A force of 100 newtons Is applled to a box at an angle of 36° with the horizontal. If the mass of the box Is 25 kilograms, what Is the horizontal

Answer:

Yes, field forces exist in nature.

Explanation:

A field force is a force experience due to an interaction with fields. In this case, a contact is not required before the force can be felt.

The three major field forces are: magnetic field, electric field and gravitational field. The magnetic fields are produced due to the interaction between the north and south poles of a magnet, the electric field is one from charges, while gravitational field is a force of attraction due to gravity on the earth. All these fields occur in nature, therefore making field forces to exist in nature.

Answer:

765,000Joules or 765kJ

Explanation:

The Quantity of heat required is expressed as;

Q = (mcΔt)al + (mcΔt)water

m is the mass

c is specific heat capacity

Δt is the change in temperature

Q = (3(900)(90-5)) + (1.5(4200)(90-5))

Q = 2700*85 + 6300*85

Q = (2700+6300)85

Q = 9000*85

Q = 765,000

Hence the amount of energy needed is 765,000Joules or 765kJ

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

m is the mass

f is the force

From the question we have

[tex]a = \frac{126}{56.2} \\ = 2.241992...[/tex]

We have the final answer as

Hope this helps you

Answer:

B )-14000N

Explanation:

F=mv-mu

t

F =2550(0)-2550(6)

1.1

F = -13909.09

approximately -14000N

Suppose a tractor was moving forward at 6.0 m/s. It runs into a pile of hay and is brought to a stop in 1.1 s. If the tractor had a mass of 2550 kg, the force did the pile of hay stop the tractor 14000N

Force can be a unit of  pushing or pulling of any object which result   from the object’s interaction or movement, without applying force the objects can not be moved, can be stopped or change the direction.

Force is a  quantitative parameter between two physical bodies, means an object and its environment, there are various  types of forces in nature.

If an object present in its moving state will be either static or motion, the position of the object will be changed if it is pushed or pulled and The external push or pull upon the object is mainly called as Force.

The contact force  that occurs when we apply some effort on an object such as Spring Force, Applied Force, Air Resistance Force, Normal Force, Tension Force, Frictional Force

Non-Contact forces are the type of forces that occur from a distance  such as Electromagnetic Force, Gravitational Force, Nuclear Force

F=mv-mu

t

F =2550(0)-2550(6)

1.1

F = -13909.09

approximately -14000N

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Answer:

v = 2.38 × 10³ m/s

Explanation:

Escape velocity, v = √(2gR) where g = acceleration due to gravity on planet and R = radius of planet.

Since it is given that the weight of the man on the moon is 1/6 his weight on earth, and g' = acceleration due to gravity on moon and g = acceleration due to gravity on earth and m = mass of man,

mg' = mg/6

g' = g/6

Since g = 9.8 m/s²,

g'= 9.8 m/s² ÷ 6

g' = 1.63 m/s²

The escape velocity of the moon is thus  v = √(2g'R) where R = radius of moon = 1.737 × 10⁶ m.

Substituting these into v, we have

v = √(2g'R)

v = √(2 × 1.63 m/s² × 1.737 × 10⁶ m)

v = √[5.663 × 10⁶ (m/s)²]

v = 2.38 × 10³ m/s

Answer:

a) 0.5644 m/s

b) ~0.384 m/s^2

c) ~3.638 m/s

Explanation:

a) Tangential speed is found be the radius*rotational speed, so it is 0.83*0.68 = 0.5644 m/s

b) Centripetal acceleration is found by v^2/r, so it is (0.5644^2)/0.83 = ~0.384 m/s^2

c) Let the tangential speed be v. The maximum centripetal force 110 N (as given). Centripetal force = mass*centripetal acceleration = mass*v^2/r (because centripetal acceleration is found by v^2/r). Inputting the values from the problem and solving for v, we get:

110 = 6.9*v^2/0.83

v = sqrt(110*0.83/6.9) = ~3.638 m/s

I hope this helps! :)

Answer:

The dryer evaporate 200 - 24.74 kg of water per hour

To remove 1kg of water it need 3000 K J

So to remove, 175.26 Kg

it need 5.257x [tex]10^{5}[/tex] KJ of heat per hour.

Explanation:

In one hour, the amount of sugar entering = 1000 kg

w.b moisture content is defined as,

weight of water / weight of water + weight of dry

[tex]W_{w}[/tex]/[tex]W_{w}[/tex] + [tex]W_{d}[/tex] x 100

[tex]W_{w}[/tex] + [tex]W_{d}[/tex] = 1000 kg when entering

it has 20% moisture content when entering

[tex]W_{w}[/tex] = 0.2 x 1000 = 200 kg

when leaving it has 3% moisture content then weight of dry material

[tex]W_{d}[/tex] = 1000 - 200 = 800 Kg

[tex]\frac{W_{w}^{'} }{W_{w}^{'} + W_{d}^{'} }[/tex] = 0.03

[tex]\frac{W_{w}^{'} }{W_{w}^{'} + 800 }[/tex] = 0.03

[tex]W_{w} ^{'}[/tex] = 0.03 x [tex]W_{w} ^{'}[/tex] + 0.03 x 800

[tex]W_{w} ^{'}[/tex] = 24.74 kg

When leaving the dryer, the crystals has total weight of the water = 24.74 kg per hour.

The dryer evaporate 200 - 24.74 kg of water per hour

To remove 1kg of water it need 3000 K J

So to remove, 175.26 Kg

it need 5.257x [tex]10^{5}[/tex] KJ of heat per hour.

Answer:

Energy decrease by approximately 1.5J

The change in the energy of the block-spring-Earth system as a result of the block being lowered will be 1.424 J.

Given information;

A person holds a 4.0 kg block at position A in contact with an uncompressed vertical spring with a spring constant, k, of 500 N/m.

The person gently lowers the block from rest at position A to rest at position B. The decrease in height, h, of the object or the compression in spring, x, will be 10 cm.

Due to the decrease in height of the block, the decrease in potential energy will be,

[tex]PE_b=-mgh\\=-4\times9.81\times0.1\\=-3.924\rm\;N[/tex]

Due to compression, the increase in potential energy of the spring will be,

[tex]PE_s=\dfrac{1}{2}kx^2\\=\dfrac{1}{2}500\times(0.1)^2\\=2.5\rm\;J[/tex]

So, the net change in the energy of the system will be,

[tex]E=-3.924+2.5\\=1.424\rm\;J[/tex]

Therefore, the change in the energy of the block-spring-Earth system as a result of the block being lowered will be 1.424 J.

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Answer:

a) 113N

b) 0.37

Explanation:

a) Using the Newton's second law:

\sum Fx =ma

Since the crate is not moving then its acceleration will be zero. The equation will become:

\sum Fx = 0

\sumFx = 0

Fm - Ff = 0.

Fm is the moving force

Ff is the frictional force

Fm = Ff

This means that the moving force is equal to the force of friction if the crate is static.

Since applied force is 113N, hence the magnitude of the static friction force will also be 113N

b) Using the formula

Ff = nR

n is the coefficient of friction

R is the reaction = mg

m is the mass of the crate = 31.2kg

g is the acceleration due to gravity = 9.8m/s²

R = 31.2 × 9.8

R = 305.76N

Recall that;

n = Ff/R

n = 113/305.76

n = 0.37

Hence the minimum possible value of the coefficient of static friction between the crate and the floor is 0.37

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block ([tex]W[/tex]), measured in newtons, is:

[tex]W = m\cdot g[/tex] (1)

Where:

[tex]m[/tex] - Mass of the block of ice, measured in kilograms.

[tex]g[/tex]  - Gravitational acceleration, measured in meters per square second.

If we know that [tex]m = 14\,kg[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], the magnitudes of the weight and normal force of the block of ice are, respectively:

[tex]N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]N = W = 137.298\,N[/tex]

And the pull force is:

[tex]F_{pull} = 98\,N[/tex]

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

[tex]m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f}[/tex] (2)

Where:

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the block, measured in meters per second.

[tex]\Sigma F[/tex] - Horizontal net force, measured in newtons.

[tex]\Delta t[/tex] - Impact time, measured in seconds.

Now we clear the final speed in (2):

[tex]v_{f} = v_{o}+\frac{\Sigma F\cdot \Delta t}{m}[/tex]

If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]m = 14\,kg[/tex], [tex]\Sigma F = 98\,N[/tex] and [tex]\Delta t = 1.40\,s[/tex], then final speed of the ice block is:

[tex]v_{f} = 0\,\frac{m}{s}+\frac{(98\,N)\cdot (1.40\,s)}{14\,kg}[/tex]

[tex]v_{f} = 9.8\,\frac{m}{s}[/tex]

The final speed of the block of ice is 9.8 meters per second.

Answer:

New acceleration = 1.5 m/s²

Explanation:

The acceleration of an object when it moves in a circular path is given by :

[tex]a=\dfrac{v^2}{r}[/tex]

Where

v is speed of an object

r is radius of path

If v remains constant,

[tex]a\propto \dfrac{1}{r}[/tex]

or

[tex]\dfrac{a_1}{a_2}=\dfrac{r_2}{r_1}[/tex]

Put r₁ = 5 m, a₁ = 3m/s², r₂ = 10 m

[tex]a_2=\dfrac{a_1r_1}{r_2}\\\\a_2=\dfrac{3\times 5}{10}\\\\a_2=1.5\ m/s^2[/tex]

Hence, if the radius of its path is increased to 10 m, its acceleration will be 1.5 m/s².

Answer:

a) 2.85 m/s

b) -24.01 m/s

c) 1

Explanation:

From the question, we can attest that the motion of the fish that was dropped by the seagul is that of a projectile motion. This motion is made up of two other motions which are, a horizontal uniform motion and a vertical motion, at constant acceleration. From the question, we are asked to find the horizontal motion. And then, the horizontal component of the fish's velocity does not change, therefore its the horizontal component of the fish's velocity is 2.85 m/s

To find the vertical component of the fish's velocity, we use the equation

v(y) = u(y) + gt

Where u(y) is the initial velocity which is zero, and g is the acceleration due to gravity which is -9.8 m/s. We are also told from the question that it took 2.45 s, and that's our time t. Applying this into the equation, we have

v(y) = 0 + -9.8 * 2.45

v(y) = -24.01 m/s

For the 3rd part, the horizontal component of the fish's velocity would decrease

Answer:

Should be -39.2 N

Explanation:

w=mg

w=4 x -9.8 m/s2

= -39.2 N

Answer:

A = 0.13 m

Explanation:

Given that,

Mass of a block, m = 1.4 kg

Spring constant of the spring, k = 16.5 N/m

While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 45.0 cm/s or 0.45 m/s

We need to find the amplitude of the subsequent oscillations.

We can use the conservation of energy here. Initially, the kinetic energy of the block is maximum and then it gets converted to the potential energy of the spring.

Mathematically,

[tex]\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2[/tex]

A is the amplitude of subsequent oscillations.

[tex]A=\sqrt{\dfrac{mv^2}{k}} \\\\A=\sqrt{\dfrac{1.4\times (0.45)^2}{16.5}} \\\\A=0.13\ m[/tex]

So, the amplitude of subsequent oscillations is 0.13 m.

For the work, applicate formula:

[tex]\boxed{\boxed{\green{\bf{W = F\times d}}}}[/tex]

According our data:

W = 12000 N * 1,5 m

W = 18000 J

The work done is 18000 Joules.

Answer:

c

Explanation:

Answer:

Beat frequency = 125.5 Hz

Explanation:

Given:

Length of first organ pipes  = 43 cm = 0.43 m

Length of second organ pipes = 63 cm = 0.63 m

Computation:

Wavelength L = λ/2

length λ = 2L

Frequency f1 = v/λ = 340 / 2(0.43)

Frequency f1 = 395.34 Hz

Frequency f2 = v/λ2 = 340/2(0.63)

Frequency f2 = 269.84 Hz

Beat frequency  = Frequency f1 - Frequency f2

Beat frequency = 395.34 - 269.84

Beat frequency = 125.5 Hz

Answer:

AB = DE <CD <BC

Explanation:

This is an exercise in kinetics, the accelerations defined as the change in velocity over the time interval, therefore the accelerations of a vector.

Because the acceleration is a vector, it has two parts, the modulus that the numerical value of the magnitude and the direction, a change in any of them implies the existence of a relationship.

Let's apply these reasoning to our problem.

AB Path  

this path is straight and as they indicate that the constant speed the acceleration is zero

DE path

This path is straight and since the velocity is constant the zero steps

BC path

This path is a curve and the velocity modulus is constant, but its directional changes therefore there is an acceleration called centripetal, given by the expression

         [tex]a_{c}[/tex] = v² / r

where r is the radius of the curve and the direction of acceleration is towards the center of the curve

CD path

This path is a curve and it also has centripetal acceleration, as can be seen in the drawing, the radius of the curve is greater than in section BC, therefore the acceleration is less

              [tex]a_{BC}[/tex] > [tex]a_{CD}[/tex]

In  summary lower accelerations are

 AB = DE <CD <BC

Answer:

Gradient of the hill is 53.33m/km which is lesser than the 500 m/km. So, he will be able to climb the hill conveniently.

Explanation: Given that

Maximum gradient = 500 m/km

Total distance = 1.5 km

Starting elevation = 20 m

Final elevation = 100 m

Gradient = change in elevation/ total distance.

Now, substitute the values into the formula.

Gradient = (100m - 20m)/1.5km

= 80m/1.5km

= 53.33m/km

Gradient of the hill is 53.33m/km which is lesser than the 500 m/km. So, he will be able to climb the hill conveniently.

Answer:

The value is [tex]\lambda = 2 \ m[/tex]

Explanation:

From the question we are told that

     The distance of the speaker  from the  second speaker  to the east is  [tex]d = 3 \ m[/tex]

      The distance of the speaker  from the listener  to the south is     [tex]a = 4 \ m[/tex]

Generally given that if the speaker move in any direction, their sound become  louder , it then mean that the position of the listener of minimum sound (i.e a position of minima ) ,

Generally the path difference of the sound produce by both speaker at a position of minima is mathematically represented as

              [tex]y = \frac{\lambda}{2}[/tex]

Generally considering the orientation  of the speakers and applying Pythagoras theorem we see that  distance from the second speaker to the listener  is mathematically represented as

             [tex]b = \sqrt{d^ 2 + a^2 }[/tex]

=>           [tex]b = \sqrt{3^ 2 + 4^2 }[/tex]

=>           [tex]b = 5[/tex]

Generally the path difference between the two speaker with respect to the  listener is  

              [tex]y = b - a[/tex]

=>           [tex]y = 5 - 4[/tex]

=>           [tex]y = 1[/tex]

So  

              [tex]1 = \frac{\lambda}{2}[/tex]

=>           [tex]\lambda = 2 \ m[/tex]

Answer:

5kgm/s

Explanation:

Given parameters:

Mass of bullet  = 0.005kg

Speed  = 1000m/s

Unknown:

Momentum  = ?

Solution:

Momentum is the amount of motion a body possesses.

Mathematically;

        Momentum  = mass x velocity

Now insert the parameters and solve;

       Momentum  = 0.005 x 1000 = 5kgm/s

Answer: Igneous rocks are created by heat. They start off as magma, which is hot, melted rock deep within a volcano. When magma cools and hardens, igneous rock forms.

Explanation:

Heat or increase in temperature plays a vital role in formation of  igneous, metamorphic rocks.

On Earth, igneous sedimentary or metamorphic rocks are created. When rocks are heated to their melting point and magma is produced, igneous rocks are created. Rocks that undergo metamorphosis are created when heat and pressure transform the original or parent rock into a whole new rock.

The heat causes a physical weathering process where the rock splits apart into fragments as it expands and contracts. When oxygen or moisture in the air change the chemical makeup of rock minerals, this also contributes to chemical weathering.

Heat and pressure cause an existing rock to change into a new rock, creating metamorphic rocks. When hot magma hits rock, contact metamorphism takes place. Large sections of existing rocks are altered by regional metamorphism as a result of the intense heat and pressure caused by tectonic forces.

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Answer:

5800

Explanation:

caluculatior

The ball was in the air for 3.625 second.

Velocity is the direction at which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time (for example, 60 km/h northbound).

In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea.

A physical vector quantity called velocity must have both a magnitude and a direction in order to be defined.

Given that: the a horizontal velocity of the ball: v = 40.0 m/s .

The ball  traveled 145 meters.

Hence, the time during which the ball is in the air:

= distance travelled/ horizontal velocity of the ball

= 145 meter /  40.0 m/s .

= 3.625 second.

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Answer:

Class

Explanation:

A class is just an abstract description of what an object will be like if any objects are ever actually instantiated.

Its purpose is to provide an appropriate superclass out of which other classes can confirm take from and even go ahead to share a mutual and particular design. In many other languages, the class name is often used as the name for the template itself, it can also be used as the name for the default constructor of the class too.

Answer:

10 is the correct answer

Explanation:

It is ten because the electrons that encircled the two orbit before the third orbit if the bohr model is 10. In bohr model, the electrons encircled the nucleus of an atom called orbit.

Answer: 27,000 J :)

Explanation:

If the winch uses a 900 W motor and the motor is used for 30 s to pull a sailboat then work needed to do this work is 27000 J. hence option D is correct

Power is the rate of doing work. Power is also defined as work divided by time. i.e. Power = Work ÷ Time. Its SI unit is Watt denoted by letter W. Watt(W) means J/s or J.s-1. Something makes work in less time, it means it has more power. Work is Force times Displacement. Dimension of Power is [M¹ L² T⁻³]

Given,

Power P = 900W

Time = 30s

Work in joule =?

By using formula,

P = Work ÷ Time

Work = Power × time

W= 900 × 30

W= 27000 J

Hence Work of 27000J is needed to pull a sailboat to shore in 30s.

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Answer:

a) v, v

b) 2mv^2

c) Elastic collion

Explanation:

(a) The velocity of the second particle after the collision is (v2x,v2y)=(v,−v).  From momentum conservation in x-direction

Here x, y represent direction.They are not variable. 1 and 2 represent before and after.

2vm=v1xm+v2xm, we find v1x=v.

From momentum conservation in y-direction

0 =v1ym+v2ym, we findv1y=v.

(b) By energy conservation principle

Before: K=1/2m(2v)^2=2mv^2.

After: K=1/2m(v^2(1x)+v^2(1y))+12m(v22x+v22y)=2mv^2

(c) The collision is elastic

Answer: