We need frequency:-
[tex]\\ \rm\Rrightarrow \nu=\dfrac{c}{\lambda}[/tex]
[tex]\\ \rm\Rrightarrow \nu=\dfrac{3\times 10^8m/s}{590\times 10^{-9}m}[/tex]
[tex]\\ \rm\Rrightarrow \nu=0.0051\times 10^{17}Hz[/tex]
[tex]\\ \rm\Rrightarrow \nu=5.1\times 10^{14}Hz[/tex]
The cart is then pushed up the ramp, compressing the spring a distance A from equilibrium. When
released from rest, the cart oscillates up and down the ramp with a period of T₁. Assume that any friction
is negligible.
The spring is then replaced with a second spring that has a constant k2 = 2k₁, and the new period, T2, is
measured.
Determine the period of T2 in terms of T₁.
When the spring is replaced with a spring with double of initial spring constant k2 = 2k₁, the new period, T2, is [tex]\sqrt{\frac{1}{2} } \ T_1[/tex].
Period of the mass oscillation
The period of the oscillation of the mass or cart on the spring is given by the following formula;
[tex]T = 2\pi \sqrt{\frac{m}{k} } \\\\[/tex]
at a costant mass;
[tex]T_1\sqrt{k_1} = T_2\sqrt{k_2} \\\\T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{k_2} }[/tex]
when spring constant is doubled, k2 = 2k1. the new period, T2 is determined as follows;
[tex]T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{2k_1} } \\\\T_2 = \frac{T_1\sqrt{k_1} }{\sqrt{2} \times \sqrt{k_1} } \\\\T_2 = \frac{T_1}{\sqrt{2} }\\\\T_2 = \sqrt{\frac{1}{2} } \ T_1[/tex]
Thus, when the spring is replaced with a spring with double of initial spring constant k2 = 2k₁, the new period, T2, is [tex]\sqrt{\frac{1}{2} } \ T_1[/tex].
Learn more about period of oscillation here: https://brainly.com/question/20070798
#SPJ1
A new band sensation is playing a concert and recording it for a live album to be released this summer. The band asks the sound mixer if he can autotune
the singer who has a habit of singing slightly lower than the note.
What would the mixer need to do to the sound wave? How would it affect the characteristics of the wave?
The sound mixer will need to increase the amplitude of the sound wave produced by the singer which will increase the loudness of the sound.
Amplitude of sound waveThe amplitude of a sound wave is the maximum vertical displacement of the sound wave.
The sound mixer will need to increase the amplitude of the sound wave produced by the singer.
The increase in the amplitude of the sound wave produced by the lower tune singer will result in increased loudness of the sound.
Thus, the sound mixer will need to increase the amplitude of the sound wave produced by the singer which will increase the loudness of the sound.
Learn more about sound waves here: https://brainly.com/question/1199084
#SPJ1
5One end of a wire is attached to a ceiling, and a solid brass ball is tied to the lower end. The tension in the wire is 120 N. What is the radius of the brass ball?
Answer:
Explanation:
Force of Tension = (m)(g)
120 = (m)(9.8)
m = volume(density)
120 = (4/3)πr³(0.308)(9.8)
[tex]\frac{(120)(3)}{(pi)(0.308)(9.8)}[/tex] = r^3
solve
The radius of the brass ball is equal to 6.94 × 10⁻² m when the tension in the wire is 120 N.
What is tension?Tension can be demonstrated as the pulling force transmitted by the means of a string, or a rope or can be described as the action-reaction pair of forces acting at each end of said elements.
The tension in the wire attached to the ceiling will be given by:
T = mg ⇒m = T/g
The radius of the brass ball is given by: [tex]r =\sqrt[3]{\frac{3V}{4\pi } }[/tex]
The density is given by: ρ = m/V = T/gV
V = T/gρ
Therefore, the expression for the radius can be written as:
[tex]r =\sqrt[3]{\frac{3T}{4\pi\rho g } }[/tex]
Given the tension in the wire, T = 120 N
The density of the brass is = 8730 Kg/m³
[tex]r =\sqrt[3]{\frac{3\times 120}{4\times 3.14 \times 8730 \times 9.81 } }[/tex]
r = 6.94 × 10⁻² m
Learn more about tension, here:
https://brainly.com/question/17073019
#SPJ2
find the distance and displacement by minutes hand of length by 7 cm at the end of 3 ⅔ mins
Answer:
3 14/3
Explanation:
you put a 1 under the 7 then times it with 3 2/3 and you get 3 14/3
Please help quickly!!!
State the basic rules to draw a vector quantity
Explanation:
i dont to i want to copy and paste on my printer
Martin perceived that there was music playing. Martin
A
did not believe there was music.
B
was very surprised by the music.
C
let everyone know about the music.
D
became aware of the music.
The cone and the cylinder below have equal surface area.
2r
OA. True
B. False
B. False, the surface area of the cone and the cylinder is not the same.
What is the Surface area?The area or region that an object’s surface occupies is known as its surface area. Volume, on the other hand, refers to how much room an object has. Geometry has numerous shapes and dimensions, including spheres, cubes, cuboids, cones, cylinders, etc. Each form has its own volume and surface area.
If the slant height of the cone is 2r, then we can use the Pythagorean theorem to find the radius of the cone:
l² = (2r)² - r²
l² = 3r²
l = r√3
Using this value for the radius of the cone, the formula for its surface area becomes:
A(cone) = πrl + πr²
A(cone) = π(r)(r√3) + πr²
A(cone) = πr²(1 + √3)
For the cylinder, we can use the given height and radius to find its surface area:
A(cylinder) = 2πrl + 2πr²
A(cylinder) = 2π(r)(r) + 2π(r²)
A(cylinder) = 2πr²(1 + r)
Comparing the two surface area formulas, we can see that they are not equal in general, since each figure's coefficient in front of the second term (πr²) is different.
Therefore, we cannot conclude that the two figures have the same surface area based on the information.
Learn more about the Surface area here:
https://brainly.com/question/29298005
#SPJ5
What emits infrared radiation?
Question 5 options:
Humans
Non-living objects
Anything that contains atoms
Answer:
anything that contains atoms is the correct answer of given statement
What best describes the speed of light waves in solids, liquids, and gases?
O The speed is fastest in solids.
O The speed is fastest in liquids.
O The speed is fastest in gases.
O The speed is the same in all matter.
Answer:
C
Explanation:
Generally, the speed of light slows down when passing through a medium that is not a vacuum. This is not always the case, but I will be ignoring the rare/exotic exceptions. Light has a harder time traveling through solids and liquids than it does with gases.
Answer:
its c
Explanation:
to which end of the horseshoe magnet will the north end of the magnet be attracted
Answer:
The north end of the magnet will be attracted to the south end of the horseshoe magnet.
Likewise, the north end of the magnet will be attracted to the earth's north pole - so the north pole of the earth is actually a south magnetic pole.
Edwin Hubble discovered that:
Galaxies were moving away from us
Some stars got brighter and dimmer in patterns.
Triangulation was not a reliable method for measuring distances
All of the above.
Answer:
galaxies were moving away from us
Explanation:
i got 100% on my quiz
Holding a pen crosswise in your mouth is likely to improve your mood, a result predicted by
Answer:
the facial-feedback hypothesis
Explanation:
Pluto was first discovered in 1930.It was determined to be located about 39.48 times as far away from the Sun as Earth is. How long does Pluto take to orbit the Sun?
Answer:
It takes total 248 years for Pluto to orbit the sun.
Pluto will take 253 year to orbit the sun.
What is the distance between the Sun and Earth ?Earth's average distance to the Sun is about 93 million miles (150 million kilometers) from the Sun.
What is the distance between Pluto and the Sun?Pluto is located about 39.48 times as far away from the Sun as Earth is.So the distance between Pluto and Sun will be , 39.48 X 93 = 3671.64 million miles.What is Kepler's third law?The squares of the orbital periods of the planets are directly proportional to the cubes of the semi-major axes of their orbits.P^2 = a^3 , where P = period of orbit , a = distance of semi major axis.Pluto has a semi-major axis distance a=40 then T2=403, which gives T=253 years.
Therefore, Pluto will take 253 year to orbit the sun.
Learn more about Kepler's third law here -
https://brainly.com/question/16705471
#SPJ2
You pull on a crate using a rope as in (Figure 1), except the rope is at an angle of 20.0 ∘ above the horizontal. The weight of the crate is 245 N , and the coefficient of kinetic friction between the crate and the floor is 0.270. What must be the tension in the rope to make the crate move at a constant velocity?
Express your answer with the appropriate units.
What is the normal force that the floor exerts on the crate?
Express your answer with the appropriate units.
Hi there!
For an object on an incline with friction being pulled, the following forces are present.
Force due to Gravity Force due to FrictionForce due to tensionThe force due to friction opposes the force due to gravity which would cause the object to slide down. (The force due to friction acts up the incline). Additionally, the force due to the rope is also upward.
Let up the incline be positive, and down the incline be negative.
Doing a summation of forces:
[tex]\Sigma F = F_T + F_f - F_g[/tex]
For the crate to be moving at a constant velocity, there is NO net force acting on the crate, so:
[tex]0 = F_T + F_f - F_g[/tex]
Now, we can express each force as an equation.
Force due to tension:
Must be solved for.Force due to gravity:
On an incline, this is equivalent to the SINE component of its weight. (Force of gravity is STILL THE WEIGHT, but on an incline, it contains a horizontal component that contributes to the net force)This is expressed as:
[tex]F_g = Mgsin\theta[/tex]
Force due to friction:
Equivalent to the normal force and coefficient of friction. The normal force is the VERTICAL component of the object's weight, so:[tex]N = Mgcos\theta[/tex]
[tex]F_f = \mu Mgcos\theta[/tex]
Now, plug these expressions into the above equation.
[tex]0 = F_T + \mu Mgcos\theta - Mgsin\theta\\\\Mgsin\theta - \mu Mgcos\theta = F_T[/tex]
Mg = 245 N (weight). Plug in all values:
[tex]245sin(20) - 0.270(245)cos(20) = F_T\\\\F_T = \boxed{21.634 N}[/tex]
The normal force is equivalent to the vertical component (PERPENDICULAR TO THE INCLINE) of the weight (cosine), so:
[tex]N = Mgcos\theta\\\\N = 245cos(20) = \boxed{230.225 N}[/tex]
To find the tension in the rope needed to make the crate move at a constant velocity, we need to consider the forces acting on the crate.
1. Tension in the rope (T): This force is applied upwards at an angle of 20 degrees above the horizontal.
2. Weight of the crate (W): This force acts downward vertically and is equal to 245 N.
3. Normal force (N): This force is exerted by the floor on the crate and acts perpendicular to the surface of the floor.
4. Kinetic friction force (f_k): This force opposes the motion of the crate and acts parallel to the surface of the floor. The magnitude of kinetic friction is given by: f_k = μ_k * N, where μ_k is the coefficient of kinetic friction (0.270 in this case).
Since the crate is moving at a constant velocity, the net force on the crate must be zero. In other words, the forces pulling the crate forward (T and the horizontal component of the weight) must balance the forces opposing its motion (kinetic friction). The vertical forces (the vertical component of the weight and the normal force) must also balance.
Let's proceed with the calculations:
Horizontal Forces:
T * cos(20°) - f_k = 0
T * sin(20°) + N - W = 0
We can now solve for T and N:
From the horizontal forces equation:
T * cos(20°) = f_k
vertical force:
T = f_k / cos(20°)
T = (0.270 * N) / cos(20°)
From the vertical forces equation:
T * sin(20°) + N = W
T * sin(20°) + N = 245 N
Now, substitute the expression for T from the horizontal forces equation:
(0.270 * N) / cos(20°) * sin(20°) + N = 245 N
Now, solve for N:
N * (0.270 * tan(20°) + 1) = 245 N
N = 245 N / (0.270 * tan(20°) + 1)
Now, plug in the values and calculate N:
N = 245 N / (0.270 * tan(20°) + 1)
N ≈ 208.75 N
Now, we can calculate the tension in the rope (T):
T = (0.270 * N) / cos(20°)
T ≈ (0.270 * 208.75 N) / cos(20°)
T ≈ 67.24 N
So, the tension in the rope needed to make the crate move at a constant velocity is approximately 67.24 N, and the normal force exerted by the floor on the crate is approximately 208.75 N.
To know more about constant velocity :
https://brainly.com/question/10217879
#SPJ3
North of Carthage is this, it is a shallow evaporate lake:
A. Rub al-Khali
B. Sebkhet Arina
C. Sebkhet Qaddafi
Sebkhet Arina
Explanation:
sorry if it's wrong need more information
A person driving in a neighborhood traveling 9 m/s slows to a stop (0 m/s) over 4
seconds as they approach a stop sign. What is the rate of acceleration of the car coming
to a stop in m/s²?
(Please help urgently if you can, thanks :D)
Answer:
-2.25 metres per second squared
A sample of ore containing radioactive strontium 38Sr90 has an activity of 8.2 × 105 Bq. The atomic mass of strontium is 89.908 u, and its half-life is 28.8 yr (1 yr = 3.156 × 107 s). How many grams of strontium are in the sample?
From the activity values and the decay constant, the mass of of Strontium in the sample is:
[tex]1.62 × 10^{-7}g[/tex]
What is the decay constant of an element?The decay constant of an element is the probability of decay of a nucleus per unit time.
{λ = ln 2 / t1/2
where;
t1/2 is the half-life of the isotope.
The half-life is converted to seconds since the decay constant is asked in per seconds.
[tex]28.8 years = 28.8 × 3.156 × 10^{7} = 908928000 s \\ [/tex]
Hence;
[tex]λ = \frac{ln2}{90892800s} = 7.626 s^{-1}[/tex]
The activity of the element, A, the decay constant, λ and the number of nuclei, N are related as follows:
A = (–) λN[tex]N = \frac{8.25 ×10^{5}}{7.626×10^{-10}} = 1.082 × 10^{15} [/tex]
Molar mass of Strontium-90 is 90 g.
1 mole of Strontium-90 contains 6.02×10^23 nuclei.
The mass, m of Strontium in the sample is calculated:
[tex]m = 1.082 × 10^{15} × \frac{90 g}{6.02 × 10^{23}} = 1.62 × 10^{-7}g \\ [/tex]
Therefore, the mass of of Strontium in the sample is:
[tex]1.62 × 10^{-7} \: g[/tex]
Learn more about decay constant at: https://brainly.com/question/17159453
If you double the mass, what happen to the acceleration?
Answer: The math behind this is quite simple. If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.
Explanation:
A tortoise challenges a hare to a four-hour race. The hare is so confident of winning that he allows the tortoise to start with a 10-km lead. The hare runs at a speed of 14 km per hour, but stops for a two-hour nap in the middle of the race. The tortoise plods along at 4 km per hour the whole race. Who gets farther in four hours?
what is electronic logic
Answer:
Digital logic is the basis of computing and many other electronic devices as well as control systems found in this continually advancing digital world.
(too short, sorry)
Can someone please help me!
Answer: I've solved the above questions and attached pictures too which show the working for better understanding of the questions.
hope that helps...
A car moving south speeds up from 10 m/s to 40 m/s in 15 seconds. What is the car’s acceleration?
Answer:
According to the question,
Initial velocity of car (at t=0) = 10 m/s
Final velocity of car (after 15 sec) = 40m/s
Time taken = 15 sec.
Now use, first equation of motion viz.
Explanation:
v = u + at.
40 = 10 + a *15
30 = a*15
a = 30/15
a = 2 m/sec square.
How does paragraph 3 help develop the ideas in this passage
Answer:
celebrating different points.
Explanation:
adds more information to what your talking about
If you wanted the car to roll a long way , would you choose carpet or wood
HELP!! ASAP I DONT KNOW HOW TO THIS
What are the similarities of life science and applied science?
Answer~
Both life science and physical science helps to understand the natural habitat of the earth. Life science deals with the living thing; thus, it is a study of the organic world. On the other hand, physical science deals with nonliving things; thus, it is a study of the inorganic world.
Explanation:
50 POINTS!! HOW DO THIS PLEASE IM SO CONFUSED
runs 4 m North and then runs 9 m West. Calculate Distance and Displacement.
Answer:
Take north as y and west as -x.
distance=√(x^2+y^2)
displacement= tan theta(tan^-1) (y/x)
answers should be, (9.85m, 66.04°)
what is the mathematical equation for resistivity
Answer:
See below
Explanation:
rho = R A/l R = resistance A = cross sectional area l = length
A projectile is fired from the ground with an initial velocity of 250 m/s at an angle 60 degrees above the horizon. Calculate the horizontal and vertical components of the velocity.
The vertical and the horizontal component of the velocity are 216.51 m/s and 125 m/s respectively.
What is velocity ?Velocity is the rate of change of displacement.
To calculate the horizontal component of the projectile we use the formula below.
Formula:
Vx = Vcos∅........... Equation 1Where:
Vx = Horizontal velocity of the projectileV = Velocity of the projectile∅ = Angle of the projectileFrom the question,
Given:
V = 250 m/s∅ = 60°Substitute these values into equation 1
Vx = 250(cos60°)Vx = 125 m/sSimilarly, to calculate the vertical velocity, we use the formula below
Vy = Vsin∅................. Equation 2Where:
Vy = Vertical component of the velocity.Also Substitute the values into equation 2
Vy = 250(sin60°)Vy = 216.51 m/sHence, the vertical and the horizontal component of the velocity are 216.51 m/s and 125 m/s respectively.
Learn more about velocity here: https://brainly.com/question/6504879
#SPJ1