [/tex]

Multiply both sides by Sin(6)

[tex] \frac{s}{Sin(6)} \times Sin(6) = \frac{53}{Sin(116)} \times Sin(6) [/tex]

[tex] s = \frac{53 \times Sin(6)}{Sin(116)} [/tex]

[tex] s = 6 inches [/tex] (nearest inch)

Answer:

4

Step-by-step explanation:

-9-(-13)

-9+13 <---- (-)*(-) = (+)

13-9

4

Answer:

Y = 1/3x + 6

Step-by-step explanation:

You are trying to find the b in y=mx + b so you plug in the information you have

7=1/3 (3) + b

1/3 *3 = 1

7 = 1 +b

-1 - 1

6=b

So Y = 1/3x + 6

Answer:

9 books each

Step-by-step explanation:

Answer:

3 3/4 brick house

Step-by-step explanation:

Total bricks bought = 3/4 of a ton

Each brick house uses = 1/5 of a ton

How many brick house can Jamie complete before they have to order more?

Number of brick house Jamie can complete with the available bricks = Total bricks bought / bricks per house

= 3/4 ÷ 1/5

= 3/4 × 5/1

= 15/4

= 3 3/4 brick house

Jamie will complete 3 3/4 brick house before they have to order more bricks

Final Answer: [tex]x = 3 + \sqrt{2}, 3 - \sqrt{2}[/tex]

Steps/Reasons/Explanation:

Question: Solve by using the quadratic formula:  [tex]x^{2} - 6x + 7 = 0[/tex].

Step 1: Use the Quadratic Formula.

[tex]x = \frac{6 + \sqrt[2]{2} }{2}, \frac{6 - \sqrt[2]{2} }{2}[/tex]

Step 2: Simplify solutions.

[tex]x = 3 + \sqrt{2}, 3 - \sqrt{2}[/tex]

~I hope I helped you :)~ The quadratic formulaic is attached in an image.

You can see all answers in the picture

Answer:

The nonlinear system of equations has 4 solutions ⇒ B

Step-by-step explanation:

The number of solutions of a system of equations equal to the number of points of intersection of the graphs of the equations of the system

Let us use this note to solve the question

From the given figure

∵ The nonlinear system of equations represented by two curves and a circle

∵ Each curve intersects the circle into two points

∴ The number of the points of intersection is 4

→ By using the note above

∵ The number of intersection points equal to the number of solutions

∴ The number of solutions is 4

∴ The nonlinear system of equations has 4 solutions

Answer:

The remainder when 3456 is divided by 7 is 6.

5 is the remainder when 3456 is divided by 7

A division is a process of splitting a specific amount into equal parts.

We need to find the  remainder when 3456 is divided by 7

3456/7

3456:7 is a ratio and 3456/7 is also called as fraction.

The number 3456 is called the numerator or dividend, and the number 7 is called the denominator or divisor.

3456 we can write as 3451+5

3451 is divided by 7 which gives 493.

5 is the remainder when 3456 is divided by 7

Hence, 5 is the remainder when 3456 is divided by 7

To learn more on Division click:

https://brainly.com/question/21416852

#SPJ2

Answer:

Function.

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

If we apply the Vertical Line Test to the graph, we can see that each x-value has it's own y-value. Therefore, the graph is a function and not a relation.

Answer:

1) The polynomial in standard form is f(x) = x³ - 9·x² + 23·x - 15

2) The polynomial in standard form is f(x) = x³ - (2 - 2·i)·x² + 4·i·x

3) The polynomial in standard form is f(x) = x² + (3·i - 3)·x + 2 - 6·i

4) The polynomial in standard form is f(x) = x² - (5 + √5)·x + 6 + 3·√5

Step-by-step explanation:

Given that that the polynomial is of least degree, we have;

The standard form is the form, f(x) = a·xⁿ + b·xⁿ⁻¹ +...+ c

1) The zeros of the polynomial are x = 5, 3, 1

Which gives the polynomial in factored form as_f(x) = (x - 5)·(x - 3)·(x - 1)

From which we have;

f(x) = (x - 5)·(x - 3)·(x - 1) = (x - 5)·(x² - 4·x + 3) = x³ - 4·x² + 3·x - 5·x² + 20·x - 15

f(x) = x³ - 9·x² + 23·x - 15

The polynomial in standard form is therefore f(x) = x³ - 9·x² + 23·x - 15

2) The zeros of the polynomial are x = 2, 0, 2·i

Which gives the polynomial in factored form as_f(x) = (x - 2)·(x)·(x - 2·i)

From which we have;

f(x) = (x - 2)·x·(x - 2·i) = (x² - 2·x)·(x - 2·i) = x³ - 2·i·x² + 2·x² + 4·ix

The polynomial in standard form is therefore f(x) = x³ - (2 - 2·i)·x² + 4·i·x

3) The zeros of the polynomial are x = 2, 1 - 3·i

Which gives the polynomial in factored form as_f(x) = (x - 2)·(x - 1 - 3·i)

From which we have;

f(x) = (x - 2)·(x - (1 - 3·i)) = x² - x + 3·i·x - 2·x + 2 -6·i = x² + 3·i·x - 3·x + 2 - 6·i

The polynomial in standard form is therefore f(x) = x² + (3·i - 3)·x + 2 - 6·i

4) The zeros of the polynomial are x = 3, 2 + √5

Which gives the polynomial in factored form as_f(x) = (x - 3)·(x - (2 + √5))

From which we have;

f(x) = (x - 3)·(x - (2 + √5)) = x² - 2·x - x·√5 - 3·x + 6 + 3·√5

f(x) = x² - 5·x - x·√5 + 6 + 3·√5 = x² - (5 + √5)·x + 6 + 3·√5

The polynomial in standard form is therefore f(x) = x² - (5 + √5)·x + 6 + 3·√5.

Answer:

1.05

Step-by-step explanation:

3.5x.30=1.05

Answer:

1.05

Step-by-step explanation:

You will have to multiply if you are trying to find the amount of water in total. So, 0.30*3.5=1.05. So, that would be your answer for the amount of rainfall.

Answer:

cos B = [tex]\frac{7}{25}[/tex]

tan B = [tex]\frac{24}{7}[/tex]

sin B = [tex]\frac{24}{25}[/tex]

Step-by-step explanation:

In the right triangle, there are three sides and 2 acute angles

The trigonometry functions of one of the acute angles Ф are

In Δ ACB

∵ ∠C is the right angle

∴ AB is the hypotenuse

∵ AC is the opposite side of ∠B ⇒ leg1

∵ CB is the adjacent side of ∠B ⇒ leg2

→ By using the ratios above

∴ cos B = [tex]\frac{CB}{AB}[/tex] , tan B = [tex]\frac{AC}{CB}[/tex] , sin B = [tex]\frac{AC}{AB}[/tex]

∵ CB = 7, AB = 25, AC = 24

∴ cos B = [tex]\frac{7}{25}[/tex]

∴ tan B = [tex]\frac{24}{7}[/tex]

∴ sin B = [tex]\frac{24}{25}[/tex]

Answer: - 6 1/2

Step-by-step explanation:

We should note that:

=-4 - 2 1/2

= -6 1/2

For example, let's assume you owe Bob $4 and then you owe Bill $2 1/2. To calculate the total amount owed, you would have $6 1/2.

Answer:

469.1 yd²

Step-by-step explanation:

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

   = πr² × [tex]\frac{210}{360}[/tex]

   = π × 16² × [tex]\frac{21}{36}[/tex]

   = 256π × [tex]\frac{7}{12}[/tex]

   ≈ 469.1 yd² ( to 1 dec. place )