A conditional relative frequency table is generated by column from a set of data. The conditional relative frequencies of the two categorical variables are then compared.

If the relative frequencies being compared are 0.21 and 0.79, which conclusion is most likely supported by the data?

An association cannot be determined between the categorical variables because the relative frequencies are not similar in value.
There is likely an association between the categorical variables because the relative frequencies are not similar in value.
An association cannot be determined between the categorical variables because the sum of the relative frequencies is 1.0.
There is likely an association between the categorical variables because the sum of the relative frequencies is 1.0.
0.06
0.24
0.69
1.0

Answer:

Step-by-step explanation:

f(x) = (−5x2−7x)e^4x

Using the product rule:

f'(x) = (−5x2−7x)* 4e^4x + e^4x*(-10x - 7)

      =  e^4x(4(−5x2−7x) - 10x - 7)

      =  e^4x(-20x^2 - 28x - 10x - 7)

      = e^4x(-20x^2 - 38x - 7)

The measure of angle x, y and w in the parallelogram are 127 degrees, 53 degrees and 53 degrees respectively.

The figure in the image is that of a parallelogram.

First, we determine the value angle w:

Note that: sum of angles on straight line equal 180 degrees.

Hence:

w + 53 = 180

w + 53 - 53 = 180 - 53

w = 180 - 53

w = 127°

Also note that: opposite angles of parallelogram are equal and consecutive angles in a parallelogram are supplementary.

Hence:

Angle w = angle x

127° = x

x = 127°

Since consecutive angles in a parallelogram are supplementary.

x + y = 180

127 + y = 180

y = 180 - 127

y = 53°

Opposite angle of parallelogram are equal:

Angle y = angle z

53 = z

z = 53°

Therefore, the measure of angle z is 53 degrees.

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To find the value of y when log(7y-5) equals 2, we need to solve the logarithmic equation. By exponentiating both sides with base 10, we can eliminate the logarithm and solve for y. In this case, the value of y is 6.

To solve the equation log(7y-5) = 2, we can eliminate the logarithm by exponentiating both sides with base 10. By doing so, we obtain the equation 10^2 = 7y - 5, which simplifies to 100 = 7y - 5.

Next, we solve for y:

100 = 7y - 5

105 = 7y

y = 105/7

y = 15

Therefore, the value of y that satisfies the equation log(7y-5) = 2 is y = 15.

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59. The set V intersected with NJ.
60. The set V intersected with the union of F, U, and W.

To find the set in question 59, we take the intersection of V and NJ. This means we are looking for the elements that are present in both V and NJ.

To find the set in question 60, we take the intersection of V and the union of F, U, and W. This means we are looking for the elements that are present in both V and the set obtained by combining the elements from F, U, and W.

In both cases, we are using the concept of set intersection, which means finding the common elements between two sets. This can be done by comparing the elements of the sets and selecting only those that are present in both sets.

In summary, the direct answers to the sets are V intersect NJ and V intersect (F union U union W). To find these sets, we use the concept of set intersection to identify the common elements between the given sets.

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Answer:

------------------------

Radius is the distance between the center and the point on the circle.

Use distance formula to find the radius:

Substitute r for d and given coordinates to get:

The odds that a randomly picked student has both a cat and a dog are 1:1.

To find the odds that a student picked at random has both a cat and a dog, we need to determine the number of students who own both a cat and a dog and divide it by the total number of students.

Given that there are 25 students in total, 15 of them own cats, and 16 own dogs.

Let's  the number of students who own both a cat and a dog as "x."

According to the principle of inclusion-exclusion, we can calculate the value of "x" as follows:

x = (number of cat owners) + (number of dog owners) - (number of students who have neither)

x = 15 + 16 - 3

x = 28 - 3

x = 25

Therefore, there are 25 students who own both a cat and a dog.

We divide the number of students who own both by the total number of students :

Odds = (number of students who own both) / (total number of students)

Odds = 25 / 25

Odds = 1

Therefore, the odds that a student picked at random has both a cat and a dog are 1:1 or 1.

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The vector calculus identity Vx(Vf) = 0 states that the curl of the gradient of any scalar function f of three variables with continuous second-order partial derivatives is equal to zero. Therefore, VxVf=0.

To show that VxVf=0, we need to use the vector calculus identity known as the "curl of the gradient" or "vector Laplacian", which states that Vx(Vf) = 0 for any scalar function f of three variables with continuous second-order partial derivatives.

To prove this, we first write the gradient of f as:

Vf = (∂f/∂x) i + (∂f/∂y) j + (∂f/∂z) k

Taking the curl of this vector yields:

Vx(Vf) = (d/dx)(∂f/∂z) i + (d/dy)(∂f/∂z) j + [(∂/∂y)(∂f/∂x) - (∂/∂x)(∂f/∂y)] k

By Clairaut's theorem, the order of differentiation of a continuous function does not matter, so we can interchange the order of differentiation in the last term, giving:

Vx(Vf) = (d/dx)(∂f/∂z) i + (d/dy)(∂f/∂z) j + (d/dz)(∂f/∂y) i - (d/dz)(∂f/∂x) j

Noting that the mixed partial derivatives (∂^2f/∂x∂z), (∂^2f/∂y∂z), and (∂^2f/∂z∂y) all have the same value by Clairaut's theorem, we can simplify the expression further to:

Vx(Vf) = 0

Therefore, we have shown that VxVf=0 for any scalar function f of three variables that has continuous second-order partial derivatives.

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The solution to the given initial value problem is:

[tex]x(t) = 2e^{(5t)} - (1/5)y\\y(t) = (15/8)e^{(5t)} - (15/8)e^t[/tex]

To solve the given initial value problem, we'll use the method of solving systems of linear differential equations. Let's start by finding the solution for x(t) and y(t) step by step.

dx/dt = 5x + y

x(0) = 2

dy/dt = -3x + y

y(0) = 0

Solve the first equation dx/dt = 5x + y.

We can rewrite the equation as:

dx/(5x + y) = dt

Integrating both sides with respect to x:

∫ dx/(5x + y) = ∫ dt

Applying integration rules, we have:

(1/5) ln|5x + y| = t + C1

Simplifying, we get:

ln|5x + y| = 5t + C1

Taking the exponential of both sides:

[tex]|5x + y| = e^{(5t + C1)}[/tex]

Since we are dealing with positive real numbers, we can remove the absolute value signs:

[tex]5x + y = \pm e^{(5t + C1)}[/tex]

Solve the second equation dy/dt = -3x + y.

Similarly, we can rewrite the equation as:

dy/(y - 3x) = dt

Integrating both sides with respect to y:

∫ dy/(y - 3x) = ∫ dt

Applying integration rules, we have:

ln|y - 3x| = t + C2

Taking the exponential of both sides:

[tex]|y - 3x| = e^{(t + C2)}[/tex]

Removing the absolute value signs:

[tex]y - 3x = \pm e^{(t + C2)}[/tex]

Apply the initial conditions to determine the values of the constants C1 and C2.

For x(0) = 2:

5(2) + 0 = ±[tex]e^{(0 + C1)}[/tex]

[tex]10 = \pm e^{C1}[/tex]

For simplicity, we'll choose the positive sign:

[tex]10 = e^{C1}[/tex]

Taking the natural logarithm of both sides:

C1 = ln(10)

For y(0) = 0:

[tex]0 - 3(2) =\pm e^{(0 + C2)}[/tex]

-6 = ±e^C2

Again, choosing the positive sign:

[tex]-6 = e^{C2}[/tex]

Taking the natural logarithm of both sides:

C2 = ln(-6)

Substitute the values of C1 and C2 into the solutions we obtained in Step 1 and Step 2.

For x(t):

[tex]5x + y = e^{(5t + ln(10))}\\5x + y = 10e^{(5t)}[/tex]

For y(t):

[tex]y - 3x = e^{(t + ln(-6))}\\y - 3x = -6e^t[/tex]

Solve for x(t) and y(t) separately.

From [tex]5x + y = 10e^{(5t)}[/tex], we can isolate x:

[tex]5x = 10e^{(5t)} - y\\x = 2e^{(5t)} - (1/5)y[/tex]

From [tex]y - 3x = -6e^t[/tex], we can isolate y:

[tex]y = 3x - 6e^t[/tex]

Now, substitute the expression for x into the equation for y:

[tex]y = 3(2e^{(5t)} - (1/5)y) - 6e^t[/tex]

Simplifying:

[tex]y = 6e^{(5t)} - (3/5)y - 6e^t[/tex]

Add (3/5)y

to both sides:

[tex](8/5)y = 6e^{(5t)} - 6e^t[/tex]

Multiply both sides by (5/8):

[tex]y = (15/8)e^{(5t)} - (15/8)e^t[/tex]

Therefore, the solution to the given initial value problem is:

[tex]x(t) = 2e^{(5t)} - (1/5)y[/tex]

[tex]y(t) = (15/8)e^{(5t)} - (15/8)e^t[/tex]

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For the value of x = 4, matrix A will have no inverse.

If a matrix A has no inverse, then its determinant equals zero. The determinant of matrix A is defined as follows:

|A| = 1(2x3 - 3x2) - 2(1x3 - 3x1) + 3(1x2 - 2x1)

we can simplify and solve for x as follows:|A| = 6x - 12 - 6x + 6 + 3x - 6 = 3x - 12

Therefore, we must have 3x - 12 = 0 for matrix A to have no inverse.

Hence, x = 4. That is the value of x for which the matrix A does not have an inverse.

For the value of x = 4, matrix A will have no inverse.

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Once we have X and D, we can compute Aⁿ by the formula Aⁿ = XDⁿX⁻¹, where ⁿ represents the power.

To find the eigenvalues of matrix A:

(a) We need to solve the characteristic equation det(A - λI) = 0, where λ is the eigenvalue and I is the identity matrix.

The matrix A is given as:

A = [[0, 0], [-1, 2]]

The characteristic equation becomes:

det(A - λI) = [[0 - λ, 0], [-1, 2 - λ]] = (0 - λ)(2 - λ) - (0)(-1) = λ² - 2λ - 2 = 0

Solving this quadratic equation, we find two eigenvalues:

λ₁ = 1 + √3

λ₂ = 1 - √3

(b) To find a basis for each eigenspace, we need to solve the homogeneous system (A - λI)x = 0 for each eigenvalue.

For λ₁ = 1 + √3:

(A - (1 + √3)I)x = 0

Substituting the values:

[[-(1 + √3), 0], [-1, 2 - (1 + √3)]]x = 0

Simplifying:

[[-√3, 0], [-1, -√3]]x = 0

Solving this system, we find a basis for the corresponding eigenspace.

For λ₂ = 1 - √3:

(A - (1 - √3)I)x = 0

Substituting the values:

[[-(1 - √3), 0], [-1, 2 - (1 - √3)]]x = 0

Simplifying:

[[√3, 0], [-1, √3]]x = 0

Solving this system, we find a basis for the corresponding eigenspace.

(c) To factor A into XDX⁻¹, where D is a diagonal matrix, we need to find the eigenvectors corresponding to each eigenvalue.

Let's assume we have found the eigenvectors and formed a matrix X using the eigenvectors as columns. Then the diagonal matrix D will have the eigenvalues on the diagonal.

Without the specific eigenvectors and eigenvalues, we cannot provide the exact factorization or compute Aⁿ.

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Theorem 22.8 states several properties of rings with additive identity 0. These properties involve the multiplication and negation of elements in the ring.

Specifically, the theorem asserts that the product of any element with the additive identity is zero, the product of an element with its negative is the negation of the product with the positive element, and the product of two negatives is equal to the product of the corresponding positive elements.

Theorem 22.8 provides three key properties of rings with additive identity 0:

0aa0 = 0:

This property states that the product of any element a with the additive identity 0 is always 0.

In other words, multiplying any element by 0 results in the additive identity.

a(-b) = (-a)b = -(ab):

This property demonstrates the relationship between the negation and multiplication in a ring.

It states that the product of an element a with its negative -b is equal to the negation of the product of a with the positive element b.

This property highlights the distributive property of multiplication over addition in a ring.

(-a)(-b) = ab:

This property shows that the product of two negatives, -a and -b, is equal to the product of the corresponding positive elements a and b. It implies that multiplying two negatives yields a positive result.

These properties are fundamental in ring theory and provide important algebraic relationships within rings.

They help establish the structure and behavior of rings with respect to multiplication and negation.

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- Fixed cost: $4000, Marginal cost per item: $2.8, Price: $4

To identify the fixed cost, marginal cost per item, and the price at which the item is sold, we can analyze the given functions.

1. Fixed cost:
The fixed cost refers to the cost that remains constant regardless of the quantity produced or sold. In this case, the fixed cost is represented by the constant term in the total cost function. Looking at the equation C = 4000 + 2.8q, we can see that the fixed cost is $4000.

2. Marginal cost per item:
The marginal cost per item represents the additional cost incurred when producing or selling one more item. To find the marginal cost per item, we need to calculate the derivative of the total cost function with respect to the quantity (q).

Differentiating the total cost function C = 4000 + 2.8q with respect to q, we get:
dC/dq = 2.8

Therefore, the marginal cost per item is $2.8.

3. Price:
The price at which the item is sold is represented by the revenue per item. Looking at the revenue function R = 4q, we can see that the price at which the item is sold is $4.

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John's son is 11 years old.

We are given that John is four times as old as his son. Let's represent John's age as J and his son's age as S. According to the given information, we can write the equation J = 4S.

We also know that John is 44 years old, so we can substitute J with 44 in the equation: 44 = 4S.

To find the age of John's son, we need to solve this equation for S. We can do this by dividing both sides of the equation by 4:

44 ÷ 4 = (4S) ÷ 4

11 = S

Therefore, John's son is 11 years old.

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Answer:

Answer C

Step-by-step explanation:

The pattern in the diagram as you move from the top row to the bottom row is that each row increases by 1 circle. Therefore, the correct answer is (C) "Each row increases by 1 circle."

Option (A) is incorrect because it is not a consistent pattern.

Option (B) is incorrect because it increases by 2 on the second and third rows, breaking the established pattern.

Option (D) is incorrect because it refers to a specific row rather than the overall pattern.

The possible values for the divisor d are 1 and 37.

Let's denote the original number as x and the divisor as d.

According to the given information:

x divided by d leaves a remainder of 24. We can express this as x ≡ 24 (mod d).

2x divided by d leaves a remainder of 11. This can be expressed as 2x ≡ 11 (mod d).

We can rewrite these congruence equations as:

x ≡ 24 (mod d) -- Equation 1

2x ≡ 11 (mod d) -- Equation 2

To find the divisor, we need to find a value of d that satisfies both equations simultaneously.

Let's solve these congruence equations:

From Equation 1, we can write:

x = 24 + kd -- Equation 3, where k is an integer

Substituting Equation 3 into Equation 2:

2(24 + kd) ≡ 11 (mod d)

48 + 2kd ≡ 11 (mod d)

48 ≡ 11 (mod d)

48 - 11 ≡ 0 (mod d)

37 ≡ 0 (mod d)

This implies that d divides 37 without any remainder. The divisors of 37 are 1 and 37.

Therefore, the possible values for the divisor d are 1 and 37.

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The value of h is -2. The phase shift is 2 units to the left.

Given function:

g(t)=f(t+2)

The general form of the function is

g(t) = f(t-h)

where h is the horizontal translation or phase shift in the function. The function g(t) is translated by 2 units in the left direction compared to f(t). Therefore the answer is that the value of h in the translation is -2.

The phase shift can be described as the transformation of the graph of a function in which the function is moved along the x-axis by a certain amount of units. The phrase used to describe this transformation is “units to the left” or “units to the right” depending on the direction of the transformation. In this case, the phase shift is towards the left of the graph by 2 units. The phrase used to describe the phase shift is “2 units to the left.”

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Using Chebyshev's theorem, we can determine the percentage of the data within specific ranges based on the mean and standard deviation.

Chebyshev's theorem provides a lower bound for the proportion of data within a certain number of standard deviations from the mean, regardless of the shape of the distribution.

To calculate the percentage of data within a given range, we need to determine the number of standard deviations from the mean that correspond to the range. We can then apply Chebyshev's theorem to find the lower bound for the proportion of data within that range.

For example, if we want to find the percentage of data within one standard deviation from the mean, we can use Chebyshev's theorem to determine the lower bound. According to Chebyshev's theorem, at least 75% of the data falls within two standard deviations from the mean, and at least 89% falls within three standard deviations.

To calculate the percentage within a specific range, we subtract the lower bound for the larger range from the lower bound for the smaller range. For example, to find the percentage within one standard deviation, we subtract the lower bound for two standard deviations (75%) from the lower bound for three standard deviations (89%). In this case, the percentage within one standard deviation would be 14%.

By using Chebyshev's theorem, we can determine the lower bounds for the percentages of data within various ranges based on the mean and standard deviation. Keep in mind that these lower bounds represent the minimum proportion of data within the given range, and the actual percentage could be higher.

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The missing information for the ASA congruence theorem is given as follows:

B. <C = <Z

The Angle-Side-Angle (ASA) congruence theorem states that if any of the two angles on a triangle are the same, along with the side between them, then the two triangles are congruent.

The congruent side lengths are given as follows:

AC and XZ.

The congruent angles are given as follows:

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The equation of the line passing through the points (3,2) and (9,3) is y = (1/6)x + (5/2).

To find the equation of a line passing through two points, we can use the slope-intercept form, which is given by y = mx + b, where m represents the slope and b represents the y-intercept.

Step 1: Calculate the slope (m)

The slope of a line passing through two points (x1, y1) and (x2, y2) can be calculated using the formula: m = (y2 - y1) / (x2 - x1).

Using the given points (3,2) and (9,3), we have:

m = (3 - 2) / (9 - 3) = 1/6

Step 2: Find the y-intercept (b)

To find the y-intercept, we can substitute the coordinates of one of the points into the equation y = mx + b and solve for b. Let's use the point (3,2):

2 = (1/6)(3) + b

2 = 1/2 + b

b = 2 - 1/2

b = 5/2

Step 3: Write the equation of the line

Using the slope (m = 1/6) and the y-intercept (b = 5/2), we can write the equation of the line:

y = (1/6)x + (5/2)

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The finite difference approximation of u tt−u x =0 in the implicit method used to solve parabolic PDEs is \ u_i^{n-1} = u_i^n + \frac{\Delta t}{\Delta x}(u_{i+1}^n - u_i^n)

PDE: u_tt - u_x = 0

The parabolic PDEs can be solved numerically using the implicit method.

The implicit method makes use of the backward difference formula for time derivative and the central difference formula for spatial derivative.

Finite difference approximation of u_tt - u_x = 0

In the implicit method, the backward difference formula for time derivative and the central difference formula for spatial derivative is used as shown below:(u_i^n - u_i^{n-1})/\Delta t - (u_{i+1}^n - u_i^n)/\Delta x = 0

Multiplying through by -\Delta t gives:\ u_i^{n-1} - u_i^n = \frac{\Delta t}{\Delta x}(u_{i+1}^n - u_i^n)

Rearranging gives:\ u_i^{n-1} = u_i^n + \frac{\Delta t}{\Delta x}(u_{i+1}^n - u_i^n)This is the finite difference equation.

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Answer:

x | f(x)

6 | 8

-1 | 6

0 | 4

4 | 14

Step-by-step explanation:

For x = 6:

f(6) = |-2(6) + 4| = |-12 + 4| = | -8 | = 8

For x = -1:

f(-1) = |-2(-1) + 4| = |2 + 4| = |6| = 6

For f(x) = 4:

|-2x + 4| = 4

-2x + 4 = 4 (Case 1)

-2x + 4 = -4 (Case 2)

Case 1:

-2x + 4 = 4

-2x = 0

x = 0

Case 2:

-2x + 4 = -4

-2x = -8

x = 4

For f(x) = 14:

|-2x + 4| = 14

-2x + 4 = 14 (Case 1)

-2x + 4 = -14 (Case 2)

Case 1:

-2x + 4 = 14

-2x = 10

x = -5

Case 2:

-2x + 4 = -14

-2x = -18

x = 9

Completing the table:

x | f(x)

6 | 8

-1 | 6

0 | 4

4 | 14

The formula qt = 38 - 12pt represents the quantity on the market in year t based on the price in that year.

The cobweb model is used to determine the sequence of prices in a market with given supply and demand sets. The sequence exhibits oscillations and approaches a steady state value.

In the cobweb model, suppliers base their pricing decisions on the previous price. The recurrence equation pt = (38 - 12pt-1)/13 is derived from the demand and supply equations. It represents the relationship between the current price pt and the previous price pt-1. Given the initial price p0 = 4, the explicit solution for the sequence of prices can be derived. The solution indicates that as time progresses, the prices approach a steady state value of 38/13. However, due to the cobweb effect, there will be oscillations around this steady state.

To calculate the quantity on the market in year t, qt, we can substitute the price pt into the demand equation q = 38 - 12p. This gives us the formula qt = 38 - 12pt, which represents the quantity on the market in year t based on the price in that year.

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To solve the equation sinθ(cosθ + 1) = 0 for θ with 0 ≤ θ < 2π, we can apply the zero-product property and set each factor equal to zero.

1. Set sinθ = 0:

This occurs when θ = 0 or θ = π. However, since 0 ≤ θ < 2π, the solution θ = π is not within the given range.

2. Set cosθ + 1 = 0:

Subtracting 1 from both sides, we have:

 cosθ = -1

This occurs when θ = π.

Therefore, the solutions to the equation sinθ(cosθ + 1) = 0 with 0 ≤ θ < 2π are θ = 0 and θ = π.

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The sum of the entire series is the sum of the first group plus the sum of the second group:1 + 1/2 = 3/2 Since the sum of the series is finite, it converges. Therefore, the given series is convergent and the sum is 3/2.

The given series can be written in the following form: 1/2 + 1/2² + 1/2³ + 1/2⁴ +... + 1/3 + 1/3² + 1/3³ + 1/3⁴ +...The first group (1/2 + 1/2² + 1/2³ + 1/2⁴ +...) is a geometric series with a common ratio of 1/2.

The sum of the series is given by the formula S1 = a1 / (1 - r), where a1 is the first term and r is the common ratio.S1 = 1/2 / (1 - 1/2) = 1Therefore, the sum of the first group of terms is 1.

The second group (1/3 + 1/3² + 1/3³ + 1/3⁴ +...) is also a geometric series with a common ratio of 1/3.

The sum of the series is given by the formula S2 = a2 / (1 - r), where a2 is the first term and r is the common ratio.S2 = 1/3 / (1 - 1/3) = 1/2Therefore, the sum of the second group of terms is 1/2.

The sum of the entire series is the sum of the first group plus the sum of the second group:1 + 1/2 = 3/2 Since the sum of the series is finite, it converges. Therefore, the given series is convergent and the sum is 3/2.

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Answer:

d

Step-by-step explanation:

Answer:

245%

Step-by-step explanation:

12/5 = 2.4

245% = 245/100 = 2.45

2.45>2.4

⇒245% > 12/5

The total cost, not including taxes, to lay the flooring is $8.35 per square foot.

To calculate the total cost of laying the flooring, we need to consider the cost of the oak floor per square foot and the labor charges per square foot.

The cost of the oak floor is given as $4.95 per square foot. This means that for every square foot of oak flooring used, it will cost $4.95.

In addition to the cost of the oak floor, there is also a labor charge for the installation. The installer charges $3.40 per square foot for labor. This means that for every square foot of flooring that needs to be installed, there will be an additional cost of $3.40.

To find the total cost, we add the cost of the oak floor per square foot and the labor charge per square foot:

Total Cost = Cost of Oak Floor + Labor Charge

          = $4.95 per square foot + $3.40 per square foot

          = $8.35 per square foot

Therefore, the total cost, not including any taxes, to lay the flooring is $8.35 per square foot.

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Answer:

The answer wound be C. {-6, -5, -4, 4, 5, 6}.

Step-by-step explanation:

For g(x) = 1:

|x| - 3 = 1

|x| = 4

The equation |x| = 4 has two solutions: x = 4 and x = -4.

For g(x) = 2:

|x| - 3 = 2

|x| = 5

The equation |x| = 5 has two solutions: x = 5 and x = -5.

For g(x) = 3:

|x| - 3 = 3

|x| = 6

The equation |x| = 6 has two solutions: x = 6 and x = -6.

Now, we have six possible values for x: 4, -4, 5, -5, 6, and -6. Therefore, the domain of g(x) = |x| - 3, given that the range is {1, 2, 3}, is {-6, -5, -4, 4, 5, 6}.

Answer:

Step-by-step explanation:

a) Consider the quadratic equation x^2-7x-18=0.

Then we have (x-9)(x+2)=0 by factoring.

Observe that x-9=0 and x+2=0.

This implies that x=0+9=9 and x=0-2=-2.

Thus x=9, -2.

Therefore, x^2-7x-18=0.

b) Note that the area of the rectangle is determined by the equation: A=L*W where L=length and W=width.

Then we have A=x(x-7)=x^2-7x.

Observe that the area of the rectangle is 18 cm^2.

This implies that 18=x^2-7x.

Thus x^2-7x-18=0.

From our answer in part (a), we can see that the values of x are 9 and -2.

But then our length and width cannot be a negative number, so we exclude the value of x, which is -2.

Therefore, the value of x is 9.

Answer:

Step-by-step explanation:

x=8.6cm  x=7.9cm

15m

Answer:

The answer is x = 24.7

Step-by-step explanation:

Using the formula,

a/(sinA) = b/(sinB) = c/(sinC),

Here, we need to find x,

and for b = 15, the corresponding angle is 35 degrees,

and for x, the angle is 71 degrees, so,

[tex]x/sin(71) =15/sin(35)\\x = 15(sin(71)/sin(35)\\x = 24.7269[/tex]

To one decimal place we get,

x = 24.7