A poker is a long thin tool used to move pieces of coal or logs burning in a fire. To be as safe as possible, the poker should be made from a material that
Answer:
See the answer below
Explanation:
A poker that will effectively and safely function to move pieces of coal or logs in a burning fire must be fireproof itself. Hence, to be as safe as possible, such poker should be made from a material that is fireproof and that does not conduct a lot of heat. Otherwise, the poker will catch fire/becomes too hot during the course of usage.
Which object has a net force of -68 N?
F = 31 N
F = 89 N
F, = 27 N
F=-53N
F = 53 N F-56N
F = 103 N
F = 34 N
F=-102 N
F = -27 N
F = -74 N
F=-89 N
Answer:third one from the left
Explanation:
The third object from the given problem has a net force of - 68 Newtons because there is no net vertical force action of this object as equal upward and downward forces cancel each other.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
F = m*a
The net vertical force = 27 Newtons - 27 Newtons
= 0 Newtons
The net vertical force on the object would be zero.
The net horizontal force acting on the object = - 102 Newtons + 34 Newtons
= -68 Newtons
Hence we can conclude that the net force of - 68 Newton acting on the third object.
Learn more about Newton's second law here, refer to the link;
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please someone knows the answer? it is physics
Answer:C
Explanation: I took the quiz if you don't believe me then your gonna miss the problem.
who are the charges developed due to friction
Answer:
The charges developed due to friction is discussed below in detailed explanation.
Explanation:
The triboelectric charging method (also identified as, charging by friction) appears in a variation of electrons among the two articles that are rubbed collectively. ... As an outcome, the atoms of rubber extract electrons from the atoms of the creature coat, leaving both articles with an asymmetry of charge.
Which is true about Earth's energy budget?
A. Most of the energy from the sun is reflected back into space
B. Most of the energy from the sun is absorbed by the atmosphere and surface.
C. Very little of the energy is absorbed by the surface
D. The amount of energy coming back into the atmosphere is less than what leaves Earth's surface
Answer:
I think is B but I'm not sure
The statement which is true about Earth's energy budget is that most of the energy from the sun is absorbed by the atmosphere and surface. Thus, the correct option for this question is B.
What is Earth's energy budget?Earth's energy budget may be characterized as the mutual balance between the radiant energy that significantly reaches Earth from the sun with respect to the energy that flows from Earth back out to space.
In order to maintain a constant global average temperature, all of the sun's radiation that successfully enters Earth's atmosphere must eventually be sent back to space. There are three sources of Earth's energy budget may include incoming solar energy (shortwave radiation), Outgoing longwave radiation, and Earth's internal heat sources and other small effects.
Therefore, the correct option for this question is B.
To learn more about Earth's energy, refer to the link:
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Jack cannot run as fast as Paul. He decides to go at his own pace and not run with Paul. Which principle of fitness is he following?
Progression
Overload
Individuality
Reversibility
Answer:
individuality
Explanation:
since he cannot run with paul he decided to run by himself making his exercise individual
Answer: individuality
Explanation:
(you can ignore this its just the deffintion of individuality)
This is a crucial principle, the fundamental fact that everyone is different! Everyone responds to training in a different way. If you are walking or cycling with a friend, and doing exactly the same amount of training, don’t be concerned if one of you gets fitter faster than the other – this is what individualisation is all about.
It might be that one of you is having some pressure at work or difficulties at home, but wherever it is, it’s surprising what can affect your training. Some days your training can go really well and the next day, even though it was exactly the same length workout, it can be a nightmare. This is individualisation.
A horse pulls a wagon forward. What is the equal and opposite force for the force of the horse pushing down on the ground as described by Newton's third law
Answer:
The equal and opposite force is equal to the sum of any frictional force to the product of the mass of the wagon and the acceleration of the wagon
Explanation:
Newton's third law states that for every action, or force, there is an equal and opposite reaction
The equal and opposite force = The mass of the Wagon, m × The acceleration of the wagon, a + Any frictional force present, [tex]F_f[/tex]
Whereby the force with which the horse pulls the wagon = F, mathematically, we have;
The equal and opposite force = -F = m × a + [tex]F_f[/tex].
Answer:
Ground pushes up on the horse’s hooves
Explanation:
khan academy
22. What force causes a skater sliding on the ice to gradually slow down?
A. balanced forces
B. friction
C. acceleration
D. inertia
the relationship between m2,cm2,mm2 and km2
Answer:
m2
Explanation:
I just knowyyysydyyyyyyyýdydysyydysysydydhdhhdhdhdhxhchxhhxhc
Answer:
Square Meters to Square Centimeters Conversion
1 Square meter (m2) is equal to 10000 square centimeters (cm2). ... For example, to convert 10 m2 to cm2, multiply 10 by 10000, that makes 100000 cm2 is 10 m2.
cm2↔mm2 1 cm2 = 100 mm2.
please help me, marked as brainest
Answer:
D. Can be done anywhere outside
Explanation:
Because it's true sports can be done pretty much anywhere outside
a bus starts to move from rest. if if its velocity becomes 90 km per hour after 8s calculate its acceleration
Answer:
11.25km/h²
Explanation:
Acceleration = Velocity / Time
Acceleration = 90 / 8
Acceleration = 11.25
A horse trotting at 3 meters per second speeds up with an acceleration of 2
meters per second2 for a distance of 15 meters. Calculate the horse’s final
speed.
Answer:
The horse's final speed is 8.31 m/s
Explanation:
Motion With Constant Acceleration
It's a type of motion in which the velocity of an object changes uniformly in time.
The equation that describes the change of velocities is:
[tex]v_f=v_o+at\qquad\qquad [1][/tex]
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
The distance traveled by the object is calculated as follows:
[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2][/tex]
Solving [1] for t and substituting into [2] we get the following equation:
[tex]V_f^2=V_o^2+2aX[/tex]
Now we use the data provided by the question. The horse starts at vo=3 m/s and then accelerates at [tex]a=2 m/s^2[/tex] for a distance of x=15 m. The final speed is:
[tex]V_f^2=3^2+2(2)(15)[/tex]
[tex]V_f^2=9+60=69[/tex]
[tex]V_f=\sqrt{69}[/tex]
[tex]V_f=8.31\ m/s[/tex]
The horse's final speed is 8.31 m/s
When balanced, which equation would have the coefficient 3 in front of any of the reactants? Zn + HCl ZnCl2 + H2 H2SO4 + B(OH)3 B2(SO4)3 + H2O Fe + AgNO3 Fe(NO3)2 + Ag C2H4O2 + O2 CO2 +H2O
Answer: H2SO4 + B(OH)3 B2(SO4)3 + H2O
I took on edge for Physical Science 100%
Answer H2SO4 + B(OH)3 B2(SO4)3 + H2O
Explanation:
just trust me here if it isnt right just tell me
Answer:
H2SO4 + B(OH)3 B2(SO4)3 + H2O
Explanation:
This will help a lot you guys trust me
HELP PLS its been a day and this lesson is due today and ita already night here and i have to solve this questions or else my parent will be mad pls help me pls im despo ):
Answer:
mind the angle that the ball is at and subtract the answer from where the goal post is. You probably know that but my brain cant function what the answer is.
The moon Phobos orbits Mars
(mass = 6.42 x 1023 kg) at a distance
of 9.38 x 106 m. What is its period of
orbit?
Skip
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-nte
Answer:
The moon Phobos orbits Mars
(mass = 6.42 x 1023 kg) at a distance
of 9.38 x 106 m. What is its period of
orbit?
Explanation:
Answer: 27.9816 x 10^3 is the period of orbit
Calculate the volume of 500 kg of lead if the density of lead is 1140 kg/m^3
Answer:
0.4386 [tex]m^3[/tex]
Explanation:
The density of an object is calculated as the ratio of its mass and that of its volume. This can be expressed mathematically as;
Density = mass/volume
In this case:
density of lead = 1140 kg/m3
mass of the lead = 500 kg
From the equation above;
volume of the lead = mass/density
= 500/1140
= 0.4386 [tex]m^3[/tex]
Hence, the volume of 500 kg of lead with a density of 1140 kg/m^3 is 0.4386 [tex]m^3[/tex].
A 15-kilogram wagon originally at rest on a level road is pulled by a rope that exerts a constant horizontal force of 45 newton's, If the frictional forces on the wagon total 15 newton's, what will be its acceleration ? *
2.0 〖m/s〗^2
4.0 〖m/s〗^2
15 〖m/s〗^2
30 〖m/s〗^2
3.0 〖m/s〗^2
Answer:
A. 2 m/[tex]s^{2}[/tex]
Explanation:
Mass of wagon = 15 kg
Horizontal force = 45 N
frictional force = 15 N
It is good to note that part of the exerted horizontal force would be used to overcome the frictional force on the wagon.
So that, total force exerted on the wagon can be determined by;
total force = horizontal force - frictional force
= 45 - 15
= 30 N
From Newton's second law of motion, we have;
F = ma
Where: F is the force applied on an object, m is its mass, and a is the acceleration of the object.
Thus,
30 = 15 x a
a = [tex]\frac{30}{15}[/tex]
= 2 m/[tex]s^{2}[/tex]
The acceleration of the wagon is 2 m/[tex]s^{2}[/tex].
Write your answer to the question below.
-How do you think energy is transformed in the Drop Tower( ride in a amusement park)?
Answer:
Hi... Potential energy is converted to kinetic energy and kinetic energy is converted to potential energy
Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 1,510 liters has an internal pressure of 1.20atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 253atm pushing on it, how big will that bubble be? You must show your work to receive full credit.
The volume should be 7.16 L
Boyles law:
Since there is a submarine with a volume of 1,510 liters has an internal pressure of 1.20atm. Also, there should be a pressure of 253atm pushing on it.
Here we used the Apply boyles law
So,
1510*1.20 = volume *253
So, the volume should be 7.16 L
hence, the volume is 7.16 L
learn more about volume here: https://brainly.com/question/16762398
calculate the potential energy of a 60 kg object that is 20 meters off the ground
Answer:
11772 joules
Explanation:
M = 60 kg
H = 20 m
G = 9.81 ms^-2
P.E = ?
P.E = MGH
P.E = 60 x 9.81 x 20
P.E = 11772 joules
Choose ALL that apply
Voltage
a)pushes free protons around a circuit
b)is measured in volts
c)causes current
d)pushes free electrons around a circuit
in " m a x f o r t e d u c a t i o n " . what is probability of vowels.
Answer:
7/16 is the probability of given querty
Chef Andy tosses an orange in the air, then catches it again at the same height. The orange is in the air for 0.75\,\text s0.75s0, point, 75, start text, s, end text. We can ignore air resistance.
What was the orange's velocity at the moment it was tossed into the air?
Answer:
3.68 m/s
Explanation:
Applying the equation of motion;
v = u + at. ....1
Where
u = initial speed
v = final speed
a = acceleration
t = time taken
Given;
Total time of flight t = 0.75s
Acceleration due to gravity g = 9.8 m/s^2
Considering the first phase of flight, during the upward motion to the maximum height. The final velocity at the maximum height is zero and the time of flight of the phase is equal to half of the total flight time.
v1 = 0
t1 = t/2 = 0.75/2 =0.375s
From equation 1;
v1 = u - gt1
Substituting the values;
0 = u - 9.8(0.375)
Solving for u;
u = 9.8(0.375)
u = 3.675
u = 3.68 m/s
Initial velocity = 3.68 m/s
Chef Andy tosses an orange in the air, then catches it again at the same height. The orange is in the air for 0.75 s. We can ignore air resistance.
What was the orange's velocity at the moment it was tossed into the air?
Answer: 3.68 m/s
Your older brother has been dealing in gold business brings to you a cube of a
stone of uniform sides and claims its gold. Having studied density, explain stating
all the instruments involved how you can affirm that the stone is gold.
Answer:
Explanation:
The density of gold is 19.3 g/cm³. Thus, you can determine the density of the unknown cube by doing the following. Get a measuring cylinder (marked in cm³) that contains a certain volume of water (preferably above average but not close to been filled up). Get a weighing balance (that can read in grams) also.
Measure the mass of the unknown stone (using the weighing balance) and record. Take the initial volume of the water in the measuring cylinder and record (in cm³) and then drop the unknown stone inside the measuring cylinder gently (avoid splashes). Record the final volume of the cylinder after the unknown stone was dropped.
Then calculate the density of the stone by using the formula; mass ÷ change in volume
The change in volume can be determined by; Final volume - initial volume
If the answer obtained from the calculation (of the density of the stone) is not around 19.3 g/cm³ (say 19.3 ± 0.2), then the stone is not gold but if it is around 19.3 g/cm³, then the stone is gold.
different between group IA and IIA elements
Answer:
Group IA elements have only one valency electron while Group IIA have two valency electrons.
Group IA elements have cations with higher charge density hence polarizing anions easier resulting into covalent character while Group IIA elements have cations with lower charge density hence difficulty in distorting anions resulting into a ionic character. This is due to difference in cationic radii and charges
Which of these is a good way to begin your personal helath plan for physical fitness A. An assessment B. An action plan C. A plan for measuring progress toward your goal D. An ambitious goal.
Answer: A. An Assessment
I hope this helps, and Happy Holidays! :)
ANSWER
A. An assessment
Where does diffusion occur in the excretory system
Answer:
Diffusion of water, salts, and waste products occurs in the kidneys. Diffusion of calcium from food into cells occurs in the intestines. Molecules are not the only things that can diffuse. Heat from the body diffuses away in the form of sweat that evaporates.
Explanation:
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Un mobil parcurge distanta dintre 2 localitati in 2 etape: in prima etapa parcurge d1+40km cu viteza v1=50km/h, apoi parcurge d2=60km cu v2=60km/h. Care este v medie?
Răspuns: 55 km / oră
Explicaţie:
Dat fiind :
Prima etapă de călătorie:
Distanța parcursă = d1 = 40km
Viteza (v1) = 50 km / oră
A doua etapă de călătorie:
Distanța parcursă = d2 = 60km
Viteza (v2) = 60km / hr
Viteza medie = (viteza primei etape + viteza celei de-a doua etape) / 2
Viteza medie = (50 + 60) km / h ÷ 2
Viteza medie = 110km / h ÷ 2
Viteza medie = 55 km / oră
Un automovil transita por una curva en forma de U y recorre una distancia de 400m en 30s sin embargo su posición final está a solo 40 m de la inicial ¿Cuál es la rapidez media y cuál es la magnitud de la velocidad media?
Answer:
Definimos:
Rapidez media es igual al cociente entre la distancia recorrida y el tiempo que se tarda en recorrer esa distancia.
En este caso la distancia recorrida es 400m, y el tiempo que se tarda es 30s, entonces la rapidez media va a ser:
RM = 400m/30s = 13.33 m/s
La velocidad media por otro lado, es igual al cociente entre el desplazamiento y el tiempo necesario para desplazarse.
El desplazamiento es igual a la distancia entre la posición final y la posición inicial, que en este caso eso 40m, y el tiempo necesario sigue siendo 30s, entonces la velocidad media va a ser:
VM = 40m/30s = 1.33 m/s
PHYSICS HELP PLEASE,, I’LL MAKE YOU THE BRAINLIEST!
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Q: Place the block at the top of a 30 degree ramp. What is the net force on the block when it begins to slide down the ramp? What is the acceleration of the block down the ramp? SHOW WORK/CALCULATIONS
First, let
f = mag. of static friction
n = mag. of normal force
w = m g = mag. of gravitational force (the weight of the block)
m = mass of the block
g = 9.80 m/s² (the mag. of the acceleration due to gravity)
a = acceleration of the block
It's the static friction that interests us at the moment "when it begins to slide", meaning the precise moment at which static friction is at its maximum. At that point, the friction has magnitude f such that
f = 0.5 n
The problem is much easier to work through if you split up the forces into components acting parallel and perpendicular to the ramp. By Newton's second law, we have
• the net force acting parallel to the ramp is
∑ F = - f + w sin(30°) = m a
• and the net force acting perpendicular to the ramp is
∑ F = n - w cos(30°) = 0
Hence the net force on the block as it begins to slide acts only in the parallel direction. Note that we take the positive parallel direction to be the one in which the block slides down the ramp (i.e. opposing the friction force), and the positive perpendicular direction to be the same as the normal force.
Solve the second equation for n :
n = m g cos(30°) = (100 kg) (9.80 m/s²) cos(30°) ≈ 849 N
Then
f = 0.5 (849 N) ≈ 424 N
and so the net force on the block is
∑ F ≈ - 424 N + (100 kg) (9.80 m/s²) sin(30°) ≈ 65.6 N
Next, you want to find the acceleration of the block as it is sliding down the ramp, during which time kinetic friction kicks in. We have the same equations as above, except now f = 0.3 n. So we still have n ≈ 849 N, which gives
f = 0.3 (849 N) ≈ 255 N
∑ F = - f + w sin(30°) = m a
→ - 255 N + (100 kg) (9.80 m/s²) sin(30°) ≈ (100 kg) a
→ a ≈ 2.35 m/s²