Answer in to comments pls cause I can’t see

To determine if 27 and -14 are congruent modulo 4, we need to check if their remainders are the same when divided by 4. Since the remainders are not the same, 27 and -14 are not congruent modulo 4. If n ≡ 4 (mod 5), then n^2 ≡ 1 (mod 5).

For 27, when divided by 4, the remainder is 3. (-14 divided by 4 has a remainder of -2, but we can convert it to a positive remainder by adding 4, so it becomes 2).

Since the remainders are not the same, 27 and -14 are not congruent modulo 4.

Let n be an integer.
If n ≡ 4 (mod 5), it means that n and 4 have the same remainder when divided by 5. In other words, n can be written as n = 5k + 4, where k is an integer.

Now, let's square both sides of the equation:
n^2 = (5k + 4)^2
Expanding this expression, we get:
n^2 = 25k^2 + 40k + 16

Now, let's consider this expression modulo 5:
n^2 ≡ (25k^2 + 40k + 16) (mod 5)

We can simplify this expression further by noticing that 25k^2 and 40k are both divisible by 5. Therefore, they will have a remainder of 0 when divided by 5.

This leaves us with:
n^2 ≡ 16 (mod 5)

Since 16 and 1 have the same remainder when divided by 5, we can conclude that n^2 ≡ 1 (mod 5).

Therefore, if n ≡ 4 (mod 5), then n^2 ≡ 1 (mod 5).

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The unit vector normal to the surface is (√3/3, √3/3, √3/3)

a unit vector normal to the surface defined by the parametric equations x = 7cos(θ)sin(4), y = 5sin(θ)sin(4), and z = cos(4), we need to calculate the gradient vector of the surface and then normalize it to obtain a unit vector.

The gradient vector of a surface is given by (∂f/∂x, ∂f/∂y, ∂f/∂z), where f(x, y, z) is an implicit equation of the surface. In this case, we can consider the equation f(x, y, z) = x - 7cos(θ)sin(4) + y - 5sin(θ)sin(4) + z - cos(4) = 0, as it represents the equation of the surface.

Taking the partial derivatives, we have:

∂f/∂x = 1

∂f/∂y = 1

∂f/∂z = 1

Therefore, the gradient vector is (1, 1, 1).

To obtain a unit vector, we need to normalize the gradient vector. The magnitude of the gradient vector is given by:

|∇f| = √(1^2 + 1^2 + 1^2) = √3.

Dividing the gradient vector by its magnitude, we have:

n = (1/√3, 1/√3, 1/√3).

Simplifying the expression, we get:

n = (√3/3, √3/3, √3/3).

Therefore, the unit vector normal to the surface is (√3/3, √3/3, √3/3).

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(a) fog: (fog)(x) = f(g(x)) = f(x - 3) = (x - 3) + 8 = x + 5

(b) gof: (gof)(x) = g(f(x)) = g(x + 8) = (x + 8) - 3 = x + 5

(c) gog: (gog)(x) = g(g(x)) = g(x - 3) = (x - 3) - 3 = x - 6

(a) The composition fog refers to the function obtained by performing the function g(x) first and then applying the function f(x).

fog(x) = f(g(x)) = f(x - 3) = (x - 3) + 8 = x + 5

In other words, fog(x) is equal to x plus 5.

(b) The composition g of f refers to the function obtained by performing the function f(x) first and then applying the function g(x).

gof(x) = g(f(x)) = g(x + 8) = (x + 8) - 3 = x + 5

Therefore, gof(x) is also equal to x plus 5.

(c) Finally, the composition go g refers to the function obtained by performing the function g(x) twice.

gog(x) = g(g(x)) = g(x - 3) = (x - 3) - 3 = x - 6

Thus, gog(x) simplifies to x minus 6.

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The total amount accumulated at the end of 10 years is approximately $1268.76. Hence, the amount accumulated is $1268.76.

Principal deposited (P): $600

Annual interest rate (r): 5.6%

Number of times interest compounded per year (n): 4

Time in years (t): 10

To find: The total amount accumulated at the end of 10 years.

Solution:

We will use the compound interest formula:

A = P * (1 + r/n)^(nt)

Substituting the given values:

A = 600 * (1 + 0.056/4)^(4 * 10)

Simplifying the expression:

A = 600 * (1.014)^40

Calculating the value:

A ≈ 600 * 2.1146

A ≈ 1268.76

Therefore, , the total money amassed after ten years is around $1268.76.

As a result, the total sum accumulated is $1268.76.

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The equation of the line is y = -2x + 7.

To find the point on the line that is closest to the origin, we need to minimize the distance between the origin (0, 0) and any point (x, y) on the line.

The distance between two points (x1, y1) and (x2, y2) is given by the distance formula:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

In this case, we want to minimize the distance between the origin (0, 0) and a point (x, -2x + 7) on the line.

So, the distance formula becomes:

d = sqrt((x - 0)^2 + ((-2x + 7) - 0)^2)

Simplifying the equation:

d = sqrt(x^2 + (-2x + 7)^2)

To minimize the distance, we can find the minimum value of the function d^2 = x^2 + (-2x + 7)^2, as squaring preserves the minimum value.

Taking the derivative of d^2 with respect to x and setting it to zero:

d^2' = 2x - 2(-2x + 7)(2) = 0

Simplifying and solving for x:

2x + 8x - 28 = 0

10x = 28

x = 2.8

Substituting x = 2.8 into the equation of the line, we can find the corresponding y-value:

y = -2(2.8) + 7

y = -5.6 + 7

y = 1.4

Therefore, the point on the line closest to the origin is approximately (2.8, 1.4).

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Answer:

the correct option is h < 8.

Step-by-step explanation:

To solve the inequality 10 + h > 2 + 2h, we can simplify the equation and isolate the variable h.

10 + h > 2 + 2h

Rearranging the equation, we can move all terms containing h to one side:

h - 2h > 2 - 10

Simplifying further:

-h > -8

To isolate h, we multiply both sides of the inequality by -1. Remember, when multiplying or dividing by a negative number, the direction of the inequality sign must be flipped.

(-1)(-h) < (-1)(-8)

h < 8

The result of the recurrence: an=9a n−1 for n≥2 with the initial condition a1=−6. an=  -6 × (-9)n-1

There is the recurrence relation: an = 9an - 1 with the initial condition a1 = -6. The task is to find the solution to the recurrence relation. Let's use the backward substitution method to solve the recurrence relation. In the backward substitution method, we start from the value of an and use the relation an = 9an - 1 to calculate an - 1, then use an - 1 = 9an - 2 to calculate an - 2, and so on until we reach the given initial value.

Here, a1 = -6, so we can start with a2. Using the relation an = 9an - 1, we get:

a2 = 9a1 = 9(-6) = -54

Using the relation an = 9 an - 1, we get:

a3 = 9a2 = 9(-54) = -486

Using the relation an = 9an - 1, we get:

a4 = 9a3 = 9(-486) = -4374

Similarly, we can calculate a5:

a5 = 9a4 = 9(-4374 ) = -39366

So, the result of the recurrence relation with the initial condition a1 = -6 is:

an = -6 × (-9)n-1

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The sum of the radical expression [tex]\sqrt{x^2y^3} + 2\sqrt{x^3y^4} +xy\sqrt y[/tex] is [tex]2xy\sqrt{y} + 2x^2y^2\sqrt{x}[/tex]

From the question, we have the following parameters that can be used in our computation:

[tex]\sqrt{x^2y^3} + 2\sqrt{x^3y^4} +xy\sqrt y[/tex]

Evaluate the exponents

So, we have

[tex]xy\sqrt{y} + 2x^2y^2\sqrt{x} +xy\sqrt y[/tex]

Add the like terms

[tex]2xy\sqrt{y} + 2x^2y^2\sqrt{x}[/tex]

Hence, the sum of the radical expressions is [tex]2xy\sqrt{y} + 2x^2y^2\sqrt{x}[/tex]

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(a) If Leo builds five standard and three deluxe models, he has 56 different choices in positioning the eight houses.
(b) If Leo builds two deluxe and six standard models, he has 28 different positionings.

To determine the number of different choices Leo has in positioning the eight houses, let's consider the two scenarios separately:

(a) If Leo decides to build five standard and three deluxe models, we can calculate the number of different choices using combinations.

For the standard models, Leo has to choose 5 out of the 8 positions for them. This can be calculated using the combination formula: C(8, 5) = 8! / (5! * (8-5)!) = 56.

Similarly, for the deluxe models, Leo has to choose 3 out of the remaining 3 positions. This can be calculated using the combination formula: C(3, 3) = 1.

To find the total number of choices, we multiply the number of choices for the standard models and the deluxe models: 56 * 1 = 56.

Therefore, Leo has 56 different choices in positioning the eight houses if he decides to build five standard and three deluxe models.

(b) If Leo builds two deluxe and six standard models, we can use a similar approach to calculate the number of different positionings.

For the deluxe models, Leo has to choose 2 out of the 8 positions. This can be calculated using the combination formula: C(8, 2) = 8! / (2! * (8-2)!) = 28.

For the standard models, Leo has to choose 6 out of the remaining 6 positions. This can be calculated using the combination formula: C(6, 6) = 1.

To find the total number of choices, we multiply the number of choices for the deluxe models and the standard models: 28 * 1 = 28.

Therefore, Leo has 28 different positionings if he builds two deluxe and six standard models.

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The answer cannot be provided in one row as it requires multiple translations and explanations.

The problem involves translating symbolic logic propositions into English using the given propositions P, Q, and R, representing statements about Rosa graduating, Andrew graduating, and there being a party.

The propositions are then analyzed to determine their contrapositive, converse, and inverse in English.

The specific translations for each proposition are not provided in the question, but the general approach would be to assign English meanings to each symbol (P, Q, R) and then use logical connectives (e.g., "and," "or," "if...then") to construct meaningful sentences based on the given propositions.

The contrapositive, converse, and inverse of each proposition are obtained by negating or rearranging the logical structure of the original proposition.

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To determine the forces in members CD, Cl, and Hl in the given truss, we need additional information such as the lengths of the truss members and the angles between them.

However,  the general approach to solving such problems.

1. Force in member CD: To find the force in member CD, we need to perform a force analysis of the joints connected by this member. This involves applying the equations of equilibrium to the forces acting on the joint. By considering the forces in the other members and the applied load, we can determine the force in member CD.

2. Force in member Cl: Similar to finding the force in member CD, we need to analyze the forces acting on the joints connected by member Cl. By applying equilibrium equations, we can solve for the force in this member.

3. Force in member Hl: Again, we perform a force analysis on the joints connected by member Hl. Equilibrium equations are applied to determine the force in this member.

To obtain specific values for the forces, it is necessary to know the lengths of the truss members, the angles between the members, and any additional information such as support conditions or external loads. With these details, the truss can be analyzed using methods like the method of joints or the method of sections to determine the forces in each member.

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this answer is 7 that is your answer

The final result of long division is: 9x - 11 with the remainder -12.

To divide (9x² - 21x - 20) by (x - 1) using long division:

To divide using long division, follow these steps:

Step 1: Write the problem in long division format. Place the dividend, which is 9x² - 21x - 20, inside the long division symbol. Place the divisor, which is x - 1, on the left side.

        _______________________
x - 1  |   9x² - 21x - 20

Step 2: Divide the first term of the dividend (9x²) by the first term of the divisor (x). Write the quotient above the long division symbol.

        _______________________
x - 1  |   9x² - 21x - 20
         9x

Step 3: Multiply the quotient (9x) by the divisor (x - 1) and write the result below the dividend. Subtract this result from the dividend.

        _______________________
x - 1  |   9x² - 21x - 20
         9x² - 9x

                - (9x² - 9x)
        _______________________
x - 1  |   9x² - 21x - 20
         9x² - 9x
        ________________
                    -12x - 20

Step 4: Bring down the next term of the dividend (-20) and continue the process.

        _______________________
x - 1  |   9x² - 21x - 20
         9x² - 9x
        ________________
                    -12x - 20
                    -12x + 12
        ________________
                           -32

Step 5: Divide the new term (-32) by the first term of the divisor (x). Write the new quotient above the long division symbol.

        _______________________
x - 1  |   9x² - 21x - 20
         9x² - 9x
        ________________
                    -12x - 20
                    -12x + 12
        ________________
                           -32
                           -32

Step 6: Multiply the new quotient (-32) by the divisor (x - 1) and write the result below. Subtract this result from the previous result.

        _______________________
x - 1  |   9x² - 21x - 20
         9x² - 9x
        ________________
                    -12x - 20
                    -12x + 12
        ________________
                           -32
                           -32
         _________________
                              0

Step 7: The division is complete when the remainder is zero. The final quotient is 9x - 12.

Therefore, (9x² - 21x - 20) / (x - 1) = 9x - 12.

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The graph of the function lies below or touches the x-axis but does not rise above it.

The axis of symmetry is a vertical line passing. For the function y = -1.5(x + 20)², the vertex is (-20, 0), the axis of symmetry is the vertical line x = -20, the function has a maximum value of 0, the domain is all real numbers (-∞, ∞), and the range is y ≤ 0.

The vertex of the function is obtained by taking the opposite sign of the values inside the parentheses of the quadratic term. In this case, the vertex is (-20, 0), indicating that the vertex is located at x = -20 and y = 0.

The axis of symmetry is a vertical line passing through the vertex. In this case, the axis of symmetry is x = -20.

Since the coefficient of the quadratic term is negative (-1.5), the parabola opens downward, and the vertex represents the maximum point of the function. The maximum value is 0, which occurs at the vertex (-20, 0).

The domain of the function is all real numbers since there are no restrictions on the x-values.

The range of the function is y ≤ 0, indicating that the function has values less than or equal to 0. The graph of the function lies below or touches the x-axis but does not rise above it.

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Answer:

2

Step-by-step explanation:

if that is not it please let me know i like feedback

By following the four crucial steps, educators can support learners in developing their relational skills and becoming more efficient in making sense of numbers in arithmetic patterns.

To help learners build the relational skill necessary to make sense of numbers in an arithmetic pattern, four crucial steps can be taken.

First, introduce the concept of an arithmetic pattern and provide examples.

Second, emphasize the constant difference between consecutive terms and guide learners to identify and articulate this relationship.

Third, encourage learners to extend the pattern by predicting the next few terms and verifying their predictions.

Finally, provide opportunities for learners to apply the acquired skills by solving problems and creating their own arithmetic patterns.

Building the relational skill in learners to make sense of numbers in an arithmetic pattern involves several steps. Firstly, introducing the concept of an arithmetic pattern is crucial. Teachers can present examples of arithmetic patterns and explain how they consist of consecutive terms where a constant number is added or subtracted each time to form the sequence.

Secondly, learners need to understand the relationship between consecutive terms in the pattern. Teachers should emphasize the constant difference between the terms and guide learners to recognize and express this relationship. In the given example of the arithmetic pattern 4, 7, 10, 13, the constant difference is 3.

Next, learners should be encouraged to extend the pattern by predicting the next terms. They can use the identified constant difference to make informed predictions and then verify their predictions by checking if the subsequent terms fit the pattern. This step helps learners develop a deeper understanding of how the arithmetic pattern continues.

Finally, learners should be provided with opportunities to apply the acquired relational skills. Teachers can present additional problems involving arithmetic patterns and ask learners to solve them, as well as encourage learners to create their own arithmetic patterns to challenge their understanding and creativity.

By following these four crucial steps, educators can support learners in developing their relational skills and becoming more efficient in making sense of numbers in arithmetic patterns.

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Answer:

The phrase that is usually associated with addition is:

d. the total of two numbers

Step-by-step explanation:

Addition is the mathematical operation of combining two or more numbers to find their total or sum. When we add two numbers together, we are determining the total value or amount resulting from their combination. Therefore, "the total of two numbers" is the phrase commonly associated with addition.

Answer:

D. The total of two numbers

Step-by-step explanation:

We are left with D, addition is essentially taking 2 or more numbers and adding them, the result is usually called "sum" or total.

________________________________________________________

Step-by-step explanation:

250%  is 2.5 in decimal form

   2.5 x 22 = 55 specials the next month

b) It will take approximately 24.6 years to save $3,000 for your vacation by saving $100 each month with a 3% nominal interest rate compounded monthly.

c) equivalent effective interest rates are:

i. Semi-annually: 5.06%

ii. Quarterly: 5.11%

iii. Daily: 5.13%

iv. Continuously: 5.13%

EXPLANATION:

To calculate the time it will take for you to save $3,000 for your vacation, we can use the future value formula for monthly compounding:

[tex]Future Value = Principal * (1 + rate/n)^(n*time)[/tex]

Where:

- Principal is the amount you save each month ($100)

- Rate is the nominal interest rate (3% or 0.03)

- n is the number of compounding periods per year (12 for monthly compounding)

- Time is the number of years we want to calculate

We need to solve for time. Let's substitute the given values into the formula:

[tex]$3,000 = $100 * (1 + 0.03/12)^(12*time)Dividing both sides of the equation by $100:30 = (1.0025)^(12*time)[/tex]

Taking the natural logarithm (ln) of both sides:

[tex]ln(30) = ln((1.0025)^(12*time))Using logarithmic properties (ln(a^b) = b * ln(a)):ln(30) = 12*time * ln(1.0025)[/tex]

Solving for time:

[tex]time = ln(30) / (12 * ln(1.0025))[/tex]

Using a calculator:

time ≈ 24.6

c)To calculate the equivalent effective interest rate for a nominal rate of 5% compounded at different intervals:

i. Semi-annually:

The effective interest rate for semi-annual compounding is calculated using the formula:

Effective Interest Rate = (1 + (nominal rate / number of compounding periods))^number of compounding periods - 1

For semi-annual compounding:

[tex]Effective Interest Rate = (1 + (0.05 / 2))^2 - 1[/tex]

Calculating:

Effective Interest Rate ≈ 0.050625 or 5.06%

ii. Quarterly:

The effective interest rate for quarterly compounding is calculated similarly:

[tex]Effective Interest Rate = (1 + (0.05 / 4))^4 - 1[/tex]

Calculating:

Effective Interest Rate ≈ 0.051136 or 5.11%

iii. Daily:

The effective interest rate for daily compounding is calculated using the formula:

Effective Interest Rate = (1 + (nominal rate / number of compounding periods))^number of compounding periods - 1

Since there are approximately 365 days in a year:

[tex]Effective Interest Rate = (1 + (0.05 / 365))^365 - 1[/tex]

Calculating:

Effective Interest Rate ≈ 0.051267 or 5.13%

iv. Continuously:

The effective interest rate for continuous compounding is calculated using the formula:

[tex]Effective Interest Rate = e^(nominal rate) - 1[/tex]

For a nominal rate of 5%:

[tex]Effective Interest Rate = e^(0.05) - 1[/tex]

Calculating:

Effective Interest Rate ≈ 0.05127 or 5.13%

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The solution to the equation 4x + [3 -7 9] = [-3 11 5 -7] is x = [-3/2 9/2 -1 -7/4].

To solve the equation 4x + [3 -7 9] = [-3 11 5 -7], we need to isolate the variable x.

Given:

4x + [3 -7 9] = [-3 11 5 -7]

First, let's subtract [3 -7 9] from both sides of the equation:

4x + [3 -7 9] - [3 -7 9] = [-3 11 5 -7] - [3 -7 9]

This simplifies to:

4x = [-3 11 5 -7] - [3 -7 9]

Subtracting the corresponding elements, we have:

4x = [-3-3 11-(-7) 5-9 -7]

Simplifying further:

4x = [-6 18 -4 -7]

Now, divide both sides of the equation by 4 to solve for x:

4x/4 = [-6 18 -4 -7]/4

This gives us:

x = [-6/4 18/4 -4/4 -7/4]

Simplifying the fractions:

x = [-3/2 9/2 -1 -7/4]

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To guarantee that at least 20 rolls result in the same number on the top face of a six-sided die, one would need to roll the die at least 25 times. to solve the problem we need to consider the worst-case scenario. In this case, we want to find the fewest number of rolls necessary to ensure that at least 20 rolls result in the same number.

Let's consider the scenario where we roll the die and get a different number on each roll. In the worst-case scenario, each new roll will result in a different number until we have rolled all six possible numbers.
To guarantee that we have at least 20 rolls of the same number, we need to exhaust all possibilities for the other five numbers before repeating any number. This means we need to roll the die 6 times to ensure that we have covered all six numbers.
After these 6 rolls, we have exhausted all possibilities for one number. Now, we can start repeating that number. Since we want to have at least 20 rolls of the same number, we need to roll the die 19 more times to reach a total of 20 rolls of the same number.
Therefore, the fewest number of rolls necessary to guarantee that at least 20 rolls result in the same number on the top face of the die is 6 (to cover all possible numbers) + 19 (to reach 20 rolls of the same number) = 25 rolls.
In summary, to guarantee at least 20 rolls of the same number on the top face of a six-sided die, you would need to roll the die at least 25 times.

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The parameterization of a circle of radius r in the xy-plane, centered at (a, b), and traversed once in a clockwise fashion can be represented by the following equations:

[tex]\[ x = a + r \cos(t) \]\[ y = b - r \sin(t) \][/tex]

where:

- (a, b) represents the center of the circle,

- r represents the radius of the circle,

- t represents the parameter that ranges from 0 to 2π (or 0 to 360 degrees) to traverse the circle once in a clockwise fashion.

In the equation for x, the cosine function is used to determine the x-coordinate of points on the circle based on the angle t. Adding the center's x-coordinate, a, gives the correct position of the points on the circle in the x-axis.

In the equation for y, the sine function is used to determine the y-coordinate of points on the circle based on the angle t. Subtracting the center's y-coordinate, b, ensures that the points are correctly positioned on the y-axis.

Together, these equations form a parameterization that represents a circle of radius r, centered at (a, b), and traversed once in a clockwise fashion.

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(a) The simultaneous equations representing the given information can be expressed in matrix form as:

3y - x = -6

x + y = 74

In matrix form, this can be written as:

[ 1   1 ] [ x ]   [ 74 ]

(b) To verify that the simultaneous equations have a unique solution, we can check the determinant of the coefficient matrix [ 3 -1 ; 1 1 ]. If the determinant is non-zero, then a unique solution exists.

(c) To solve for x and y using the inverse matrix method, we can represent the system of equations in matrix form:

where A is the coefficient matrix, X is the column vector [ x ; y ], and B is the column vector of constants [ -6 ; 74 ]. By multiplying both sides of the equation by the inverse of matrix A, we can isolate X:

[tex]A^(-1) * (A * X) = A^(-1) * B[/tex]

X = [tex]A^(-1) * B[/tex]

By calculating the inverse of matrix A and multiplying it by matrix B, we can find the values of x and y.

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i) The Newton-Raphson iterative formula for finding the roots of an equation f(y) = 0 is given by:

yn+1 = yn - f(yn)/f'(yn)

For the function f(y) = y^3 - 2y - 5, we have:

f'(y) = 3y^2 - 2

Substituting these expressions for f(y) and f'(y) into the Newton-Raphson formula, we get:

yn+1 = yn - (yn^3 - 2yn - 5)/(3yn^2 - 2)
    = (2yn^3 + 5)/(3yn^2 - 2)

Thus, we have shown that the Newton-Raphson iterative formula for this function can be written as yn+1 = (2yn^3 + 5)/(3yn^2 - 2).

ii) Using the formula derived in part (i), we can find y1, y2, and y3 if y0 = 2 as follows:

y1 = (2y0^3 + 5)/(3y0^2 - 2)
  = (2 * 2^3 + 5)/(3 * 2^2 - 2)
  = (16 + 5)/(12 - 2)
  = **21/10**

y2 = (2y1^3 + 5)/(3y1^2 - 2)
  = (2 * (21/10)^3 + 5)/(3 * (21/10)^2 - 2)
  = **1.964**

y3 = (2y2^3 + 5)/(3y2^2 - 2)
  = (2 * (1.964)^3 + 5)/(3 * (1.964)^2 - 2)
  = **1.943**

Therefore, if y0 = 2, then y1 ≈ **21/10**, y2 ≈ **1.964**, and y3 ≈ **1.943** using the Newton-Raphson iterative formula.

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Step-by-step explanation:

[tex]18^{10}\approx3.57*10^{12}[/tex]

Answer:

3.57

Step-by-step explanation:

3.570467 a bit longer if needed

Susan needs to pay back approximately $516.37 at the end of the 60-day loan period, and the total interest she needs to pay is approximately $16.37.

To calculate the total amount Susan needs to pay back at the end of the 60-day loan period, we can use the formula for simple interest: Interest = Principal * Rate * Time. Given that Susan takes a cash advance of $500 and the interest rate is 19.99%, we can calculate the interest she needs to pay as follows: Interest = $500 * 0.1999 * (60/365);  Interest ≈ $16.37. Therefore, Susan needs to pay back the principal amount ($500) plus the interest ($16.37) at the end of the loan period.  

Total amount to pay back = Principal + Interest = $500 + $16.37 = $516.37. Hence, Susan needs to pay back approximately $516.37 at the end of the 60-day loan period, and the total interest she needs to pay is approximately $16.37.

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To raise the free chlorine level from 3.0 ppm to 5.0 ppm in a 75,000-gallon pool, we need 15,000 gallons of sodium hypochlorite. None of the given answer choices match this value.

To calculate the amount of sodium hypochlorite needed to raise the free chlorine level in a pool, we can use the following formula:

Amount of chlorine needed = (desired chlorine level - current chlorine level) x pool volume / 10

In this case, the desired chlorine level is 5.0 ppm, the current chlorine level is 3.0 ppm, and the pool volume is 75,000 gallons. Substituting these values into the formula, we get:

Amount of chlorine needed = (5.0 - 3.0) x 75,000 / 10 = 15,000 gallons

Therefore, we need 15,000 gallons of sodium hypochlorite to raise the free chlorine level from 3.0 ppm to 5.0 ppm in a 75,000-gallon pool. None of the given answer choices match this value.

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The probability that either event A or event B occurs is 1/4.

Two events A and B overlap each other partially, and the probability of A and B are P(A) and P(B) respectively.The events A and B overlapping each other.The probability that either event A or event B occurs is given by:

[tex]$$P(A \ \text{or} \ B)=P(A)+P(B)-P(A \ \text{and} \ B)$$[/tex]

Given that the probability of event A is 3/12, and the probability of event B is 1/6.

The overlapping area of A and B is given as 2/12.

Using the above formula, we can find the probability of either event A or event B occurs as follows:

[tex]$$\begin{aligned} P(A \ \text{or} \ B)&=P(A)+P(B)-P(A \ \text{and} \ B) \\ &=\frac{3}{12}+\frac{1}{6}-\frac{2}{12} \\ &=\frac{1}{4} \end{aligned}$$[/tex]

Hence, the probability that either event A or event B occurs is 1/4.

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The company make per day is  941.5 feet.

To find the average number of feet of licorice made per day, we can divide the total amount of licorice made by the number of days:

Average = Total amount / Number of days

In this case, the total amount of licorice made is 6,590.7 feet, and the number of days is 7. Plugging in these values into the formula, we get:

Average = 6,590.7 feet / 7 days

Calculating this division gives us:

Average ≈ 941.5286 feet

Rounding this value to the nearest tenth of a foot, the average number of feet of licorice made per day by Max's Licorice Company is approximately 941.5 feet.

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