An auditorium has 30 rows with 10 seats in the first row, 12 in the second row, 14 in the third row, and so forth. How many seats are in the auditorium? (1 point)

Answer:

quadrant 1 - (2,4)

quadrant 2 - (-3,4)

quadrant 3 - (-1, -5)

quadrant 4 - (6, -1)

Step-by-step explanation:

quadrant one consists of both x and y being positive.

quadrant two being the x is negative but the y is negative.

quadrant 3 has its x and y both negative.

finally, quadrant 4 has its x positive, but y is negative.

Answer:

139/150

Step-by-step explanation:

Let's make a list of the perfect squares.

1 4 9 16 25 36 49 64 81 100 121 144

The probability that one of these is drawn is 12/150 = 4/50 = 2/25

Take out 1. So that means there are 11 perfect squares.

11/150 are your chances of getting a perfect square.

1 - 11/150 = 139/150 that you will not get a perfect square.

I would have included 1 in the perfect squares, but the question says not to so you can't.

If the question did not mean that 1 should be excluded, then the answer is 23/25

Step-by-step explanation:

(1x2+1) x -(6/15)

3/2 x -(6/15)

3/2 x -(2/5)

3/2 x (-2/5)

(-3/2)

Answer:

[tex]1 \frac{1}{2} \times ( - \frac{6}{15} ) = \frac{3}{2} \times ( \frac{ - 6}{15} ) \\ = \frac{ - 3}{5} [/tex]

Answer:

Difference between the two is $36.

Step-by-step explanation:

Pair of shorts costs $12. Shirt costs $48.

48-12=36

Answer:

my answer is a bit different but kinda similar ig.

254.34in^2

Step-by-step explanation:

Radius = Diameter/2          18/2 = 9

Area of circle= pi(3.14) x r^2

A= (3.14) x 9^2

A= (3.14) x 81

A= 254.34in^2

Answer:

I can confirm that the answer is 3(254.34 in.2). I did it on Odyssey

Step-by-step explanation:

Answer:

15 % of usual price is a savings

Step-by-step explanation:

Given that tool set normally cost $80

During the sale this week the tools that cost $12 less than usual

To find: what percentage of the usual price is a savings

From given information,

Usual price of tool set = $ 80

Given that tools that cost $12 less than usual which means she saved $ 12

Savings = $ 12

To find what percentage of the usual price is a savings, we can solve by framing a expression,

Let "x" be the required percentage

Then x % of percentage is equal to savings price

x % of usual price = savings price

x % of 80 = 12

Therefore 15 % of usual price is a savings

Answer:

Answer is 15%

Step-by-step explanation:

You have to do a proportion

12. = x

80 100 and u have to cross multiply

80x = 1200

80. 80

then divide 1200÷80=15

Answer:

hope my answer is helpful to you

plz mark me as brainlist and also follow me

Step-by-step explanation:

after you draw a unit circle you will find the answer

cosec(3pi)=1/sin(3pi)

sin3pi=sinpi=0

so cosec3pi=1/0 which is undefined.

The trigonometric functions [tex]csc(3\pi)[/tex] is undefined.

To understand more, check below explanation.

The value of given trigonometric function are show below,

            [tex]sec(-\pi)=sec(\pi)=-1\\\\csc(3\pi)=\frac{1}{sin(3\pi)}=1/0 =\infty\\\\cot(\frac{7\pi}{2} )=\frac{1}{tan(\frac{7\pi}{2} )} =\frac{1}{\infty} =0\\\\csc(-\frac{3\pi}{2} )=1\\\\cot(\frac{5\pi}{3} )=\frac{1}{\sqrt{3} }[/tex]

Hence, the trigonometric functions [tex]csc(3\pi)[/tex] is undefined.

Learn more about the trigonometric function here:

https://brainly.com/question/14421002

Answer:

point B is in quadrant I and point D is in quadrant II

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given that the radius of a bubble increases by 4%.

Let r be the radius of the spherical bubble, so the new radius of the sphere

[tex]R= r+0.04r = 1.04r\cdots(i)[/tex]

(a) Surface area of the bobble,

[tex]s=4\pi r^2[/tex]

So, the rate of increase of surface area = [tex]4\pi R^2 -4\pi r^2= 4\pi(R^2-r^2)[/tex]

The percentage change in the surface area [tex]= \frac {4\pi(R^2-r^2)}{4\pi r^2}\times 100[/tex]

By using equation (i)

The percentage change in the surface area = [tex]\frac {(1.04r)^2-r^2}{ r^2}\times 100[/tex]

[tex]=(1.04^2-1)\times 100[/tex]

=8.160%

Therefore, the percentage change in the surface area is 8.160%

(b) The volume of the sphere = [tex]4/3 \pi r^3[/tex]

So, the change in the volume = [tex]4/3 \pi R^3-4/3 \pi r^3[/tex]

Percentage change in the volume =

[tex]\frac {4/3 \pi R^3-4/3 \pi r^3}{4/3 \pi r^3}\times 100[/tex]

[tex]=(1.04^3-1)100[/tex] [by using equation (i)]

=12.486%

Therefore, the percentage change in the volume is 12.486%.

what r the tax amounts

Answer:

Step-by-step explanation:

(28a+36ab)

Answer:

22m+42 is the answer

Step-by-step explanation:

All you have to do is simplify and add the common factors.

Answer:

a)3^-2 = 1/3^2 =1/9

b)4^-3 = 1/4^3 = 1/64

c)2^-6 = 1/2^6 = 1/64

Answe

number plus 14

fourteen more than a number

a number increased by 1

Step-by-step explanation:

Which phrases can be represented by the algebraic expression x + 14

Assuming the unknown number = x

Then,

a number plus 14

= x + 14

fourteen more than a number

= x + 14

a number increased by 14

= x + 14

Plus, more than and increased all means plus(+)

Answer:

number plus 14

fourteen more than a number

a number increased by 1

Step-by-step explanation:

Answer:

I think is The little (D) -12.4.

Answer:

k=-100

Step-by-step explanation:

Hope this helped have an amazing day!

Answer:

b

Step-by-step explanation:

because there only allowing the first 50 to register that would be a contest

The method which would not provide voluntary response is that at one of the team games, a person surveys the first 50 people who arrived at the game. Hence, option B is correct.

Mathematical actions are called expressions if they have at least two terms that are related by an operator and include either numbers, variables, or both. Adding, subtraction, multiplying, and division are all reflection coefficient operations.

A mathematical operation such as reduction, addition, multiplication, or division is used to integrate terms into an expression.

As per the given information in the question,

An ice hockey team is changing their team name as well as the mascot and would like to measure city support for the change to the method which would not provide a voluntary response sample is that at one of the team games, a person surveys the first 50 people who arrived at the game.

To know more about Expression:

https://brainly.com/question/14083225

#SPJ6

Answer:

It's a.

Step-by-step explanation:

15s*3+180＝225

30s*3+180＝270

60s*3+180＝360

30s*3+180＝270

Given:

The function is

[tex]f(x)=\log_5(x)[/tex]

To find:

The graph of the given function.

Solution:

We have,

[tex]f(x)=\log_5(x)[/tex]

At x=1,

[tex]f(1)=\log_5(1)[/tex]

[tex]f(1)=0[/tex]        [tex][\because \log_a(1)=0, a>0][/tex]At x=5,

[tex]f(5)=\log_5(5)[/tex]

[tex]f(5)=1[/tex]      [tex][\because \log_aa=1][/tex]

So, the graph of given function passes through the points (1,0) and (5,1). Only graph in option A passes through these two points.

Therefore, the correct option is A.

Answer:

a) The height of the building is 12 metres.

b) The ball will take 6 seconds to hit the ground.

c) The maximum height of the ball is 16 metres and occurs 2 seconds after launch.

d) The ball have a height of 7 meters above the ground 5 seconds after launch.

Step-by-step explanation:

a) The roof of the building is represented by the initial height of the ball according to the function. If we know that [tex]t = 0\,s[/tex], the height of the building, measured in metres, is:

[tex]y = -(0\,s)^{2}+4\cdot (0\,s) + 12[/tex]

[tex]y = 12\,m[/tex]

The height of the building is 12 metres.

b) Let equalise the given polynomial and solve for [tex]t[/tex] to determine the time taken for the ball to hit the ground:

[tex]-t^{2}+4\cdot t +12 = 0[/tex] (1)

By the Quadratic Formula, we find the following solutions:

[tex]t_{1} = 6\,s[/tex] and [tex]t_{2} = -2\,s[/tex]

Since time is a positive variable, then the only solution that is physically reasonable is:

[tex]t = 6\,s[/tex]

The ball will take 6 seconds to hit the ground.

c) The maximum height of the ball occurs when speed is equal to zero. First, we differentiate the function and equalise to zero:

[tex]-2\cdot t + 4 = 0[/tex] (2)

[tex]t = 2\,s[/tex]

Lastly, we evaluate the function at given time:

[tex]y = -(2\,s)^{2}+4\cdot (2\,s)+12[/tex]

[tex]y = 16\,m[/tex]

The maximum height of the ball is 16 metres and occurs 2 seconds after launch.

d) We equalise the height formula to seven and solve the resulting polynomial:

[tex]-t^{2}+4\cdot t + 12 = 7[/tex]

[tex]-t^{2}+4\cdot t +5 = 0[/tex] (3)

By the Quadratic Formula, we get the following solutions:

[tex]t_{1} \approx 5\,s[/tex] and [tex]t_{2} \approx -1\,s[/tex]

The only solution that is physically reasonable is [tex]t = 5\,s[/tex].

The ball have a height of 7 meters above the ground 5 seconds after launch.

Answer:

Step-by-step explanation:

Imagine the numbers are plotted on the number line.

Order on the number line which is from least to greatest:

Answer:

d no 8 unit df parallel bc and 1by 2 bc

Answer:

A multiple is the product result of one number multiplied by another number.

Step-by-step explanation:

Multiples are what we get after multiplying the number by an integer (not a fraction).

Example:

3 × 4 = 12, so 3 and 4 are factors of 12.

Hope this helps!

have a great day/night :D

Answer: step 4

Step-by-step explanation:

Error in the proof starts with the first mistake done. The erroneous step in the proof is given by: Option B: Step 6.

Sign changing in equation does by multiplying -1 on both the sides.

So, if we had [tex]a + b = c[/tex]

Then, its signs are changed as:

[tex]-1(a + b) = -1 \times c\\-a -b = -c[/tex]

For the given case, the mistake occurred during transition from step 5 to step 6. Step 6 is wrong as when sign was changed, sin of cos(θ) remain same, which makes step 5 and step 6 not equal to each other.

The correct proof would be like:

[tex]\rm \cos(2x) = 1- 2\sin^2(x)\\Let\: 2x = \theta\\\\Then: x = \dfrac{\theta}{2}\\\\\cos(\theta) = 1 - 2\sin^2(\dfrac{\theta}{2})\\-1 + \cos(\theta) = -2\sin^2(\dfrac{\theta}{2})\\\\1 - \cos(\theta) = 2\sin^2(\dfrac{\theta}{2})\\\\\dfrac{1-\cos(\theta)}{2} = \sin^2(\dfrac{\theta}{2})\\\\\sin(\theta) = \pm \sqrt{\dfrac{1-\cos(\theta)}{2} }[/tex]

Thus, the erroneous step in the proof is given by: Option B: Step 6.

Learn more about trigonometric functions here:

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Answer:

[tex] {2}^{2x + 2} + 8 = 33( {2}^{x} ) \\ = > ( {2}^{2x} \times {2}^{2} ) + 8 = 33( {2}^{x} ) \\ let \: {2}^{x} be \: m \\ = > 4 {m}^{2} + 8 = 33m \\ = > 4 {m}^{2} - 33m + 8 = 0 \\ use \: quadratic \: equation \\ m = \frac{- b \frac{ + }{} \sqrt{( {b}^{2} - 4ac)} }{2a} [/tex]

Answer:

[tex](5p + 11) + (8p - 4) \\ = ( 13p + 7)[/tex]